Factor out the greatest common factor. 3x + 27x^2Question 6 options:

3x(9x)


3x(x + 9x)


3x(x + 9x^2)


3x(1 + 9x)

Answers

Answer 1
Answer: 27x² + 3x
3x(9x) + 3x(1)
3x(9x + 1)

The answer is D.

Related Questions

The formula n = rt gives the number n of boxes packed in time t at rate r. A machine packs boxes at a constant rate of 11.5 boxes per minute.How many boxes will the machine pack in 6 min?please help! 15 points and I will thank the best answer!
Use the distributive property to multiply-7 (2x - 4)I think it's -14x + 28
To clean a tank, 3/4 cup of disinfectant is needed for every 2 gallons of water. How many cups of disinfectant are needed for 20 gallons of water?A. 7 1/2B. 15C. 22 1/2 D. 30
How also was this answered? pls. help​
Graph the line : y= -2/3x+4

Line AB contains points A (−2, 6) and B (4, 5). The slope of line AB is −6 negative 1 over 6 1 over 6 6

Answers

Answer:

The slope is negative 1 over 6

Step-by-step explanation:

we know that

The formula to calculate the slope between two points is equal to

m=(y2-y1)/(x2-x1)

we have

A(-2,6)\ B(4,5)

Substitute the values

m=(5-6)/(4+2)

m=-(1)/(6)

To work out the slope of a line, you have to divide the difference in y by the difference in x

The difference in y = 5-6 = -1
The difference in x = 4--2 = 6

So, -1/6 is the answer

What is 1386/1000 in simplest form

Answers

If you would like to write 1386/1000 in the simplest form, you can do this using the following steps:

1386/1000 = 693/500 = 1 193/500

The correct result would be 693/500.

Ms. Scott wrote a test. Part A had true/false questions, each worth 6 points. Part B had multiple choice questions, each worth 4 points. She made the number ofpoints for Part A equal the number of points for Part B. It was the least number of points for which this was possible,
Answer the following questions.
How many points was each part worth?
points
How many questions did Part A have?
questions
How many questions did Part B have?
questions

Answers

Answer:

1. How many points was each part worth?

 - 12 points

2. How many questions did part A have?

 - 2 questions

3. How many questions did Part B have?

 - 3 questions

Step-by-step explanation:

We can set up our equation like this:

6x = 4y

In the above equation, x is representing the number of true/false questions and y is representing the nymber of multiple choice questions.

Now, the problem tells us that they want the least number of points possible so we know we need to use low numbers.

Since 6 is higher than 4, it's easier to go off of there.

6 x 1 = 6                        4 is too big to go into 6 so we will move on.

6 x 2 = 12                      4 goes into 12 3 times so we can use this.

Now that we've figured this out, we can put it in our equation:

6(2) = 4(3)

In the above equation, we can see that I've put 2 in for x because we multiplied 6 by 2 to get 12. I also put 3 in for y because we multiplied 4 by 3.

Now we can start with the questions:

1. How many points was each part worth?

Each part was worth 12 points because we can multiply 6 by 2 and get 12 or 4 by 3 and get the same thing

2. How many questions did part A have?

Part A had 2 questions because this is what x was when we multiplied by 6

3. How many questions did Part B have?

Part B had 3 questions because this is what y was when we multiplied by 4

Hope this helps!!

Final answer:

Each part is worth 12 points. Part A has 2 questions. Part B has 3 questions.

Explanation:

The problem states that the number of points for Part A is equal to the number of points for Part B, and we need to find the least number of points for which this is possible. Let's represent the number of questions in Part A as x. Since each true/false question is worth 6 points, the total points for Part A will be 6x. Similarly, let's represent the number of questions in Part B as y. Since each multiple choice question is worth 4 points, the total points for Part B will be 4y. To find the least number of points for which the two parts are equal, we need to find the smallest common multiple of 6 and 4.

The prime factorization of 6 is 2 x 3.

The prime factorization of 4 is 2 x 2.

From the prime factorization, we can see that the least common multiple (LCM) of 6 and 4 is 2 x 2 x 3 = 12.

Therefore, each part is worth 12 points.

To find the number of questions in Part A and Part B, we can substitute 12 for the total points in each part and solve for x and y:

6x = 12

x = 2

4y = 12

y = 3

Learn more about Least Common Multiple here:

brainly.com/question/34291727

#SPJ2

Write an expression that is equivalent to 5(t+3) .

Answers

Answer: 5t+15

Step-by-step explanation: Distribute the 5 into the parenthesis.

5 x t = 5t

5 x 3 = 15

You will get 5t +15.

Answer: 5t+15

This is equivalent to 5t+5*3

To get the answer, you multiply the outer term 5 by each term inside

5 times t = 5*t = 5t

5 times 3 = 5*3 = 15

Then you add up those products to get 5t+15.

This is using the distributive property.

A quadratic equation x^2-8x+9=0 is rewritten in the form (x-p)^2=q. What are the values of p and q?

Answers

x^2-(2)(x)(4)+16-7=0
x^2-(2)(x)(4)+4^2 =7
(x-4)^2=7

So value of p is 4 and q is 7

If the cost of an orange is 18 kobo, what is the cost of 185 orange?​

Answers

Answer:

1 orange = 18

185 oranges = x

(cross multiply)

18*185 = x

x= 3,330 kobo

hope this helps

Answer:

3330 kobo

Step-by-step explanation:

We know that one orange costs 18 kobo and we want to find the cost of 185 oranges. We will need to use ratio's for this question. A ratio is to show how much of one thing there is compared to another. So,

1 orange : 18 kobo

185 oranges = ? kobo

185 ÷ 1 = 185

185 × 18 = 3330 kobo

The cost of 185 oranges is 3330 kobo considering that one orange is 18 kobo.