Peregrine falcons frequently grab prey birds from the air, as BI0 in Example 9.10. Sometimes they strike at high enough speeds that the force of the impact disables prey birds. A 480 g per- egrine falcon high in the sky spies a 240 g pigeon some dis- tance below. The falcon slows to a near stop, then goes into ve-called a stoop-and picks up speed as she falls. The n reaches a vertical speed of 45 m/s before striking the pigeon, which we can assume is stationary. The falcon strikes the pigeon and grabs it in her talons. The collision between the falco birds lasts 0.015 s. a. What is the final speed of the falcon and pigeon? b. What is the average force on the pigeon during the impact?

Answers

Answer 1
Answer:

A) 30 m/s

The problem can be solved by using the law of conservation of momentum. In fact, the total momentum falcon+pigeon before the collision must be equal to the total momentum falcon+pigeon after the collision:

p_i = p_f

m_f u_f + m_p u_p = (m_f + m_p) v

where

mf = 0.480 g is the mass of the falcon

uf = 45 m/s is the initial velocity of the falcon

mp = 0.240 g is the mass of the pigeon

up = 0 is the initial velocity of the pigeon

v is the final combined velocity of pigeon+falcon

Solving the equation for v, we find

p=(m_f u_f)/(m_f +m_p)=((0.480 kg)(45 m/s))/(0.480 kg+0.240 kg)=30 m/s

B) 480 N

The average force on the pigeon during the impact is given by

F=(\Delta p)/(\Delta t)

where

\Delta p is the change in momentum of the pigeon

\Delta t is the duration of the collision

here we have:

- Change in momentum of the pigeon:

\Delta p = m (v-u)=(0.240 kg)(30 m/s-0)=7.2 kg m/s

- Duration of the collision:

\Delta t=0.015 s

So the average force is

F=(7.2 kg m/s)/(0.015 s)=480 N

Answer 2
Answer:

Final answer:

To determine the final speed of the falcon and pigeon, we need to use the principles of conservation of momentum. To calculate the average force on the pigeon during the impact, we can use the equation for impulse. The primary topic of this question is conservation of momentum and impulse.

Explanation:

To determine the final speed of the falcon and pigeon, we need to use the principles of conservation of momentum. Since the pigeon is assumed to be stationary, its initial momentum is zero. The final momentum of the falcon and pigeon combined must also be zero, according to the law of conservation of momentum. Using the equations for momentum and rearranging, we can solve for the final speed of both the falcon and pigeon.

To calculate the average force on the pigeon during the impact, we can use the equation for impulse, which is the change in momentum. Impulse is equal to force multiplied by the time of impact. Rearranging the equation, we can solve for force.

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Answers

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In the Niagara Falls hydroelectric generating plant, the energy of falling water is converted into electricity. The height of the falls is about 48 meters. Assuming that the energy conversion is highly efficient, approximately how much energy is obtained from one kilogram of falling water? Therefore, approximately how many kilograms of water must go through the generators every second to produce a megawatt of power (106 watts)?

Answers

Answer:

2.124 kg of water

Explanation:

height of the falls is about 48 meters.

Mass of water needed is 1kg = 1000g

Power needed is 106 watts.

The amount of energy in 106 watts in one sec is 106 joules.

To calculate the energy of the 1kg falling water = Mgh

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Energy = 470880 joules.

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Answers

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A
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b. False

Answers

Answer:

false

Explanation:

i chose false when i was taking my practice exam

A runner achieves a velocity of 11.1 m/s 9 seconds after he begins. What is his acceleration? What distance did he cover?

Answers

Acceleration=\frac { Final\quad Velocity\quad -\quad Initial\quad Velocity }{ Time } \n

Therefore:

Acceleration=\frac { 11.1\quad m/s\quad -\quad 0\quad m/s }{ 9\quad seconds } \n \n =\frac { 11.1\quad m/s }{ 9\quad seconds } \n \n =1.23\quad m/{ s }^( 2 )\quad (2\quad decimal\quad places)

As the runner was travelling for 9 seconds, he covered a distance of 99.9 metres. 9 seconds x 9 seconds  = 81 seconds squared, and the runner covers roughly 1.23 metres in distance every second squared.

Explanation:

Acceleration=

Time

FinalVelocity−InitialVelocity

Therefore:

\begin{gathered}Acceleration=\frac { 11.1\quad m/s\quad -\quad 0\quad m/s }{ 9\quad seconds } \\ \\ =\frac { 11.1\quad m/s }{ 9\quad seconds } \\ \\ =1.23\quad m/{ s }^{ 2 }\quad (2\quad decimal\quad places)\end{gathered}

Acceleration=

9seconds

11.1m/s−0m/s

=

9seconds

11.1m/s

=1.23m/s

2

(2decimalplaces)

As the runner was travelling for 9 seconds, he covered a distance of 99.9 metres. 9 seconds x 9 seconds = 81 seconds squared, and the runner covers roughly 1.23 metres in distance every second squared.