What is the GCF of 56 and 40

Answers

Answer 1

Answer: Okay so the factors for 56 are 1, 2, 4, 7, 8, 14, 28, and of course 56. So the factors for 40 are 1, 2, 4, 5, 8, 10, 20, and of course 40.
Okay so now the prevalent factors are now 1, 2, 4, and 8.
So the greatest prevalent factor is now 8.
The GCF can be calculated by identifying the prevalent prime numbers and by withal multiplying them together.
The prime factors of 56 are 2, 2, 2, and 7
The prime factors of 40 are 2, 2, 2, and 5.
Okay so now the prime factors in prevalence are 2, 2, and 2, so the greatest mundane factor is 2 x 2 x 2 = 8.
I do hope this helps you!

Answer 2

Answer: 8 it will be there 8 goes evenly into both 56 and 40 hope this helped

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The sum of the roots of 8x^2- 2x

Answers

Answer:

1/4

Step-by-step explanation:

To find the roots of the expression, factor the expression by GCF.

$8x^2 - 2x\n2x(4x-1)$

The roots are the factors set equal to 0 and solved for x.

2x = 0

x=0

4x-1 = 0

x = 1/4

The sum is the addition of the two roots 0 + 1/4 = 1/4

A spinner has 3 equal sections that are red white and blue what would be the probability of not landing on the blue

Answers

the probability of it not landing on blue %66.666

Solve 2x2 + 12x − 14 = 0 by completing the square.

Answers

add 14 both sides
2x^2+12x=14
make term in front of x^2 1

divide both sid s by 2
x^2+6x=7
take 1/2 of 6 and square it and add to both sides (6/2=3 3^2=9)
x^2+6x+9=7+9
factor pefect square
(x+3)^2=16
sqrt both sides
x+3=+/-4
minus 3
x=+/-4-3
x=4-3 or -4-3
x=1 or -7

3x+y=17 4x-y=18 how can you order a ladder?

Answers

3x + y = 17
4x - y = 18

Add both the equations together.

3x + 4x + y - y = 17 + 18
7x = 35
x = 5

Plug in x = 5 into any equation, and solve for y.

3(5) + y = 17
15 + y = 17
y = 2

Your solution is (5,2).

How can you order a ladder?
Call the rung number

What's the answer, "If 84 cookies will serve 28 students, how many cookies are needed for 30 students" I need serious help!!!

Answers

For this question you will need to find out how many cookies each student eats. To find this, do 84 divided by 28. You will get 3. Since 28 is 2 less than 30, add 6 cookies for the two extra students. You will need 90 cookies.

First you need to figure out how many cookies will serve a single student.
You divide 84 by 28 and get 3.
So if 3 cookies serves an individual student, you multiply 3×30 and get 90. 90 cookies serve 30 students.

Can 1 be an additive identity?

Answers

Hey there, Valensolar! I would usually explain my answer, but in this case, I cant use any of the symbols required. But the answer is no. The number 1 can NOT be an additive identity. I hope this helps! :D

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