Please help!!What is the value of x? Enter your answer in the box. x = NOTE: Image not drawn to scale. Triangle G E H with segment E D such that D is on segment G H, between G and H. Angle G E D is congruent to angle D E H. E G equals 44.8 millimeters, G D equals left parenthesis x plus 4 right parenthesis millimeters, D H equals 35 millimeters, and E H equals 56 millimeters.
Please help!! What is the value of x? Enter your - 1

Answers

Answer 1
Answer:

Answer:

The value of x is 24.

Step-by-step explanation:

Given information: In ΔGHE, ED is angle bisector, EG=44.8 millimeters, GD=(x+4) millimeters, DH=35 millimeters, and EH=56 millimeters.

According to the angle bisector theorem, an angle bisector divide the opposite side into two segments that are proportional to the other two sides of the triangle.

In ΔGHE, ED is angle bisector, By using angle bisector theorem, we get

(GD)/(DH)=(EG)/(EH)

(x+4)/(35)=(44.8)/(56)

Multiply both the sides by 35.

x+4=(44.8)/(56)* 35

x+4=28

Subtract 4 from both the sides.

x=28-4

x=24

Therefore the value of x is 24.

Answer 2
Answer:

Answer:

  x = 24

Step-by-step explanation:

The segments on either side of an angle bisector are proportional:

  (x +4)/44.8 = 35/56

  x +4 = 44.8·(35/56) = 28 . . . . multiply by 44.8

  x = 24 . . . . . subtract 4


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AJ, Blaze, Laurence, and Jack pick oranges. Blaze picks three times as many as Laurence. Jack picks twice as many as Blaze. Aj picks three times as many as Laurence. The total weight of the oranges is 1092 pounds. How many pounds does AJ pick?

Answers

Answer: 252 pounds.

Step-by-step explanation:

Let be "b" the amount of pounds  Blaze picks, "j" the amount of pounds Jack picks, "l" the amount of pounds Laurence picks and "a" the amount of pounds AJ picks.

Based on the information provided, we know that:

b=3l\n\n j=2b\n\n a=3l

Substitute the first equation into the second one:

j=2(3l)\n\nj=6l

 Since the total weight of the oranges is 1092 pounds, we can write the following expression and solve for "l". Then:

b+j+a+l= 1092\n\n3l+6l+3l+l=1092\n\n13l=1092\n\nl=84

Finally, substituting this value into the equation a=3l, we get :

a=3(84)\n\na=252

The original cost of an item is $64 but you have to pay $78.08. What is the markup of the item as a percent

Answers

Answer:

22%

Step-by-step explanation:

$78.08 - $64 = $14.08

$14.08 * 100% / $64 = 22%

Jacob went to Walmart to buy a water cooler for $4650. Walmart offered an off-season discount of 18%. How much did Jacob pay for the water cooler?

Answers

Answer:3813

Step-by-step explanation:

First, turn the discount percentage to a decimal

18%= .18

Multiply the decimal by the original price

.18 x 4650= 837

Subtract that amount from the original price to get the discount

4650-837= 3813

Find the critical numbers of the function f(x) = x6(x − 2)5.x = (smallest value)x = x = (largest value)(b) What does the Second Derivative Test tell you about the behavior of f at these critical numbers?At x = the function has ---Select--- [a local minimum, a local maximum, or neither a minimum nor a maximum].(c) What does the First Derivative Test tell you that the Second Derivative test does not? (Enter your answers from smallest to largest x value.)At x = the function has ---Select--- [a local minimum, a local maximum, or neither a minimum nor a maximum].At x = the function has ---Select--- [a local minimum, a local maximum, or neither a minimum nor a maximum].

Answers

Answer:

a) x=0, x=(12)/(11), x=2 \:b) The 2nd Derivative test shows us the change of sign and concavity at some point. c) At which point the concavity changes or not. This is only possible with the 2nd derivative test.

Step-by-step explanation:

a) To find the critical numbers, or critical points of:

f(x)=x^(6)(x-2)^(5)

1) The procedure is to calculate the 1st derivative of this function. Notice that in this case, we'll apply the Product Rule since there is a product of two functions.

f(x)=x^(6)(x-2)^(5)\Rightarrow f'(x)=(f*g)'(x)\n=f'g+fg'\Rightarrow (fg)'(x)=6x^(5)(x-2)^(5)+5x^(6)(x-2)^(4) \Rightarrow 6x^(5)(x-2)^(5)+5x^(6)(x-2)^(4)=0\nf'(x)=6x^(5)(x-2)^(5)+5x^(6)(x-2)^(4)

2) After that, set this an equation then find the values for x.

x^(5)(x-2)^(4)[6(x-2)+5x]=0\Rightarrow x^(5)(x-2)^(4)[11x-12]=0\Rightarrow x_(1)=0\n(x-2)^(4)=0\Rightarrow \sqrt[4]{(x-2)}=\sqrt[4]{0}\Rightarrow x-2=0\Rightarrow x_(2)=2\n(11x-12)=0\Rightarrow x_(3)=(12)/(11)

x=0\:(smallest\:value)\:x_(3)=(12)/(11)\:x=2 (largest value)

b) The Second Derivative Test helps us to check the sign of given critical numbers.

