MATHEMATICS HIGH SCHOOL

A bag contains 5 yellow marbles, 7 pink marbles, and 3 purple marbles. Gordon selects a marble without looking. What is the probability that he selects a yellow marble or a purple marble? A.8/15
B.1/15
C.7/15
D.2/45

Answers

Answer 1
Answer: 5/15 x 3/15 = 1/3x 1/5 = 1/15

B is the answer.

Hope i become the brainliest

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Answers

Answer:

its 1

Step-by-step explanation:

Answer:

its number one

Step-by-step explanation:

thank you and I'm sure

What is the equation of the line in slope-intercept form?

Answers

Answer:

y = 4/3x + 4

Step-by-step explanation:

y = mx + b is the formula for finding the slope intercept form equation

m = slope

b = y intercept

If you look at points (-3, 0) and (0, 4), you can calculate the slope

You have to go over, from point (-3, 0), 3 times, and up four to get to the point (0, 4)

Slope is change in y over change in x, so, if we look to see where the line crosses the y-axis, or vertical axis, we can see it reach the number four on the y-axis, b = 4

Now, lets create your equation...

y = 4/3x + 4

Need help 20-24 anything helps

Answers

I’ve attached the work done on the paper
Hope this helped!

dalanay enlarges a photograph tahst is 3 inches long and 2 inches wide. the length of the enlarged photograph is 15 inches. what is the width of the enlarged photograph, in inches?​

Answers

Answer:

10 inches

Step-by-step explanation:

Length of photograph, L1 = 3 inches; Length of enlarged photograph, L2 = 15 inches; Width of photograph, W1 = 2 inches; Width of photograph, W2 = ?

Hence, L1/L2 = W1/W2

∴ W2 = (L2*W1)/L1 = (15 X 2)/3 = 10 inches

Let a=x^2+4. Use a to find the solutions for the following equation: (x^2+4)^2+32=12x^2+48. Which one of the following are solutions for x? Select any/all that apply. -8, -2, 4, 0, 2, -4, 8

Answers

(x^2+4)^2+32=12x^2+48 \n(x^2+4)^2+32=12(x^2+4) \ \ \ |-12(x^2+4) \n(x^2+4)^2-12(x^2+4)+32=0 \n\hbox{substitute a for } x^2+4: \na^2-12a+32=0 \na^2-4a-8a+32=0 \na(a-4)-8(a-4)=0 \n(a-8)(a-4)=0 \na-8=0 \ \lor \ a-4=0 \na=8 \ \lor \ a=4 \n \n\hbox{substitute 8 and 4 for a and solve for x:} \na=8 \n\Downarrow \n8=x^2+4 \ \ \ |-4 \n4=x^2 \nx=-2 \ \lor \ x=2 \n \na=4 \n\Downarrow \n4=x^2+4 \ \ \ |-4 \n0=x^2 \nx=0 \n \n\boxed{x=-2 \hbox{ or } x=0 \hbox{ or } x=2}

The solutions for x are -2, 0, 2.

Answer:

-2,0,2

Step-by-step explanation:

The given equation is:

(x^2+4)^(2)+32=12x^2+48

⇒(x^2+4)^(2)+32=12(x^2+4)

Substituting (x^2+4)=a in the above equation, we get

⇒a^(2)+32=12a

⇒a^2-12a+32=0

⇒a^2-4a-8a+32=0

⇒a(a-4)-8(a-4)=0

⇒(a-8)(a-4)=0

⇒a=8,4

Now,  (x^2+4)=a, then substituting the value of a in this equation,

x^(2)+4=8 and x^2+4=4

⇒x^(2)+4=8

⇒x={\pm}2 and

⇒x^(2)+4=4

⇒x=0

Thus, the value of x are -2,0 and 2.

Use the relation S { (3,4) , (2,3), (1,2), (2,1)} for questions 1 and 21. State the domain and range of S
2. Is S a function? Explain your reasoning.

Answers

Answer:

HOPE THIS HELPS!!

Step-by-step explanation:

1. The domain and range of relation S are as follows:

Domain: The domain refers to the set of all input values in a relation. In this case, the domain of S is {3, 2, 1}, which corresponds to the first element of each ordered pair in the relation.

Range: The range refers to the set of all output values in a relation. In this case, the range of S is {4, 3, 2, 1}, which corresponds to the second element of each ordered pair in the relation.

2. No, relation S is not a function.

To be considered a function, each input value (or element in the domain) should have only one corresponding output value (or element in the range). However, in the given relation S, the input value 2 is associated with both the output values 3 and 1.

Since one input value is associated with multiple output values, S fails the definition of a function.
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