A puck moves 2.35 m/s in a -22° direction. A hockey stick pushes it for 0.215 s, changing its velocity to 6.42 m/s in a 50.0° direction. What was the direction of the acceleration?

Answers

Answer 1

Answer:

The puck starts with velocity vector

$\vec v_0=\left(2.35(\rm m)/(\rm s)\right)(\cos(-22^\circ)\,\vec\imath+\sin(-22^\circ)\,\vec\jmath)=(2.18\,\vec\imath-0.880\,\vec\jmath)(\rm m)/(\rm s)$

Its velocity at time $t$ is

$\vec v=\vec v_0+\vec at$

Over the 0.215 s interval, the velocity changes to

$\vec v=\left(6.42(\rm m)/(\rm s)\right)(\cos50.0^\circ\,\vec\imath+\sin50.0^\circ\,\vec\jmath)=(4.13\,\vec\imath+4.92\,\vec\jmath)(\rm m)/(\rm s)$

Then the acceleration must have been

$\vec v=\vec v_0+(0.215\,\mathrm s)\vec a\implies\vec a=(\vec v-\vec v_0)/(0.215\,\rm s)=(9.06\,\vec\imath+27.0\,\vec\jmath)(\rm m)/(\mathrm s^2)$

which has a direction of about $71.4^\circ$ .

Answer 2

Answer:

Final answer:

The direction of the acceleration is determined by the direction of the change in velocity. This would be calculated by subtracting the initial velocity vector from the final velocity vector. However, the calculation would involve complex trigonometric functions.

Explanation:

In order to find the direction of the acceleration, we need to calculate the direction of the change in velocity and that direction will be the direction of the acceleration.

To calculate the change in velocity, we subtract the initial velocity from the final velocity: (6.42 m/s, 50.0°) - (2.35 m/s, -22°). We then calculate the angle of this vector which represents the change in velocity, and hence the direction of acceleration.

However, this calculation is not straightforward because it involves vector operations and would require the use of trigonometric functions to solve. This is due to the fact that velocity is a vector, meaning it has both a magnitude and a direction. Consequently, this becomes a multi-step process involving trigonometry and physics.

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The total energy of a 0.050 kg object travelling at 0.70 c is:A) 2.10 × 107 J

B) 3.06 × 107 J

C) 2.46 × 1015 J

D) 6.30 × 1015 J

E) 8.82 × 1015 J

Answers

Answer:

1.1025×10^15Joules

No correct option

Explanation:

The type of energy possessed by the object is kinetic energy. Kinetic energy is the energy due to virtue of an object motion.

KE = 1/2MV² where;

M is the mass of the car = 0.05kg

V is the velocity of the car

Since the car is traveling at 0.7c (c is the speed of light)

speed = 0.7c { 0.7(3×10^8)}

Speed = 2.1×10^8

Substituting this values in the formula given we have;

KE = 1/2×0.05×(2.1×10^8)²

KE = 1.1025×10^15Joules

No correct option.

What is the unit c denotes here

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Answers

The correct answer is

A concave lens diverges light and curves inward.

A picture of a concave lens and the ray diagram produced by it can be seen in attachment. As it can observed, the concave lens (also called diverging lens) is wider at the edges and narrow at the centre (so, it curves inward), and it can also be seen that the lens diverges the incoming light rays.

A concave lens diverges light and curves inward is the statement which

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What is a Concave lens?

This type of lens is used to treat short-sightedness and has at least one of

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ensure proper view.

It has a high degree of diffraction and is the reason why option A was

chosen as it's the most appropriate choice.

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Answers

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Final answer:

Thermohaline circulation is driven by density, salinity, and temperature. These factors cause changes in the water's density, leading to the creation of ocean currents.

Explanation:

Thermohaline circulation is primarily driven by density, salinity, and temperature. Salinity and temperature affect the density of ocean water, with higher salinity and lower temperature leading to a denser substance. When water in an area of the ocean becomes denser than the surrounding water, it sinks, creating a current. This process is global, meaning it involves the entire ocean system and thus is an essential part of Earth's climate.

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Answers

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I dont get what 42 m below the horizontal is, can someone give me direction on how to do this?