MATHEMATICS HIGH SCHOOL

What is the solution to the equation 1.6m − 4.8 = −1.6m?m = 0.5

m = 0.7

m = 1.5

m = 3

Answers

Answer 1
Answer:

m = 1.5  is the solution to the equation.

What is the equation ?

An equation is a mathematical statement that is made up of two expressions connected by an equal sign. For example, 3x – 5 = 16 is an equation. Solving this equation, we get the value of the variable x as x = 7.

1.6m-4.8=-1.6m

Subtract 1.6m to both sides to get

-4.8=-3.2m

Divide both sides by -3.2to get

x = 1.5

m = 1.5  is the solution to the equation.

The solution of an equation is the set of all values that, when substituted for unknowns, make an equation true. For equations having one unknown, raised to a single power, two fundamental rules of algebra, including the additive property and the multiplicative property, are used to determine its solutions.

To learn more about An equation, refer

brainly.com/question/14107099

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Answer 2
Answer: see attached picture for answre

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Asking again for your help! I really don't understand!

Answers

Answer: y≤4x+3 and y≤-3x-5

Step-by-step explanation:

The slope of the first line is 4. The slope of (-1,-1) and (0,3) is 4. And the line passes through 3, so the y-intercept is 3.

The slope of the second line is 3. The slope of (-3,4) and (-1,-2) is -3. And the line passes through -5, so the y-intercept of the second line is -5

Christopher looked at his quiz scores shown below for the first andsecond semester of his Algebra class.
Semester 1: 78, 91, 88, 83, 94
Semester 2: 91, 96, 80, 77, 88, 85, 92
Which statement about Christopher’s performance is correct?
(1) The interquartile range for semester 1 is greater than the
interquartile range for semester 2.
(2) The median score for semester 1 is greater than the median
score for semester 2.
(3) The mean score for semester 2 is greater than the mean score
for semester 1.
(4) The third quartile for semester 2 is greater than the third
quartile for semester 1.

Answers


The answer is (2) because median means the number halfway into the set and the median for semester1 is 88 and the median for semester 2 is 77
What you can do is find out everything mentioned until you find one that matches.
(1) Semester 1's IQR is 8, and semester 2's IQR is 12, so that statement is incorrect
(2) Semester 1's median is 88, and semester 2's median is 88, so that statement is incorrect
(3) Semester 1's mean is 86.8, and semester 2's mean is 87, so that statement is correct.
Since that is correct, the answer is (3).

Solve the system of equations.6x – 3y = 3
–2x + 6y = 14
What number would you multiply the second equation by in order to eliminate the x-terms when adding to the first equation?

What number would you multiply the first equation by in order to eliminate the y-terms when adding to the second equation?

Answers

Keywords:

Systems of equations, variables, values, steps

For this case we have a system of two equations with two variables given by "x" and "y" respectively. We must solve the system by finding the values of the variables. For this, we follow the steps below:

6x - 3y = 3\ (1)\n-2x + 6y = 14\ (2)

Step 1:

We multiply the second equation by 3:

3 * (- 2x + 6y = 14)\n-6x + 18y = 42

Step 2:

We add both equations:

6x - 3y = 3\n-6x + 18y = 42\n-6x + 6x-3y + 18y = 42 + 3\n15y = 45

y = \frac {45} {15}\ny = 3

Step 3:

We substitutey=3 in the first equation:

6x - 3 (3) = 3\n6x-9 = 3\n6x = 3 + 9\n6x = 12\nx = \frac {12} {6}x = 2

Thus, the solution of the system is given by (x, y) = (2,3)

Answer:

The second equation must be multiplied by "3" to eliminate the terms of the "x" when added with the first equation

The first equation must be multiplied by "2" to eliminate the terms of the "y" when added with the second equation

The system solution is given by (x, y) = (2,3)

The sum of the squares of two positive integers is 394. If one integer is 2 less than the other and the larger integer is x. Find the integers.

Answers

larger is x
the other is called y
sum of squares is 394
x^2+y^2=394
one is 2 less that other
x>y so
y+2=x
subsitute y+2 for x

(y+2)^2+y^2=394
expand
y^2+4y+4+y^2=394
add like terms
2y^2+4y+4=394
divideboth sides by 2
y^2+2y+2=197
subtract 197 from both sides
y^2+2y-195=0
factor
(y+15)(y-13)=0
set each to zero
y+15=0
y=-15
impossible since it is stated that they are positive so get rid of this solution
y-13=0
y=13

find other
y+2=x
13+2=x
15=x


numbers are 13 and 15

List all the factors of 32.1, 2, 3, 4, 6, 8, 12, 16, 32
1, 2, 4, 8, 16, 32
1, 2, 6, 8, 16, 32
1, 2, 16, 32

Answers

Factors of 32 are 1, 2, 4, 8, 16 and 32.

Answer:

1 2 3 4 6 8 12 16 32

Step-by-step explanation:

a square rotated about its center by 360° maps on to itself at (1, 2, 3, or 4) different angles of rotation.

Answers

A square rotated around its center maps onto itself every 90° of rotation.
If you rotate it a full 360°, then that happens 4 times.

Answer: no rotation because only reflections through the center of a square can map it onto itself
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