Help please Isabella was standing directly below a power line, and her compass failed to give an accurate reading.

How could she explain why her compass was not working?

A

A compass works with a magnetic field, and the electric current running through the lines above it would interfere with the magnetic field.

B

The compass works because of an electric field, and the electric current running through the lines above would interfere with the electric field.

C

The compass works because of a gravitational field, and the magnetic current running through the lines above would interfere with the gravitational field.

D

A compass works because of a magnetic field, and the magnetic current running through the power lines above it would interfere with the magnetic field below it.

Answers

Answer 1

Answer:

a compass works with magnetic field the answer is d

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What is the wavelength of a 147-g baseball traveling at 91.0 mph?

Answers

The formula to determine the wavelength is, De-Broglie wavelength formula:

$\lambda =(h)/(mv)$ -(1)

where, $\lambda$ is wavelength, m is mass, v is velocity and h is Planck's constant = $6.63* 10^(-34) Js$ = $6.63* 10^(-34) kgm^(2)s^(-1)$

mass, m = 147 g (given)

Since, 1 g = 0.001 kg

So, 147 g = 0.147 kg

v = 91.0 mph (given)

Converting mph to mps:

Since, $1 mph = (1.609* 10^(3) ms^(-1))/(60* 60)$

So, $90 mph = (91* 1.609* 10^(3) ms^(-1))/(60* 60)$ = $40.67 ms^(-1)$

Substituting the values in formula 1:

$\lambda =(6.63* 10^(-34) kgm^(2)s^(-1))/(0.147 kg* 40.67 ms^(-1))$

$\lambda =1.11* 10^(-34) m$

Hence, the wavelength wavelength of a 147-g baseball traveling at 91.0 mph is

$1.11* 10^(-34) m$ .

Answer: its D

Explanation:

Write a balanced half-reaction describing the reduction of aqueous vanadium(V) cations to aqueous vanadium(I) cations.

Answers

Explanation:

Reduction is a chemical reaction in which electrons are gained by one of the atoms taking part in the reaction and lowering of an oxidation state of that atom.

Reduction takes place at the cathode.

In aqueous, vanadium(V) is present in +5 oxidation state which on reduction changes to vanadium(I) with +1 oxidation state.

The half reaction is :

$V^(5+)(aq)+4e^- \rightarrow V^(1+)(aq)$

The balanced half-cell reaction for the reduction of aqueous vanadium (V) cations to aqueous vanadium (I) cations is $\boxed{{{\text{V}}^(5 + )}\left({aq}\right) + 4{e^ - }\to {{\text{V}}^(1 + )}\left({aq}\right)}$ .

Further Explanation:

Redox reaction:

It is a type of chemical reaction in which the oxidation states of atoms are changed. In this reaction, both reduction and oxidation are carried out at the same time. Such reactions are characterized by the transfer of electrons between the species involved in the reaction.

The process of gain of electrons or the decrease in the oxidation state of the atom is called reduction while that of loss of electrons or the increase in the oxidation number is known as oxidation. In redox reactions, one species lose electrons and the other species gain electrons. The species that lose electrons and itself gets oxidized is called as a reductant or reducing agent. The species that gains electrons and gets reduced is known as an oxidant or oxidizing agent. The presence of a redox pair or redox couple is a must for the redox reaction.

The general representation of a redox reaction is,

${\text{X}} + {\text{Y}} \to {{\text{X}}^ + } + {{\text{Y}}^ - }$

The oxidation half-reaction can be written as:

${\text{X}} \to {{\text{X}}^ + } + {e^ - }$

The reduction half-reaction can be written as:

${\text{Y}} + {e^ - } \to {{\text{Y}}^ - }$

Here, X is getting oxidized and its oxidation state changes from to +1 whereas B is getting reduced and its oxidation state changes from 0 to -1. Hence, X acts as the reducing agent whereas Y is an oxidizing agent.

Initially, vanadium is present in +5 oxidation state. Its oxidation state changes from +5 to +1 oxidation state. The oxidation state of V is decreased during the reaction so reduction is taking place. The balanced reduction half-cell reaction is as follows

${{\text{V}}^(5 + )}\left({aq}\right) + 4{e^ - }\to {{\text{V}}^(1 + )}\left( {aq}\right)$

Learn more:

1. Which occurs during redox reaction? brainly.com/question/1616320

2. Oxidation and reduction reaction: brainly.com/question/2973661

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Redox reactions

Keywords: V5+, V1+, 4e-, oxidation state, reduction, oxidation, redox reaction, transfer of electrons, reducing agents, oxidizing agents.

1. Magnesium is the limiting reactant in this experiment. Calculate the theoretical yield of MgO for trial 1 and 2.2. Determine the percent yield of MgO for your experiment for trial 1 and 2.

