CaSO3 (s) → → → → CaO (s) + SO2 (g)

What mass of CaSO3 must have been present initially to produce 14.5 L of SO2 gas at a temperature of 12.5°C and a pressure of 1.10 atm?

Answers

Answer 1
Answer: Using the ideal gas law, the number of moles SO2 is equal to PV/RT, or pressure times volume divided by the gas constant and temperature.  This is 14.5*1.1/((2.5+279.15)*.082), or 0.66 moles.  Since one mole CaSO3 is consumed for every mole SO2 generated, 0.66 moles of CaSO3 are consumed.  CaSO3 has a molar mass of 40+32+16*3=120 grams, so .66 moles of CaSO3 is equal to 80 grams, our final answer.

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Determine the mass 2 mol Li??

Answers

You can look on the periodic table for the number of automic mass units in each element. 

1 mole Li = 6.94 amu
6.94 • 2 = 13.9 amu

There are 13.9 amu in 2 moles of Li
Molar mass Li = 6.94 g/mol

1 mol --------- 6.94 g
2 mol --------- ?

Mass Li = 2 * 6.94 / 1

Mass Li = 13.88 g

hope this helps!

Explain what an air mass is?

Answers

Answer:

A body of air with horizontally uniform temperature, humidity, and pressure.

Explanation:

hope this helped :)

An

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Explanation:

At 25C and 795 torr, carbon dioxide has a solubility of 0.0356 M in water. What is the solubility at 25 C and 2070 torr? ____ MI know that at a given temperature, the solubility of a gas in a liquid is directly proportional to its pressure but how would that be set up in an equation..?

Answers

If you want to do real scientifically, the equation is 
p = kc. 
We evaluate k = p/c and plug in the first set of conditions. 
k = 795/0.0356 = 22,331 

Then p = kc and solve for c 
c = p/k = 2070/22,331 = 0.093

The mixing of solute in the solvent is called solubility. In a solution, there are two types of components, these components are solute and solvent.

  • Solute - a component that presents in less amount.
  • Solvent - a component that is present in a large amount.

According to the question, the torr is defined as the torr is a unit of pressure based on an absolute scale, defined as exactly 1/760 of a standard atmosphere.

The equation is  

p = kc  

hence,k = (795)/(0.0356) = 22,331

After solving the equation,

c = (p)/(k) \n\n= (2070)/(22,331)\n\n = 0.093\n

Hence, the solubility is 0.093.

For more information, refer to the link:-

brainly.com/question/11228968

Please help I cant figure this outformula is m(t) = Mo e^-rt
decay rate is r= ln2/h. Radium-221 has a half-life of 30 seconds. How long will it take for 90% of a sample to decay = o-rt

Answers

half life formula is t1/2 = ln2/lambda
Where lambda is the decay constant
Rewriting we get lambda = ln2 / t1/2
Subbing in 30 seconds as half life we get lambda= 0.0231049 approx.
I assume only mass of radium is what you want.
Hence he have the formula
m=mo e^-lambda x t
Where m is mass after time
Mo is initial mass.
For 90% to decay, m/mo x100% = 90%
Hence m/mo = 0.1 this is because 90% has decays so we are left with 10%
Rearranging, m=mo e^-lambda x t
We obtain
(m/mo)=e^-lambda x t
Subbing in above values we get,
0.1=e^-0.0231049 x t
Take ln on both sides to get
ln(0.1) = -0.0231049 x t
Hence,
t = ln(0.1) / (-0.0231049)
t= 99.65787 s
It takes about 100 seconds for 90% to decay

What is sublimation?

Answers

Sublimation is the transition from solid to gaseous.

hope this helps!

Solidsto gases without entering liquid state

The same amount of force is applied to bowling balls one of the balls Waze 8 pounds and the other weighs 13 pounds which bowl will have a greater acceleration

Answers

Answer:

The bowling ball with mass 8 pounds has greater acceleration.

Explanation:

The acceleration on the objects is equal to the quotient of the force applied on it and its mass. From Newton's second law of motion, we have;

F = ma

where F is the force on the object, m is its mass and a is its acceleration.

⇒ a = (F)/(m)

Let us assume that a force of 50 N was applied on the two bowling balls.

Thus;

mass of the first bowling ball = 8 pounds = 3.62874 kg

So that,

50 = 3.62874 x a

a = (50)/(3.62874)

  = 13.779

The acceleration of the first ball is 13.78 m/s^(2).

For the second ball of mass = 13 pounds = 5.8967 kg

So that,

50 = 5.8967 x a

a = (50)/(5.8967)

  = 8.4793

The acceleration of the second ball is 8.48 m/s^(2).

Therefore, the bowling ball with mass 8 pounds has greater acceleration.