What happens to a spermatid to change it into a sperm cell?

Answers

Answer 1
Answer:

Answer:

The correct answer is meiosis takes place, making the sperm cell haploid.

Explanation:

From secondary spermatocytes, the formation of haploid male gamete, that is, spermatid takes place. Its formation takes place by the procedure of meiosis, and therefore, it comprises half of the genetic substance as found in in the primary spermatocyte.  

In the beginning, spermatid is a round, immotile cell that distinguishes and turns motile and unique by the procedure is known as spermiogenesis.  

Answer 2
Answer: The process in which the spermatogonia that are located in the base portion of the germinal epithelium and differentiate it into a sperm is called spermatogenesis. The spermatid is an immature sex cell that is from a spermatocyte and after it had gone meiosis it will transform into a new mature sperm cell.

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Which term describes the point when two objects reach the same temperature and there is no longer a transfer of energy through heat?1. Latent Heat
2.specific Heat
3.thermal equilibrium
4.Heat of Fusion

Answers

Answer: Option (3) is the correct answer.

Explanation:

When two substances or objects at the same temperature do not exchange heat with each other then this state is known as thermal equilibrium.

Whereas latent heat is the release or absorption of energy at a constant temperature.

Specific heat is the amount of heat per unit mass necessary to increase the temperature by one degree Celsius.

Heat of fusion is the amount of energy required to change the state of matter or substance.

Thus, we can conclude that out of the given options, thermal equilibrium describes the point when two objects reach the same temperature and there is no longer a transfer of energy through heat.




C. Thermal Equilibrium

A compound is formed when 171.2 g of carbon reacts with 28.8 g of hydrogen. What is the mass percent of hydrogen in the compound

Answers

Following the law of conservation of mass, the mass percent of hydrogen in the resulting compound is 14.4%(wt/wt). This is assuming that all of the carbon reacts with all of the hydrogen. The solution is as follows:

mass % = mass hydrogen*100/total mass = 28.8*100/(28.8+171.2) = 14.4%

Answer:

For Edmentum/Plato users, the correct answer is A. 14.4%

What would be the molecular formula for a triglyceride that contains 3 copies of the fatty acid below?

Answers

Fatty acid hope it’s helpful

According to the law of conservation of energy, the energy released by the system must be transferred to and absorbed by the surroundings

Answers

True! 
 Energy released by system is absorbed by surroundings.

When comparing bromine to chlorine, bromine hasA. Fewer protons in its nucleus.
B. A weaker effective nuclear charge
C. More valence electrons
D. More electron shielding

Answers

Explanation:

I'm pretty sure the answer is D

If 62.0 grams of magnesium metal (Mg) react with 55.5 grams of oxygen gas (O2) in a synthesis reaction, how many grams of the excess reactant will be left over when the reaction is complete? Be sure to write out the balanced equation for this reaction and to show all of your work.

Answers

The balanced chemical equation would be as follows:

Mg + O2 → MgO2

We are given the amounts of the reactants. We need to determine first which one is the limiting reactant. We do as follows:

62.0 g Mg (1 mol / 24.31 g ) = 2.55 mol Mg 
55.5 g O2 ( 1 mol / 32 g ) = 1.74 mol O2   -----> consumed completely and therefore the limiting reactant

2.55 mol - 1.74 mol O2( 1 mol Mg / 1 mol O2 ) = 0.81 mol Mg excess

Answer:

14.1648 grams of oxygen gas will be left.

Explanation:

2Mg +O_2\rightarrow 2MgO

Moles of magnesium metal =(62.0 g)/(24 g/mol)=2.5833 mol

Moles of oxygen gas =(55.5 g)/(32 g/mol)=1.7343 mol

According to reaction, 2 mol of magnesium react with 1 mol of oxygen gas .

Then 2.5833 moles of magnesium will react with:

(1)/(2)* 2.5833 mol=1.29165 mol of oxygen gas.

Moles of oxygen left unreacted =1.7343 mol - 1.29165 mol = 0.44265 mol

Oxygen gas is an excessive reagent.

Mass of 0.44265 moles of oxygen gas:

0.44265 mol × 32 g/mol = 14.1648 g

14.1648 grams of oxygen gas will be left.