A sample of gas has increased in temperature from 20° Celsius to 22° Celsius. Which of the following happens as the temperature of the gas goes up? The gas undergoes a phase change.
The velocity of the gas particles decreases.
The kinetic energy of the particles increases.
An exothermic reaction is more likely to occur.

Answers

Answer 1

Answer: The correct answer for this question is the statement 'the kinetic energy of the particles increases'. As the temperature of gas goes up, the kinetic energy of the particles increases because their velocities increase. This is because particles get excited and hit each other more - leading to increase in kinetic energy.

Answer 2

Answer:

Answer: The kinetic energy of the particles increases.

Explanation:

Average kinetic energy is defined as the average of the kinetic energies of all the particles present in a system. It is determined by the equation:

$K=(3RT)/(2)$

From above, it is visible that kinetic energy is directly related to the temperature of the system. So, if temperature is increased, average kinetic energy of the system also increases.

Also the velocity of the particles also increase as $K.E=(1)/(2)* mv^2$ .

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Pleaseeee helpp its a HW questionwill mark brainliest!!
Which of the following is not an acid? HCl H2SO4 HNO3 NaOH

What is the maximum mass of methane (CH4) that can be burned if only 1.0 g of oxygen is available and how do you figure it out?

Answers

Make the reaction: $CH_4+2O_2=CO_2+2H_2O$
For 2*32=64 grams of oxygen, you can burn 2*16=32 grams of methane (that is, half).
So, our answer is .5g.
Other intermediate calculations are mollecular masses:
$\mu_(CH_4)=A_C+4A_H=12+4=16 \n mu_(O_2)=2A_O=2*16=32$

Answer:

0.28 g of $CH_4$

Explanation:

You need a balanced equation first. $CH_4 + 2O_2$ ⇒ $CO_2 + 2H_2O$

You need to find the number of moles of oxygen, which is mass divided by the Mr: 1 ÷ 32 = 1/32

Then you find the moles of methane using the mole ration oxygen to methane 2:1. 1/32 ÷ 2 = 1/64

Then you find the mass by multiplying the Mr with the number of moles:

1/64 × 18 = 0.28125 g = 0.28 g

True or False: Mechanical weathering is the breakdown or rock by changing its chemical composition.

Answers

Answer:

False

Explanation:

Mechanical weathering breaks rocks into smaller pieces without changing their composition. Ice wedging and abrasion are two important processes of mechanical weathering. Chemical weathering breaks down rocks by forming new minerals that are stable at the Earth's surface.

Hope this helps☺️

Answer: False

Explanation:

That’s not using mechanics

What is the reason water is a liquid at normal earth conditions when it should be a gas

Answers

Actually, from the phase diagram, water should exist as liquid at normal conditions. At a pressure of 1.0 atm and 25 degrees Celsius, water exist as a liquid not a gas. Only when the temperature reaches 100 and more, it exist as gas.

A container is filled with 4.0 g H2 and 5.0 02. How much water is produced

Answers

4.0 g water. Water is the limiting reactant. Therefore there will be excess oxygen.

Is the compound CO ionic or covalent

Answers

If a compound is made of one metal and one non-metal it's bond will be ionic, whereas if a compound is made of two non-metals, it's bond will be covalent.

C - Non-Metal
O - Non-Metal

CO = Covalent.

What do colligative properties depend on?

Answers

Colligative properties depend on the amount of solute dissolved in a solvent. These set of properties do not depend on the type of species present. These properties include freezing point depression, boiling point elevation, osmotic pressure and vapor pressure lowering.

Answer:

Colligative properties depend on the quantity of solute and solvent and the identity of the solvent.

Explanation:

Colligative properties are defined as a set of intensive physical properties that result from the interactions between solute and solvent that form a solution. In this group of properties, we can find the freezing point depression, boiling point elevation, osmotic pressure, and vapor pressure lowering.

The mentioned properties dependon the amount of solute and solvent (concentration) and the nature of the solvent. this fact can be pictured by the freezing point depression formula:

$T_(f) _(solvent) -T_(f) _(solution) = K_(f) _(x) m$

where $T_(f) _(solvent)$ is the freezing point of the pure solvent, $T_(f) _(solution)$ is the freezing point of the solution, $K_(f)$ is the freezing point depression constant and m is the molality

In the equation, it can be seen that the change of temperature of the solution with respect to the pure solvent depends on the molality, which is the ratio of moles of solute and mass of solvent. Moreover, the change also depends on the freezing point depression constant that is a characteristic of the solvent.

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