MATHEMATICS MIDDLE SCHOOL

Find the circumference of a circle with an area of 254.47 square inches.

Answers

Answer 1

Answer:

Answer:

56.5 inches

Step-by-step explanation:

We are given the area of a circle and we are to find the circumference of the same circle.

We know that the area of a circle is given by $\pi r^2$ so equating the given value to get.

$\pi r^2=254.47$

$r^2=(254.47)/(\pi )$

$r=√(81.00)$

r = 9 inches

Since we now know the radius of the circle so we can find its circumference.

Circumference of circle = $2\pi r$ = $2\pi (9)$ = 56.5 inches

Answer 2

Answer:

Answer: 56.54 in

Step-by-step explanation:

The area can be calculated with this formula:

$A=\pi r^2$

Where r is the radius

And the circumference can be calculated with this formula:

$C=2\pi r$

Where r is the radius

Solve for the radius from $A=\pi r^2$ . Then, tha radius is:

$r=\sqrt{(A)/(\pi )}=\sqrt{(254.47in^2)/(\pi )} =9in$

Then, the circumference is:

$C=2\pi (9in)=56.54in$

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Caleb draws 14 dogs on each of 4 posters. He draws 18 cats on 6 other posters. If he draws 5 more dogs on each poster with dogs, how many dogs & cats does he draw

Answers

Caleb draws 24 cats. Caleb Draws 19 dogs.

24 cats and 19 dogs are drawn

jeanette drew a rectangle with an area of 6 square centimeters identify a possible length and width for her rectangle

Answers

so if its the area, the area is length times width. I think it would be two numbers that equal 6, so length is 3 and width is 2 :)

describe the shape Center and spread of data distribution. are ther any outliers numbers 12 10 11 9 9 10 12 9 8 7 9 10

Answers

No, there are not any outliers because all of the numbers are relatively close in value

Final answer:

The data distribution is a normal distribution with a mean of 10. The spread of the data is 5 and there are no outliers.

Explanation:

The data distribution can be described as a symmetric bell-shaped curve, indicating a normal distribution. The center of the distribution is the mean, which can be calculated by adding up all the numbers and dividing by the total count. In this case, the mean is 10.
The spread of the distribution can be determined by calculating the range, which is the difference between the highest and lowest values. In this case, the range is 12 - 7 = 5.
To determine if there are any outliers, we can use the concept of the interquartile range (IQR). The IQR is the range of the middle 50% of the data. First, we need to calculate the first quartile (Q1), which is the median of the lower half of the data, and the third quartile (Q3), which is the median of the upper half of the data. In this case, Q1 = 9 and Q3 = 11.
The IQR is then calculated as Q3 - Q1 = 11 - 9 = 2. Any data point that falls below Q1 - 1.5 * IQR or above Q3 + 1.5 * IQR is considered an outlier. Since there are no numbers that meet this criteria in this dataset, there are no outliers.

Learn more about Data Distribution here:

brainly.com/question/32135692

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PLEASE HELP GIVING BRAINLIEST I NEED TO PASS THIS CLASS!!!The graph of an exponential function of the form y = f(x) = a^x passes through the points_____ and ____ . The graph lies ____ the x-axis.

Answers

y = f(x) = a^x is an expo function with constant base a and exponent x. First, let's assume that a is positive and lying either in (0,1) or (1, infinity).

If a satisfies 0<a<1, then the expo fn is decreasing with x. Its y-intercept is (0,1) because a^0 = 1 for all a that satisfy (0,1). Same is true for (a>1).

In both cases the horiz. asymptote is the line y=0.

y = f(x) = a^x has only one intercept, the y-intercept, (0,1).

However, z = f(x) = a^x + C could have an x-intercept for certain C.

a square has a side length of x. A rectangle has a length that is 4 inches longer than the square and a width that is 2 inches shorter than the square. If the areas of the square and rectangle are equal, what is the length of the rectangle?

Answers

Answer:

Length of the rectangle is = 8 inches.

Step-by-step explanation:

Given :

Area of square = Area of the rectangle

According to the question:

Length of the square be 'x'.

Its area = (Side)*(Side) = $x^2$ ...equation (i)

Length of the rectangle = $(x+4)$

Width of the rectangle = $(x-2)$

Area of the rectangle =Length * Width

⇒ $(x+4)(x-2)=x^2-2x+4x-8$

⇒ $x^2+2x-8$ ...equation (ii)

Equating both the equation as area of both the figure are equal.

⇒ $x^2+2x-8=x^2$

⇒ $2x-8=0$ ...subtracting $x^2$ both sides

⇒ $2x=8$ ...dividing both sides with 2

⇒ $x=(8)/(2)=4$ inches

Plugging the value of x=4 in the length of the rectangle.

We have,

⇒ $(x+4)=(4+4)=8$

So the length of the rectangle = 8 inches.

jose jumped 8 1/3 feet. this was 2 1/3 feet farther than lila jumped. how far did lila jump TELL MEH AFTER THIS I GET ON IXL

Answers

In this scenario Jose jumped the distance Lila jumped plus 2 1/3 ft, so...

Lilia + 2 1/3 = 8 1/3

subtract 2 1/3 from each side to get Lila by herself

Lila = 8 1/3 - 2 1/3
Lila = 6

Lila jumped 6 feet

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