MATHEMATICS MIDDLE SCHOOL

B. Henry lives 95 km from work. How many kilometres does he drive to and from work each week? c. Henry uses 9 litres of fuel for each trip. (18 litres per day ) How many litres of fuel does he use each week?

d. if he pays 120 cents per litre, how much does it cost to drive to and from work each week? Remember to divide your answer by 100 to convert the cost to dollars and cents.

Answers

Answer 1
Answer:

Answer:

(b) 950 km

(c) 90 litres

(d) $108

Step-by-step explanation:

Henry lives 95 km from work.

Number of km from home to work = 95 km

Number of km from work to home = 95 km

One day = 95 + 95 = 190 km

Assuming he works 5 days a week.

1 day = 190 km

5 days = 190 x 5 = 950 km

Assuming he works 5 days a week.

1 day = 18 litres

5 days = 18 x 5 = 90 litres.

Assuming he works 5 days a week.

1 litre = 120 cents

90 litres = 120 x 90 = 10800 cents = $108

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In △ABC, m∠A=72°, c=61, and m∠B=16°. Find the perimeter of the triangle.

Answers

The perimeter of the triangle is about 136

Further explanation

Firstly , let us learn about trigonometry in mathematics.

Suppose the ΔABC is a right triangle and ∠A is 90°.

sin ∠A = opposite / hypotenuse

cos ∠A = adjacent / hypotenuse

tan ∠A = opposite / adjacent

There are several trigonometric identities that need to be recalled, i.e.

cosec ~ A = (1)/(sin ~ A)

sec ~ A = (1)/(cos ~ A)

cot ~ A = (1)/(tan ~ A)

tan ~ A = (sin ~ A)/(cos ~ A)

Let us now tackle the problem!

This problem is about Sine Rule.

First of all, we will calculate the ∠C :

∠A + ∠B + ∠C = 180°

72° + 16° + ∠C = 180°

∠C = 180° - 72° - 16°

∠C = 92°

Next, we will use the Sine Rule to find the length of the other side of the triangle.

(c)/(\sin \angle C) = (b)/(\sin \angle B)

(61)/(\sin 92^o) = (b)/(\sin 16^o)

b \approx \boxed {16.82}

(c)/(\sin \angle C) = (a)/(\sin \angle A)

(61)/(\sin 92^o) = (a)/(\sin 72^o)

a \approx \boxed {58.05}

Finally, we can find the perimeter of a triangle with the following formula

\text{Perimeter of the triangle} = a + b + c

\text{Perimeter of the triangle} = 58.05 + 16.82 + 61

\text{Perimeter of the triangle} \approx \boxed {136}

Learn more

Answer details

Grade: College

Subject: Mathematics

Chapter: Trigonometry

Keywords: Sine , Cosine , Tangent , Opposite , Adjacent , Hypotenuse  

Answer:

136

Step-by-step explanation:

A telephone pole casts a shadow 30 feetlong while a nearby fence post 4 feet
high casts a shadow 3 feet long. How
high is the pole?

Answers

Answer:

The height of the pole is 40 feet.

Step-by-step explanation:

Answer:

Step-by-step explanation:

37.5 feet

50 points decreased by 26%

Answers

well you can set it up 26/100 and X/50 and cross multiply to get 100X=1300 and hen divide by 100 and you get 13 then you subtract 50 by 13 to get 37.

Answer:

37

Step-by-step explanation:

Sa se determine masurile unghiurilor formate de doua inaltimi ale unui triunghi echilateral

Answers

Let's determine the measures of the angles formed by two heights of an equilateral triangle.
i dont think i speak your language 

How do you write 50,372 in word form

Answers

fifty thousand three hundred and seventy two
Fifty thousand, three hundred, seventy, two
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