A ball is thrown straight up. At the top of its path its acceleration isa. 0 m/s2.
b. about 5 m/s2.
c. about 10 m/s2.
d. about 20 m/s2. E. about 50 m/s2.
Answers
We have that From the Question a ball is thrown straight up. At the top of its path its acceleration is
0 m/s2.
Option A
From the question we are told
A ball is thrown straight up. At the top of its path its acceleration is
a. 0 m/s2.
b. about 5 m/s2.
c. about 10 m/s2.
d. about 20 m/s2.
E. about 50 m/s2.
Generally
For a Ball thrown straight up at the top of its path where The gravitational force equals the force of the thrown,the Point where the ball is at equilibrium the Velocity of the ball is zero
Therefore
From the Question
A ball is thrown straight up. At the top of its path its acceleration is
a. 0 m/s2.
Option A
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Answer:
Explanation:
Time can be found by dividing the distance by the speed.
The distance is 9,000 meters and the speed is 39 meters per second.
Substitute the values into the formula.
Divide. Note that the meters, or "m" will cancel out.
It takes 230.769231 seconds for the truck to travel 9,000 meters at 39 meters per second.
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It can also be described as the instantaneous rate of change of the particle's
distance traveled, and the direction in which the distance is changing.
v=d/t
where v is velocity
d is distance travelled and
t is time interval.....
its units are - kmph , m/s read as kilometers per second and meters per second
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B. The atom has 7 protons and 7 electrons.
C. The atom has 19 electrons and 19 neutrons.
D. The atom has 15 neutrons and 15 electrons.
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Answers
Final answer:
The speed a spherical raindrop would achieve falling from 3950 m in the absence of air drag is calculated by firstly finding the time it takes for the raindrop to fall this distance using equations of motion, and then using this time in the equation for final velocity. The calculated speed is approximately 2785.30 m/s.
Explanation:
To calculate the speed a spherical raindrop would achieve falling from 3950 m in the absence of air drag, we must recall the equations of motion. The relevant equation here is Final velocity (v) = Initial velocity (u) + Acceleration (gravity, g) * time (t). However, since initial velocity (u) is 0 (when the drop starts falling, it's stationary), the equation simplifies to Final velocity (v) = g * t.
In free fall, a body accelerates under gravity (approximated as 9.81 m/s^2). In terms of time, difficulties arise because we don't know exactly when the raindrop will hit the ground. We can, however, calculate the time it would take for the raindrop to fall 3950 m by rearranging the equation distance (s) = ut + 0.5 * g * t^2 to solve for time. Removing (u), for the reasons explained earlier, we have the equation s = 0.5 * g * t^2. Solving this for time gives t = sqrt(s / (0.5 * g)). Substituting the given fall distance for s we get t = sqrt(3950 / (0.5 * 9.81)) or approximately 284.10 seconds.
Finally, we use this calculated time in our simplified velocity equation which gives v = g * t or 9.81 * 284.10, which equals approximately 2785.30 m/s.
Learn more about Physics of Free Fall here:
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B. size.
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The property that distinguishes the potential energy from kinetic energy are the shape and position of the object, letter C. Potential energy is directly proportional with mass times gravity times the height of the object at rest. On the other hand, kinetic energy is directly proportional with half of the square of the velocity times the mass of the object in motion.