What are the unit for acceleration
Answers
The rate of change of velocity per unit time is called acceleration.
Its SI unit is m/s².
Formula of acceleration is v-u/t
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an object at rest starts accelerating if it travels 30 meters to end up going 10 m/s what was it’s acceleration
A physical property that describes how something feels
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Forces Quiz 1. What is true about all forces?a. They are unbalancedb. They involve more than one objectc. They cause objects to moved. They cancel each other out
m/s
Answers
Answer:
7.1 m/s
Explanation:
First, find the time it takes for the fish to reach the water.
Given in the y direction:
Δy = 6.1 m
v₀ = 0 m/s
a = 9.8 m/s²
Find: t
Δy = v₀ t + ½ at²
6.1 m = (0 m/s) t + ½ (9.8 m/s²) t²
t = 1.12 s
Next, find the velocity needed to travel 7.9 m in that time.
Given in the x direction:
Δx = 7.9 m
a = 0 m/s²
t = 1.12 s
Find: v₀
Δx = v₀ t + ½ at²
7.9 m = v₀ (1.12 s) + ½ (0 m/s²) (1.12 s)²
v₀ = 7.1 m/s
Answer:
7.1m/s
Explanation:
EDGE
at the north and south poles
B.
next to the south pole
C.
in the middle of the magnet
D.
between the north and south poles
Answers
Answers
Hope this helps
Answers
Answer:
0.8684 atm
Explanation:
Using combined gas equation,
PV / T = k
P1*V1 / T1 = P2*V2 / T2
P1 = 1.10 atm
P2 = ?
V1 = 2.5L
V2 = 3.9L
T1 = 298k
T2 = 367k
P1*V1 / T1 = P2*V2 / T2
Making P2 the subject of formula;
P2 = P1*V1*T2 / V2*T1
P2 = 1.1*2.5*367 / 3.9*298
P2 = 1009.25 / 1162.2
P2 = 0.8684 atm
Here you go
This problem can be solved using one of the different gas laws, which is shown below:
PV/T
Given:
P1 = 1.1 atm
V1 = 2.5 L
T1 = 298 K
P2 = ?
V2 = 3.9 L
T2 = 367 K
Substituting the given:
P1V1/T1 = P2V2/T2
(1.1 * 2.5)/298 = (P2 * 3.9)/367
P2 = 0.868 atm
Hope it helps
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Answers
From the information given, cannon ball weighs 40 kg and has a potential energy of 14000 J.
We need to find its height.
We will use the formula P.E = mgh
Therefore h = P.E / mg
where P.E is the potential energy,
m is mass in kg,
g is acceleration due to gravity (9.8 m/s²)
h is the height of the object's displacement in meters.
h = P.E. / mg
h = 14000 / 40 × 9.8
h = 14000 / 392
h = 35.7
Therefore the canon ball was 35.7 meters high.
Final answer:
The height of the cannon ball to have 14000 J of potential energy is approximately 357.14 meters. This is calculated using the formula for potential energy: PE = mgh, and solving for 'h'.
Explanation:
The potential energy (PE) of an object is given by the formula PE = mgh, where 'm' is the mass of the object, 'g' is the acceleration due to gravity (standard approximate value is 9.8 m/s² on Earth), and 'h' is the height. In your question, we want to find the height 'h'. Given that the potential energy is 14000 J and the mass of the cannon ball is 40 kg, we can rearrange the formula to solve for 'h': h = PE / (m*g).
So, inputting the given values, h = 14000 J / (40 kg * 9.8 m/s²). Solving this, we find that the height is approximately 357.14 meters. This means the cannon ball was at around this height to have 14000 J of potential energy.
Learn more about Potential Energy here:
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Answers
Answer:
u fall
Explanation:
personal experience