Hurry please I am being timed

Final answer:

The sum of the first 4 terms of the arithmetic sequence where the 6th term is 8 and the 10th term is 13 is 14.5.

Explanation:

In an arithmetic sequence, the difference between consecutive terms is constant. This difference is commonly called the common difference. Given that the 6th term is 8 and the 10th term is 13, we can calculate this common difference.

The common difference is (13 - 8) / (10 - 6) = 5 / 4 = 1.25.

The common difference is backward from the 6th term to the first term or we can say the 6th term minus 5 times the common difference will give us the first term. Therefore, the first term is 8 - 5*1.25 = 8 - 6.25 = 1.75.

The sum of the first 4 terms of an arithmetic sequence is given by the formula S = n/2 *[2a + (n-1)*d], where 'n' is the number of terms (in this case 4), 'a' is the first term, and 'd' is the common difference.

Therefore, substituting our known values into the formula gives us: S = 4/2 *[2*1.75 + (4-1)*1.25] = 2*[3.5 + 3.75] = 2*7.25 = 14.5

Learn more about Arithmetic Sequence here:

brainly.com/question/32830972

okay so you would do it like this

2x + (3 - x)

2x + 3 - x

x + 3

the answer would be x + 3

hope this helps!

Following PEMDAS, the parentheses comes first. Essentially, (3 - x) is times 1, which removes the parentheses. So 2x + 3 - x. Subtract the x first. This leaves x + 3.

Option D

ANSWER:  

The number 49,836 is divisible by 2, 3, and 6.

SOLUTION:

Let us check one by one statement.

Consider Option (A)

The number 49,836 is divisible by 5, but not by 9.

Given, 49,836 is divisible by 5.

Divisibility rule for 5 is, last digit of the number should be either 0 or 5.

But here last digit is 6, so given number is not divisible by 5

Hence, this statement is not true.

Consider Option (B)

The number 49,836 is divisible by 5 and 9.

Here again given that, 49,836 is divisible by 5, but we know that it is not divisible by 5.

Hence, this statement is also wrong.

Consider Option (C)

The number 49,836 is divisible by 3, 6, and 9.

Given, 49,836 is divisible by 3.

Divisibility rule for 3 is, sum of the digits must be a multiple of 3.

Now sum of digits = 4+9+8+3+6 = 30.

Since, 30 is an multiple of 3, given number is divisible by 3.

And, 49,836 is divisible by 6.

Divisibility rule for 6 is, the number should be divisible by both 2 and 3.

First let us check divisibility with 2,

Divisibility rule for 2 is, the last digit of the number must any one of 0,2,4,6,8

Here, last digit is 6, so it is divisible by 2

And it is also divisible by 3 as we proved above.

So, the given number is divisible by 6.

And 49,836 is divisible by 9.

Divisibility rule for 9 is, sum of the digits must be a multiple of 9.

Sum of digits = 30 which is not a multiple of 9

So, given number is not divisible by 9

Hence, this statement is wrong.

Consider Option (D)

The number 49,836 is divisible by 2, 3, and 6.

Given, 49,836 is divisible by 2, 3, and 6.

As we have already seen in above case that, 49,836 is divisible by 2, 3 and 6  .Hence statement D is correct.