Triangle PQR ~ triangle PꞌꞌQꞌꞌRꞌꞌ.Which two transformations were performed on triangle PQR to produce triangle PꞌꞌQꞌꞌRꞌꞌ?

Choose exactly two answers that are correct.


A.Triangle PQR was reflected across the y-axis to produce triangle PꞌQꞌRꞌ.

B.Triangle PQR was reflected across the x-axis to produce triangle PꞌQꞌRꞌ.

C.Triangle PꞌQꞌRꞌ was dilated by a scale factor of to produce triangle PꞌꞌQꞌꞌRꞌꞌ.

D.Triangle PꞌQꞌRꞌ was dilated by a scale factor of 2 to produce triangle PꞌꞌQꞌꞌRꞌꞌ.

Answers

Answer 1
Answer: The correct answer for the question that is being presented above is this one: D.Triangle PꞌQꞌRꞌ was dilated by a scale factor of 2 to produce triangle PꞌꞌQꞌꞌRꞌꞌ; C.Triangle PꞌQꞌRꞌ was dilated by a scale factor of to produce triangle PꞌꞌQꞌꞌRꞌꞌ.

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A gardener is going to plant 2 red rosebushes and 2 white rosebushes. If the gardener is to select each of the bushes at random, one at a time, and plant them in a row, what is the probability that the 2 rosebushes in the middle of the row will be the red rosebushes?

Answers

Answer:

16.66%

Step-by-step explanation:

The probability would be the multiplication of the different events.

First event, take out a white rose and plant it, the probability of that is 2/4 = 1/2

Second event, take out a red rose and plant it, the probability is 2/3.

Third event, take out another red rose and plant it, the probability is 1/2.

Now, the probability of everything is:

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that is to say, the probability of what the statement asks us to happen is 16.66%

Answer:

The answer to the question is

The probability that the 2 rosebushes in the middle of the row will be the red rosebushes = 1/6

Step-by-step explanation:

To solve the question we note that the required permutation is WRRW

Therefore the total number of ways to plant the four rose bushes given that two white rose bushes are in the middle is given by

4!/(2!2!) = 6 Therefore the probability that the 2 rosebushes in the middle of the row will be the red rosebushes = 1/6

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Step-by-step explanation: