MATHEMATICS MIDDLE SCHOOL

Students in miss moseley's fourth grade class

Answers

Answer 1
Answer:

Answer:

what?

Step-by-step explanation:
Answer 2
Answer: What?!?!?!!?!?!?!?!?!

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Solve the following system of equations graphically on the set of axes below. y=2x−5. 3x+4y=24

Answers

Answer:

all work is shown and pictured

Ryan has nine 14-ounce bags of popcorn to repackage and sell at the school fair. A small bag holds 3 ounces. How many small bags can he make?

Answers

42 small bags

14*9 = 126
126/3 = 42 

Carla made a scale drawing of a classroom. The length of the classroom in the drawing is 5in. The actual length is 40ft. What scale did Carla use for her drawing?

Answers

Answer:

1/96

Step-by-step explanation:

scale is

a model cannot be as same size as that of actual object ,

hence objects are scales down to some value so that its model can be comfortably made.

scale is generally ratio of length  of drawing and actual length of object

scale = length  of drawing / actual length of object.

Given

length of classroom drawing = 5in

actual length of classroom = 40 ft

as unit of drawing and actual classroom is different lets make unit of class smilar to that of drawing that is in inches

we know

1 feet = 12 inches

thus 40 feet = 12*40 inches = 480 inches

thus,

actual length of classroom in inches = 480 inches

scale used by Carla = length  of drawing / actual length of classroom

                                = 5 inches/480 inches = 1/96 (answer)

Help help help help help help help

Answers

The answer is A (or the first one) because the numbers are just switched around but they stay the same.
The first one is equivalent to the Associative Property of Multiplication because  a•(b • c) = (a • b) • c.

What is 1/100 of 605 feet

Answers

1/100 of 605 is 6.05 because you divide 605 by 100

A store is having a sale where school supplies are 30% off their original price. A backpack is on sale for $11.20. What was the original price for the backpack?

Answers

To find the original price, you could use a variable to represent the original price in this equation;

Let p represent the original price

.70 × p=11.20

to solve this, we'd isolate the variable (p) 

p=11.20 ÷.70

p=16

The original price was $16
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