A 4.00 kg stone is dropped from a height of 145 m. What is the stone’s potential and kinetic energy respectively when it is 50.0 m from the ground?A - 1,960 J, 5,680 J
B - 5,680 J, 1,960 J
C - 3,720 J, 1,950 J
D - 1,960 J, 3,720 J
Answers
Answer:
C - 3,720 J, 1,950 J
Explanation:
Hello
Epotential = M*G*H
Ep = (4)(9.8)(145-50)
Ep = 3729 J
Then
Ec = 1950 J
Best regards
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Answers
Answer:
73.8 N
Explanation:
The total volume is,
V =
=
= 0.1396 m
The average density is,
=
= 7.169 g/cm³
The linear mass density is,
μ = pπr²
= (7.169 x 10⁹) (π (0.3 x 10⁻³)²)
= 2.026 x 10⁻³ Kg/m
The fundamental mode of length is,
L = λ/2
λ=2L
= 2 x 0.65
= 1.3 m
The speed of the wave is,
v = λf
= 1.3 m x 147 Hz
= 1.91 m/s
The tension is,
v = √T/ц
T = ц v²
= 2.026 x 10⁻³)(1.91 m/s)²
= 73.769N
73.8N
Answers
Answer:
The mass of the object is 0.2 kg
Explanation:
The magnitude of the applied force = 2.0 N
The duration of application of the force = 0.1 second
The increase in velocity given to the body by the force = 1.0 m/s
From the equation of motion under acceleration, we have;
v = u + a·t
Therefore;
a = (v - u)/t
Where;
v = The final velocity
u = The initial velocity
t = The time taken for the change in velocity = 0.1 s
Given that the change in velocity = 1 m/s, we have;
v - u = 1 m/s
∴ a = (v - u)/t = 1 m/s/(0.1 s) = 10 m/s²
The acceleration, a = 10 m/s²
The equation for the applied force, F is F = Mass, m × Acceleration, a
Therefore, when the applied force, F = 2.0 N, and the acceleration, a is a = 10 m/s², we have;
F = Mass, m × Acceleration, a
2.0 N = Mass of the object × 10 m/s²
∴ Mass of the object = 2.0 N/10 m/s² = 0.2 kg
The mass of the object = 0.2 kg.
Answers
in order to float. 145 metric tons= 145,000 kilograms. Use the rough-but-close rule
of thumb that 1 liter of water has 1 kilogram of mass. So the barge displaces 145,000
liters, which is also 145 cubic meters of water.
(Length) x (width) x (depth of the part under water) = 145 cubic meters
Draft of the barge (depth under water) = 145 / (50 x 20) = 145/70 = 2.07 meters.
No, it will not clear the reef 1.5 meters below the surface. Either the barge will shave off the top 0.57 meter of the reef, or else the reef will do serious damage to the barge. In any case, there will be a situation.
B. Frequently cleaning the furnace filter.
C. Fixing cracks in the walls and floor.
D. Opening the front door in winter to filter and clean warm air.
Answers
Answer:
D. Opening the front door in winter to filter and clean warm ai
Explanation:
All of the following are examples of ways to improve energy efficiency of heating systems, except _______.
A. Closing off rooms that aren’t in use.
B. Frequently cleaning the furnace filter.
C. Fixing cracks in the walls and floor.
D. Opening the front door in winter to filter and clean warm air
for an heating systems it is better to keep the front door shut so that all the heat energy does not escape outside.
when heat energy is within a closed system ,it can still be utilized to keep the inhabitants warm otherwise there will be an exchange with the cold from winter fall outside the air, and the heating system's efficiency will be reduced
Answers
ANSWER: D. The universe is expanding.
Answers
The speed of the plane without a wind is 430 miles/hr and speed of the wind is 20 miles/hr.
What is Speed ?
Speed is a rate of change of distance with respect to time. i.e. v=dx÷dt. Speed can also be defined as distance over time
i.e. speed= distance ÷ time
it is denoted by v and its SI unit is m/s. it is a scalar quantity.
Speed shows how much distance can be traveled in unit time.
To find dimension for speed is, from formula
Speed = Distance ÷ Time
Dimension for distance is [L¹] ,
Dimension for Time is [T¹],
Dividing dimension of distance by dimension of time gives,
{L¹] ÷ [T¹] = [L¹T⁻¹]
Dimension for speed is [L¹T⁻¹].
Consider,
Speed of the plane = v
Speed of the wind = u
Speed of the wind in the direction of wind is,
v + u = 450 miles/hr.....1
Speed of the wind in the opposite direction of wind is,
v - u = 410 miles/hr.....2
Adding equation 1 and 2
2v = 860
v = 430 miles/hr
Subtracting equation 1 and 2
2u = 40
u = 20 miles/hr
Hence the speed of the plane without a wind is 430 miles/hr and speed of the wind is 20 miles/hr.
To know more about Speed :
#SPJ2.
the plane is 430 and the wind it 20miles