A teacher assigns a journal to be completed. In the journal, a student is supposed to include 32 quotations from a book they read in class. Their are 19 chapters in the book. How many quotations are to be given from every chapter?

Answers

Answer 1
Answer:

32➗19= 1.684...

So that would mean that you would need 1-2 quotations per chapter with the minimum of at least 1 per chapter.

You would need 1-2 quotations

Hope this helps! :3


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A mouse population starts with 2,000 mice and grows at a rate of 5% per year. The number of mice after t years can be modeled by the equation, P(t)=2000(1.05)^t. What is the average rate of change in the number of mice between the second year and the fifth year, rounded to the nearest whole number?

Answers

m=2000 (1.05)^2 for 2 years
so m=2205

m=2000 (1.05)^5 for 5 years
so m= approximately 2553


2553-2000
=553

That's your average rate of change in mice between two years and five years.

400,000,000,000 + 90,000,000,000 + 6,000,000,000 + 600,000,000 + 60,000,000 + 300,000 + 40,000 + 2,000 + 800 + 10 + 1 Write the standard form of the number shown above.

Answers

Answer:

Standard form = 496,660,342,811.

Step-by-step explanation:

Standard form is a way of writing down very large or very small numbers easily.

  • To convert small normal numbers into standard form.
  • Find the first non 0 digit after the decimal point.
  • After this digit, place your new decimal point ignoring everything that is in front of this digit.

General form:

400,000,000,000 + 90,000,000,000 + 6,000,000,000 + 600,000,000 + 60,000,000 + 300,000 + 40,000 + 2,000 + 800 + 10 + 1

Standard form:

Ans = 496,660,342,811.


i think it's 4.96x10^11
if you input into a calculator and count the decimal from the end to the left it should give you your answer
p.s. that was a bad explanation, im sorry

What are the first three terms of the sequence represented by the recursive formula an=n^2-an-1 if a5=14 1/4

Answers

Answer:

B. 0.25, 3.75, 5.25

just convert what the person above said but into decimals

Answer:

  1/4, 3 3/4, 5 1/4

Step-by-step explanation:

Solving for a[n-1], we get ...

  a[n-1] = n^2 -a[n]

Then ...

  a[4] = 5^2 -a[5] = 25 -14 1/4 = 10 3/4

  a[3] = 4^2 -a[4] = 16 -10 3/4 = 5 1/4

  a[2] = 3^2 -a[3] = 9 -5 1/4 = 3 3/4

  a[1] = 2^2 -a[2] = 4 -3 3/4 = 1/4

Then the first three terms are a[1], a[2], and a[3]:

  1/4, 3 3/4, 5 1/4

What is the volume of a cube shaped box with 6cm. In length?

Answers

volume= lxwxh
v= 6cm x 6cm x 6cm (all are 6 because it is a cube, so all sides are equal)
v= 216 cm³

Tanx cosx = 0i believe you have to use the cancellation method. you turn tanx into sinx/cosx times cos but i dont know where to go from there

Answers

You're almost finished.

(sin/cos) times cos = 0

Look at the left side.  You could write it as (sin x cos) / cos = 0
and simply divide numerator and denominator by the cosine (cancel it).

Then what do you have left ? . . .  sin(x) = 0       Do I need to finish this for you ?

At a concert 2/5 of the people were men, there were 3 times as many women as children. If there were 45 more men than children, how many people were there at the concert.

Answers

Final answer:

In solving the question, we establish two equations based on the condition provided, including the ratios among men, women, and children. Solving the equation, we find out that there were 270 people at the concert.

Explanation:

This question relates to the mathematical concept of ratio and proportion as well as fraction.

According to the question, 2/5 of the attendees at the concert were men and men outnumbered children by 45. First, let's make the number of children, x. So, the number of men will be x + 45. Because 2/5 of the total attendees were men, set up the equation: 2/5 * Total = x + 45.

There were 3 times as many women as children, thus the number of women will be 3x. So, the total number of people in the concert is the sum of the men, women, and children, which is (x + 45) + 3x + x. Simplifying this, we get 5x + 45 = Total. Therefore, if we substitute (x + 45) for 2/5 of the total in our original equation, we have 2/5 * (5x + 45) = x + 45. Solving this equation, we get x = 45.

So, if we substitute x=45 into our total equation, we get Total = 5(45) + 45 = 270. Therefore, there were 270 people at the concert.

Learn more about Ratio and Proportion here:

brainly.com/question/26974513

#SPJ12

This involves creating some equations.

First, these are what the letters I used stand for:

c = children

w = women

m = men

x = total population

Then, we must make an equation for each statement.

2/5x = m (2/5 of the people are men)

3c = w (there are 3 times as many women than children)

45+c = m (there are 45 more men than children)

Now, let's start plugging in our numbers:

x = all the men, women, and children

2/5(m+w+c) = m

2/5 (45+c +3c + c) = m     [Now simplify]

2/5 (45 + 5x) = m       [Now Distribute]

2/5(45) + (2/5)(5x) = m

2c + 18 = m    [Above we stated that there were the same amount as men as c +45]

2c + 18 = 45 +c     [Now set equal to c]

2c (-c) +18 = 45 +c (-c)

c+18 (-18) = 45 (-18)

c = 27

Now that we know that there was 27 children, we can plug 27 in for c in the other equations.

MEN = 27 + 45

WOMEN = 3(27)

CHILDREN = 27

Now add those three answers to find your total!