CHEMISTRY HIGH SCHOOL

This is an interaction in which two waves meet, matching crest to crest and trough to trough. The resultant wave will have an amplitude of the sum of the two.

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Answer 1

Answer:

I'm Osei George the answer is interference

Answer 2

Answer:

Answer:deferehug

Explanation:

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What do the 14th Amendment and the Civil Rights Act of 1866 have in common?A. They were ways Congress sought to guarantee blacks the full rights of citizenship.B. They were efforts by Congress to solve economic problems in the South.
C. They were attempts by President Abraham Lincoln to end regional and racial divisions.
D. They were laws President Andrew Johnson supported to punish south slave owners.

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A. They were ways Congress sought to guarantee blacks the full rights of citizenship.

An atom with an equal number of electrons and protons has no _________.A. reactivity
B. weight
C. charge

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The answer would be C. charge because the protons, which are positively charged particles, and the electrons, negatively charged particles, balance each other out and the atom becomes of a neutral charge (or no charge)

According to astronomers , the age of the universe is estimated to be

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The age of the universe is approximately 13.8 billion years old. The universe is constantly expanding. A universe with a low density of matter is older than a matter – dmominated one. To determine the density and composition of the universe, scientists rely on missions such as NASA’s Wilkinson Microwave Anisotropy Probe spacecraft. They measure the thermal radiation left from Big Bang.

A mixture of CH4 and H2O is passed over a nickel catalyst at 1000 K. The emerging gas is collected in a 5.00-L flask and is found to contain 8.62 g of CO, 2.60 g of H2, 43.0 g of CH4, and 48.4 g of H2O.

Answers

The given question is incomplete. But the complete question is this:

A mixture of $CH_(4)$ and $H_2O$ is passed over a nickel catalyst at 1000 K. The emerging gas is collected in a 5.00-L flask and is found to contain 8.62 g of CO, 2.60 g of $H_2$ , 43.0 g of $CH_(4)$ , and 48.4 g of $H_(2)O$ . Assuming that equilibrium has been reached, calculate $K_(p)$ for the reaction.

Explanation:

As the given reaction is as follows.

$CH_4 + H_2O \rightarrow CO + 3H_2$

And, we know that

No. of moles = $\frac{mass}{\text{molar mass}}$

Therefore, calculate the moles as follows.

Moles of $CH_4$ = $(43)/(16.04)$

= 2.6808 mol

Moles of $H_2O$ = $(48.4)/(18.01528)$

= 2.6866 mol

Moles of CO = $(8.62)/(28.01)$

= 0.307747 mol

Moles of $H_(2)$ = $(2.6)/(2.01588)$

= 1.2897 mol

As, we know that

Concentration = $(moles)/(volume (L))$

Given volume = 5 L

Hence, calculate the concentration of given species as follows.

Conc. of $CH_4 = (2.6875)/(5)$

= 0.5361

Conc. of $H_2O = (2.6889)/(5)$

= 0.5373

Conc. of CO = $(0.307747)/(5)$

= 0.06155

and, Conc. of $H_2 = (1.2897)/(5)$

= 0.2579

Now, expression for equilibrium constant for the given reaction is as follows.

$K_(c) = ([CO][H_2]^(3))/([CH_4][H_2O])$

Now, putting the given values into the above formula as follows.

$K_(c) = ([0.06155][0.2579]^(3))/([0.5361][0.5373])$

$K_(c) = 3.665 * 10^(-3)$

Also, we know that

$K_p = K_c * (RT)^dn$

Consider the equation

$CH_4(g) + H2O(g) \rightarrow CO(g) + 3H_2(g)$

Calculate change in moles of gas as follows.

change in gas moles (dn) = 1 + 3 - 1 - 1

dn = 2

As, $K_p = K_c * (RT)^2$

It is given that,

T = 1000 K, R = 0.0821

So,

$K_p = 3.665 * 10^(-3) * (0.0821 * 1000)^(2)$

$K_p$ = 24.70

Thus, we can conclude that value of $K_(p)$ for the reaction is 24.70.

tert-Butyl alcohol is a solvent with a Kf of 9.10 ∘C/m and a freezing point of 25.5 ∘C. When 0.807 g of an unknown colorless liquid was dissolved in 11.6 g of tert-butyl alcohol, the solution froze at 15.3 ∘C.Which of the following is most likely the identity of this unknown liquid?tert-Butyl alcohol is a solvent with a of 9.10 and a freezing point of 25.5 . When 0.807 of an unknown colorless liquid was dissolved in 11.6 of tert-butyl alcohol, the solution froze at 15.3 .Which of the following is most likely the identity of this unknown liquid?ethylene glycol (molar mass = 62.07 g/mol)1-octanol (molar mass = 130.22 g/mol)glycerol (molar mass = 92.09 g/mol)2-pentanone (molar mass = 86.13 g/mol)1-butanol (molar mass = 74.12 g/mol)

Answers

Answer: ethylene glycol (molar mass = 62.07 g/mol)

Explanation:

Depression in freezing point :

Formula used for lowering in freezing point is,

$\Delta T_f=k_f* m$

or,

$\Delta T_f=k_f* \frac{\text{mass of solute}}{\text{molar mass of solute}* \text{weight of solvent in kg}}$

where,

$T_f$ = change in freezing point

$k_f$ = freezing point constant= $9.10^0C/m$

m = molality

Given mass of solute = 0.807 g

Molar mass of solute=? g/mol

weight of solvent in kg= 11.6 g=0.0116 kg

$\Delta T_f=T^(o)_f-T_f=25.5^0C-15.3^0C)=10.2^0C$

$10.2=9.10* \frac{0.807}{\text{molar mass of solute}* 0.0116kg}$

${\text{molar mass of solute}}=62.07 g/mol$

Thus the solute is ethylene glycol which has same molecular mass as calculated, i.e 62.07 g/mol.

Which statement describes the particles of an ideal gas, based on the kinetic molecular theory

Answers

this is easy...to put it simply, gas particles go in a straight line until they hit something, then ricochetand travel in a new direction, still in a straight line.

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