Rewriting f'(x) factorizing:

f'(x)=(11x-12)(x-2)^4x^(5)

Applying product Rule to find the 2nd Derivative, similarly to 1st derivative:

f''(x)>0 \Rightarrow Concavity\: Up\n\nf''(x)<0\Rightarrow Concavity\:down

f''(x)=11\left(x-2\right)^4x^5+4\left(x-2\right)^3x^5\left(11x-12\right)+5\left(x-2\right)^4x^4\left(11x-12\right)\nf''(x)=10\left(x-2\right)^3x^4\left(11x^2-24x+12\right)

1) Setting this to zero, as an equation:

10\left(x-2\right)^3x^4\left(11x^2-24x+12\right)=0\n\n

10\left(x-2\right)^3x^4\left(11x^2-24x+12\right)=0\n(x-2)^(3)=0 \Rightarrow x_1=2\nx^(4)=0 \therefore x_2=0\n11x^(2)-24x+12=0 \Rightarrow x_3=(12+2√(3))/(11)\:,x_4=(12-2√(3))/(11)\cong 0.78

2) Now, let's define which is the inflection point, the domain is as a polynomial function:

D=(-\infty<x<\infty)

Looking at the graph.

Plugging these inflection points in the original equationf(x)=x^(6)(x-2)^(5) to get y coordinate:

We have as Inflection Points and their respective y coordinates (Converting to approximate decimal numbers)

(1.09,-1.05) Inflection Point and Local Minimum

(2,0) Inflection Point and Saddle Point

(0,0) Inflection Point Local Maximum

(Check the graph)

c) At which point the concavity changes or not. This is only possible with the 2nd derivative test.

At

x=(12)/(11)\cong1.09 Local Minimum

At\:x=0,\:Local \:Maximum

At\:x=2, \:neither\:a\:minimum\:nor\:a\:maximum (Saddle Point)

Final answer:

To find the critical numbers of the function f(x) = x^6(x - 2)^5, we need to set the first derivative equal to zero and solve for x. The Second Derivative Test tells us the behavior of the function at the critical numbers, while the First Derivative Test tells us the behavior of the function based on the sign change of the derivative at the critical numbers.

Explanation:

The critical numbers of the function f(x) = x^6(x - 2)^5 can be found by taking the first and second derivatives of the function. The first derivative is f'(x) = 6x^5(x - 2)^5 + 5x^6(x - 2)^4 and the second derivative is f''(x) = 30x^4(x - 2)^5 + 20x^5(x - 2)^4.

To find the critical numbers, we need to set the first derivative equal to zero and solve for x: 6x^5(x - 2)^5 + 5x^6(x - 2)^4 = 0. We can solve this equation using factoring or by using the Zero Product Property. Once we find the values of x that make the first derivative zero, we can evaluate the second derivative at those values to determine the behavior of the function at those critical numbers.

The Second Derivative Test tells us that if the second derivative is positive at a critical number, then the function has a local minimum at that point. If the second derivative is negative at a critical number, then the function has a local maximum at that point. If the second derivative is zero, the test is inconclusive and we need to use additional information to determine the behavior of the function. The First Derivative Test tells us that if the derivative changes sign from negative to positive at a critical number, then the function has a local minimum at that point. If the derivative changes sign from positive to negative at a critical number, then the function has a local maximum at that point.

Learn more about Critical numbers and behavior of functions here:

brainly.com/question/34150405

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This is to confusing​

Answers

Answer:

40%  

Step-by-step explanation:

because there is 10 parts and if the 10 multipied by 10 (to find the percent) is 100 then the 4 is 40 (the unshaded part would be 60%)

Have a fantastic day!

Suppose that nine Massachusetts athletes are scheduled to appear at a charity benefit. The nine are randomly chosen from eight volunteers from the Boston Celtics and four volunteers from the New England Patriots. We are interested in the number of Patriots picked.a. In words, define the random variable X.
b. List the values that X may take on.
c. Give the distribution of X. X ~ _____(_____,_____)
d. Are you choosing the nine athletes with or without replacement?

Answers

Answer:

a) Random Variable - The value of this variable occur according to the frequency distribution

b) X may be volunteers from the Boston Celtics or the volunteer from New England Patriots

c) Distribution  1 to 13

d) Without replacement

Step-by-step explanation:

a) Random Variable - The value of this variable occur according to the frequency distribution

b) X may be volunteers from the Boston Celtics or the volunteer from New England Patriots

c) Distribution  1 to 13

d) Without replacement