Twenty percent of candies in a package are red. The rest are another color.Simulate randomly checking 20 packages for red candies using these randomly generated digits. Let the digits 1 and 2 represent a red candy.

91027 18200 74536 83514

Approximately how many red candies will be in the packages?
Twenty percent of candies in a package are red. The - 1

Answers

Answer 1
Answer:

Answer:

  5

Step-by-step explanation:

Among the 20 digits shown, each digit appears in the list twice except 0 and 1 appear 3 times and 6 and 9 appear once. That means ...

  • 1 appears 3 times
  • 2 appears 2 times

So, if 1 and 2 represent red candies, there are 3+2 = 5 red candies in the simulated random sample of 20 candies.

_____

Comment on the question

The simulation makes sense only if it represents taking a single candy from each of 20 packages (of unknown quantity of candies). That is, it seems we cannot answer the question, "how many red candies will be in the packages?" We can only answer the question, "how many of the simulated candies are red?"

Answer 2
Answer:

Answer:

5

This is the correct answer! I just took the test! Good luck!


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Divide 36 by the difference of 16 and 4

Answers

The answer is 3. First you solve 16-4 and you get 12. Then you solve 36/12 which equals 3.
You subtract ➡️. first 16-4= 12
Then divide ➡️. 36 divided by 12 is =3 so the answer is 3

A scientist begins an experiment with a culture of 5 bacteria cells. Every hour, the number of bacteria cells triples. Which equation can be used to represent the number of bacteria cells, y, as it relates to time in hours, x?a. y = 5 x
b. y = 3(5) x
c. y = 3 x
d. y = 5(3) x

Answers

The answer is c hope it helps

Help meeeeeeeeeeeee pleaseeeeeeee

Answers

Answer:

i think its b

Step-by-step explanation:

3. What is the slope and the y-intercept ofthe line represented by equation:
2x + y = 1?
Explanation:

Answers

Answer:

The slope is -2/1 or simplified -2 and the y-intercept is 1

Step-by-step explanation:

transform the quadratic function y=-2x^2-12x-10 into vertex form. find the vertex, x and y intercepts.

Answers

The\ vertex\ form\ of\ y=ax^2+bx+c:y=a(x-h)^2+k\n\nwhere\ h=(-b)/(2a)\ and\ k=f(h)=(-(b^2-4ac))/(4a)\n-----------------------------\n\ny=-2x^2-12x-10\n\na=-2;\ b=-12;\ c=-10\n\nh=(-(-12))/(2(-2))=(12)/(-4)=-3\n\nk=f(-3)=-2(-3)^2-12(-3)-10=-2\cdot9+36-10=-18+26=8\n\ntherefore:y=-2(x-(-3))^2+8\to\boxed{y=-2(x+3)^2+8}\leftarrow The\ vertex\ form


y-intercept\to f(0)=-2(0^2)-12(0)-10=\boxed{-10}\leftarrow y-intercept


x-intercept\ if\ y=0\n\n-2x^2-12x-10=0\ \ \ \ \ |divide\ both\ sides\ by\ (-2)\nx^2+6x+5=0\nx^2+x+5x+5=0\nx(x+1)+5(x+1)=0\n(x+1)(x+5)=0\iff x+1=0\ or\ x+5=0\n\n\boxed{x=-1\ or\ x=-5}\leftarrow x-intercept
y=-2x^2-12x-10
to find the x value of the vertex find the axis of symmetry which is
-b/2a
=12/2(-2)
=-3
to find the y value of the vertex sub the axis of symmetry back into the original equation. 
y=-2(-3)^2-12(-3)-10
y=8
vertex=(-3,8)
to put it into vertex form use y=a(x-h)^2 +k where h and k are the x and y values of the vertex respectively. 

y=-2(x--3)^2 +8
y=-2(x+3)^2+8

to find the x intercept let y=0

-2x^2-12x-10=0
x^2+6x+5=0 
use quad formula and you will get 
x=-5 and -1

to find the y intercept let x=0

y= -2(0)^2-12(0)-10
y=-10







What is the value of w in the equation 1/2w+7=2w-2

Answers

(1)/(2)w+7=2w-2\ \ \ \ |subtract\ 7\ from\ both\ sides\n\n(1)/(2)w=2w-9\ \ \ \ |subtract\ 2w\ from\ both\ sides\n\n-1(1)/(2)w=-9\n\n-1.5w=-9\ \ \ \ |divide\ both\ sides\ by\ (-1.5)\n\n\boxed{w=6}