The graph of f(x) = (1)/(4) 3^(x) -6 is shown below. g(x) is a transformation of f(x). How would you write the equation for the function g(x)?A. g(x) = (1)/(4)3^(x)  +2
B. g(x) = -(1)/(4)3^(x)  -6
C. g(x) = (1)/(3) *4^(x)  +3
D. g(x) = 3^(x) +2
The graph of [tex]f(x) = \frac{1}{4} 3^{x} -6[/tex] is shown - 1

Answers

Answer 1
Answer:

Answer:

A

Step-by-step explanation:

If g(x) is a transformation of f(x), then we can consider function f(x) as parent function.

So, to get the graph of the function g(x), we have to translate the graph of the function f(x) 8 units up.

This translation will give us the function

g(x)=f(x)+9\n \ng(x)=(1)/(4)\cdot 3^x-6+8\n \ng(x)=(1)/(4)\cdot 3^x+2

Answer 2
Answer:

Answer:

the answer would be like finding the point and then doing the math

after the math u will find you answer on the am going to say either C or D

Step-by-step explanation:


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The scoop of an excavator holds 27 ft3 of sand. If the capacity of a freight car is 40 tons of sand and we know that 1 ft3 of sand weighs 0.5 tons, how many freight cars can be filled with 120 loads?

Answers

27ft³=x tons
1ft³=0.5 tons

(27cubicfeet)/(x_t_o_n_s) = (1cubic foot)/(0.5 tons)

Cross multiply
1x=13.5tons
x=13.5tons

So one scoop/load carries 13.5 tons of sand. Lets see how many 120 loads can carry.

13.5tons*120loads=1620 tons of sand

Now lets see how freight cars it would take to hold 1620 tons of sand

1620/40=40.5 freight cars

Since you can't have .5 of a freight car, lets round 40.5 up to 41

Answer=41 freight cars

Answer:

40.5

Step-by-step explanation:

Please show me how to solve for Xsquared - 21.75X = -15.75. I have the solution but do not know how to solve it.

Answers

x^2-21.75x=-15.75 \nx^2-21.75x+15.75=0

Use the quadratic formula:
x^2-21.75x+15.75=0 \n \na=1 \n b=-21.75 \n c=15.75 \n b^2-4ac=(-21.75)^2-4 * 1 * 15.75=473.0625-63=410.0625 \n \nx=(-b \pm √(b^2-4ac))/(2a)=(-(-21.75) \pm √(410.0625))/(2 * 1)=(21.75 \pm 20.25)/(2) \nx=(21.75-20.25)/(2) \ \lor \ x=(21.75+20.25)/(2) \nx=(1.5)/(2) \ \lor \ x=(42)/(2) \nx=(15)/(20) \ \lor \ x=21 \nx=(3)/(4) \ \lor \ x=21 \n\boxed{x=(3)/(4) \hbox{ or } x=21}

Brad spent 20 percent of his money to buy a car costing £6800 how much did he havePlease reply asap

Answers

He had 34000 euros total.  Divide 6800 by 0.2 (AKA 20%)
There are few ways but i prefere this way:

100/20=5
6800*5=?
6000*5=30000
800*5= 4000
+-----------
= 34000

=£34000

Is 3/8 greater than 1/8

Answers

yes 3/8 is bigger that 1/8 because there is 2 more 8ths added to it 
3/8 is greater than 1/8.

HOPE THIS HELPED
:)

Rectangle ABCD is similar to rectangle EFGH. Side CD is proportional to side ___.A.EF
B.FG
C.GH
D.HE

Answers

If the rectangle ABCD is similar to rectangle EFGH, side CD is proportional to the side

C. GH

The order of the letters in naming the rectangle gives us which sides are adjacent  in rectangle and which sides correspond to the other rectangle.

Answer: C. GH

Step-by-step explanation:

Given: Rectangle ABCD is similar to rectangle EFGH.

Side AB is corresponding to EF  [First two letters]

Side BC is corresponding to FG [Middle two letters]

Side CD is corresponding to GH [Last two letters]

Side AD is corresponding to EH [First and last letter]

We know that the corresponding sides of the similar figures are proportional.

Therefore, we can see that Side CD is proportional to side  GH.

A line has a rise of 6 and a slope of 1/20. What is the run?30
90
120
What is the answer please help.
Thank you

Answers

Answer:

\boxed{\boxed{\text{Run}=120}}

Step-by-step explanation:

From coordinate geometry we know that, slope is ratio of vertical change rise and the horizontal change run.

Mathematically,

\text{Slope}=\frac{\text{Rise}}{\text{Run}}

Putting the given values,

\Rightarrow (1)/(20)=\frac{6}{\text{Run}}

\Rightarrow \text{Run}=6* 20

\Rightarrow \text{Run}=120

Rise/Run=(Y-y)/(X-x)

6/Run=1/20=6/120

Say that R=Run

6/R=6/120

720/R=6

6R=720

R=720/6=120

Therefore Run=120.