3. Determine the average percent yield of MgO for the two trials.

Answers

Answer:

Part 1

Theoretical yield of MgO for trial 1 = 0.84 g

Theoretical yield of MgO for trial 2 = 1.01 g

Part 2

Percent yield trial 1 = 28.6 %

Percent yield trial 2 = 49.9 %

Part 3

Average percent yield of MgO for two trial = 39.25 %

Explanation:

Part 1.

Data Given

Trial 1 Trial 2

mass of empty crucible and lid: 26.679 g 26.685 g

mass of Mg metal, crucible and lid: 26.931 g 26.988 g

mass of MgO, crucible and lid: 27.090 g 27.179 g

Theoretical yield of MgO for trial 1 and 2 = ?

Solution:

As Mg is limiting reagent so amount of MgO depends on the amount of Mg.

So, now we will look for the reaction to calculate theoretical yield

MgO form by the following reaction:

Mg + O₂ ---------> 2 MgO

1 mol 2 mol

Convert moles to mass

Molar mass of Mg = 24 g/mol

Molar mass of MgO = 24 + 16 = 40 g/mol

So,

Mg + O₂ ---------> 2 MgO

1 mol (24 g/mol) 2 mol(40 g/mol)

24 g 80 g

So,

24 g of Mg gives 80 g of MgO

To Calculate theoretical yield of MgO for Trial 1

First we look for the mass of Mg in the Crucible

mass of Mg for trial 1

Mass of Mg = mass of Mg metal, crucible and lid - mass of empty crucible and lid

Mass of Mg = 26.931 g - 26.679 g

Mass of Mg = 0.252 g

As we come to know that 24 g of Mg gives 80 g of MgO, then amount of Mg from trial 1 that is 0.252 g will produce how many grams of MgO

Apply unity formula

24 g of Mg ≅ 80 g of MgO

0.252 g of Mg ≅ X g of MgO

Do cross multiplication

X g of MgO = 0.252 g x 80 g / 24 g

X g of MgO = 0.84 g

So the theoretical yield of MgO is 0.84 g

--------------

To Calculate theoretical yield of MgO for Trial 2

First we look for the mass of Mg in the Crucible

mass of Mg for trial 2

Mass of Mg = mass of Mg metal, crucible and lid - mass of empty crucible and lid

Mass of Mg = 26.988 g - 26.685 g

Mass of Mg = 0.303 g

As we come to know that 24 g of Mg gives 80 g of MgO, then amount of Mg from trial 2 that is 0.303 g will produce how many grams of MgO

Apply unity formula

24 g of Mg ≅ 80 g of MgO

0.303 g of Mg ≅ X g of MgO

Do cross multiplication

X g of MgO = 0.303 g x 80 g / 24 g

X g of MgO = 1.01 g

So the theoretical yield of MgO is 1.01 g

__________________________

Part 2

percent yield of MgO for trial 1 and 2 = ?

Solution:

For trial 1

To calculate percent yield we have to know about actual yield of MgO

mass of MgO for trial 1

Mass of MgO = mass of MgO, crucible and lid - mass of empty crucible and lid

Mass of MgO = 27.090 g - 26.685 g

Mass of MgO = 0.24 g

And we also know that

Theoretical yield of MgO for trial 1 = 0.84 g

Formula used

Percent yield = actual yield / theoretical yield x 100

put values in above formula

Percent yield = 0.24 g / 0.84 g x 100

Percent yield = 28.6 %

--------------

For trial 2

To calculate percent yield we have to know about actual yield of MgO

mass of MgO for trial 2

Mass of MgO = mass of MgO, crucible and lid - mass of empty crucible and lid

Mass of MgO = 27.179 g - 26.685 g

Mass of MgO = 0.494 g

And we also know that

Theoretical yield of MgO for trial 2 = 1.01 g

Formula used

Percent yield = actual yield / theoretical yield x 100

put values in above formula

Percent yield = 0.494 g/ 1.01 g x 100

Percent yield = 49.9 %

--------------

Part 3

average percent yield of MgO for the two trials =?

Solution:

As we know

Percent yield trial 2 = 28.6 %

Percent yield trial 2 = 49.9 %

Formula used

Average percent yield = percent yield trial 1 + percent yield trial 2 / 2

Put values in above formula

Average percent yield = 28.6 + 49.9 / 2

Average percent yield = 78.5 / 2

Average percent yield = 39.25 %

Average percent yield of MgO for two trial = 39.25 %

explain what force caused the movement of the continets from one supercontinet to their present positions

Answers

convection currents in the mantle. heat rises, cool drops.

This was caused by plate tectonics. Convection currents caused by the magma flowing in the mantle, slowly spread the continents apart. FACT: The continents are still moving due to the convection currents in the mantle! Millions of years from now, there may be another super continent! And it will be a cycle!

How are antibodies and receptor molecules function similarly

Answers

Answer:

Antigens are molecules capable of stimulating an immune response. Each antigen has distinct surface features, or epitopes, resulting in specific responses. Antibodies (immunoglobins) are Y-shaped proteins produced by B cells of the immune system in response to exposure to antigens.

What is the conversion of 85.0kg

Answers

Answer:

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