Whi is the domain of the function f(x)= x^3 (0,10) and the image (0,1000) ?I don't get it. Help me please.

Answers

Answer 1

Answer: The domain and range of f(x)=x^3 are:
x ∈ (-∞,∞)
y ∈ (-∞,∞)
so I am a little confused as to what your talking about.

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If Sally can paint a house in 4 hours, and John can paint the same house in 6 hour, how long will it take for both of them to paint the house together?A. 2 hours and 24 minutes
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Answers

Answer:No A

Step-by-step explanation:

2hours 24 minutes

1. Complete the tables of values below for graphing the secant and cotangent functions. You can type “U” for an undefined value. Use exact values with fractions and square roots, not the decimal approximations. For example, use 3/2 rather than 0.866 (pictures attached) 2. Graph the secant graph for 0 ≤ x ≤ 2π. Graph the cotangent graph for 0 ≤ x ≤ 2π. (don't need these pictures I have them)

3. Indicate whether each of the three reciprocal functions (cosecant, secant, and cotangent) is a periodic function. If so, state the period of each.

4. List the domain and range for the secant and cotangent functions. (Use "pi" for π.)

5. Compare the graphs of the cosecant and secant functions. How are they different? How are they similar?

Answers

Step-by-step explanation:

1. All the trigonometric values can be found using the unit circle. See attached table.

2. Graph:

desmos.com/calculator/10n7yrm3tm

3. All trig functions are periodic functions. The period of secant and cosecant is 2π. The period of cotangent is π.

4. Using the table from step 1 and the graph from step 2, secant has a domain of x ≠ pi/2, 3pi/2 and a range of x ≤ -1, x ≥ 1. Cotangent has a domain of x ≠ 0, pi, 2pi and a range of -∞ < x < ∞.

5. Graph:

desmos.com/calculator/tldiqt7qra

Cosecant has the same graph as secant shifted π/2 to the right. So they have different domains, but the same range.

How do you simplify this

Answers

You ALWAYS remove parentheses first.

That gives you [ 1/4 a⁴ b⁻² ] in the denominator, and then
you can start dividing the numerator and denominator by
their common factors ("canceling").

I think the answer to that might be 1/2 or .5ab^3 because I multiplied the bottom part -2*-2 which is 4ab^4 then the top part is 2ab -3+2= 2ab^-1 then divide 2/4 and subtract -1-4 so it's = 1/2 or .5ab^3

You are at a stall at a fair where you have to throw a ball at a target. There are two versions of the game. In the firstversion, you are given three attempts, and you estimate that your probability of success on any given throw is 0.1.
In the second version, you are given five attempts, but the target is smaller, and you estimate that your probability of
success on any given throw is 0.05. The prizes for the two versions of the game are the same, and you are willing to
assume that the outcomes of your throws are independent. Which version of the game should you choose? (Hint: In
the first version of the game, the probability that you do not get the prize is the probability that you fail on all three
attempts.)

Answers

Answer:

$P(X=0)=(3C0)(0.1)^0 (1-0.1)^(3-0)=0.729$

And the probability of loss with the first wersion is 0.729

$P(Y=0)=(5C0)(0.05)^0 (1-0.05)^(5-0)=0.774$

And the probability of loss with the first wersion is 0.774

As we can see the best alternative is the first version since the probability of loss is lower than the probability of loss on version 2.

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Alternative 1

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=3, p=0.1)$