Calculate the angular velocity of a clocks second hand, its minute hand, and its hour hand. State in Rad/s. What is its angular acceleration in each case?
Answers
The angular velocity of a clocks second hand, its minute hand, and its hour hand are 0.1047rad/s, 1.745 × 10⁻³rad/s and 1.454 × 10⁻⁴rad/s respectively.
Time period for second hand;
Time period for minute hand;
Time period for hour hand;
Now, we use the relation between angular speed and time period:
Where ω is the angular velocity and T is the time period in seconds.
For Second hand
For Minute hand
For Hour hand
Therefore, the angular velocity of a clocks second hand, its minute hand, and its hour hand are 0.1047rad/s, 1.745 × 10⁻³rad/s and 1.454 × 10⁻⁴rad/s respectively.
Learn more: brainly.com/question/8711708
Second hand:
1 rev per minute = (2π radians/minute) x (1 min/60sec) = π/30 rad/sec
Minute hand:
1 rev per hour = (2π radians/hour) x (1 hr/3600 sec) = π/1800 rad/sec
Hour hand:
1 rev per 12 hours = (2π rad/12 hr) x (1 hr/3600 sec) = π/21,600 rad/sec
As long as the clock is in good working order, and the hands are turning steadily at their normal rate, there is no angular acceleration.
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of the cart at the end of this 3.0 second interval?
Answers
Answer:
V = 20.5 m/s
Explanation:
Given,
The mass of the cart, m = 6 Kg
The initial speed of the cart, u = 4 m/s
The acceleration of the cart, a = 0.5 m/s²
The time interval of the cart, t = 30 s
The final velocity of the cart is given by the first equation of motion
v = u + at
= 4 + (0.5 x 30)
= 19 m/s
Hence the final velocity of cart at 30 seconds is, v = 19 m/s
The speed of the cart at the end of 3 seconds
V = 19 + (0.5 x 3)
= 20.5 m/s
Hence, the final velocity of the cart at the end of this 3.0 second interval is, V = 20.5 m/s
Answers
9.0
0.91
Answers
Answer:
0.91
Explanation:
as equivalence resistance can be found out using the
1/Req = 1/r1 +1/r2 +1/r3......
now, 1/req= 1/2+1/3+1/4
=6/12+4/12+3/12
=13/12
i.e, req =12/13 =0.91
✌️:)