John is playing a game of darts. The probability that he throws a dart into the center of the dart board (the Bull’s eye) is 1/10. The probability that he throws the dart into the 10-point ring is 3/10.What is the probability that he either hits a Bull’s eye or scores 10 points?
a. 1/3
b. 2/3
c. 3/5
d. 2/5
e. 1/4

Answers

Answer 1

Answer: The correct answer for the question that is being presented above is this one: "d. 2/5." John is playing a game of darts. The probability that he throws a dart into the center of the dart board (the Bull’s eye) is 1/10. The probability that he throws the dart into the 10-point ring is 3/10. The probability that he either hits a Bull's eye or scores 10 points is 2/5

Answer 2

Answer:

Answer: The correct option is (d). $(2)/(5).$

Step-by-step explanation: Given that John is playing a game of darts. The probability that he throws a dart into the centre of the dart board (the Bull’s eye) is $(1)/(10)$ and the probability that he throws the dart into the 10-point ring is $(3)/(10).$

We are to find the probability that he either hits a Bull’s eye or scores 10 points.

Let, 'A' and 'B' represents the events that John throws the dart into a Bull's eye and 10-point ring respectively.

Then, according to the given information, we have

$P(A)=(1)/(10),~~P(B)=(3)/(10),~~~P(A\cup B)=?$

Since John cannot throw the dart into the Bull's eye and 10 point ring together, both the events are independent of each other.

Therefore,

$P(A\cap B)=0$

From the theorems of probability, we have

$P(A\cup B)=P(A)+P(B)-P(A\cap B)=(1)/(10)+(3)/(10)-0=(4)/(10)=(2)/(5).$

Therefore, the probability that John either hits a Bull’s eye or scores 10 points is $(2)/(5).$

Thus, (d) is the correct option.

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Answers

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