Which is a prime number
111
121
131
141
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Related Questions
What is the radius of a circle circumscribed about a rectangle with a length of 8 centimeters and a width of 6 centimeters?
If a garage is 121 square feet will a 13 foot long car fit in it
It a grade 9 please help me do this I don’t really understand it at all
Given the following functions f(x) and g(x), solve (f + g)(3) and select the correct answer below:f(x) = 2x + 21g(x) = x − 24
B) x = 2 ± 2√5 / 3
C) x = -4 ± 4√5 / 6
D) x = -2 ± 2i√5 / 3
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A = 1/2 nsr
In this equation...
n = number of sides
s= side length
r = apothem (radius of the inscribed circle)
To find the area, we must first find the apothem. The apothem is the radius of the inscribed circle (draw a line from the center of the figure to the center of one of the sides). If you draw the apothem in to the figure, it creates a right triangle with a hypotenuse of 13.07 in and one side length of 5 in (1/2 of the figure's side length). Now we can find the apothem with the formula
a^2 + b^2 = c^2
a^2 = c^2 - b^2
a^2 = 13.07^2 - 5^2
a^2 = 170.8249 - 25
a^2 = 145.8249
a = 12.076
Now we have the value for the apothem and we can plug it into the area formula...
A = 1/2 nsr
(recall that n = number of sides; s= side length; r= apothem)
A = 1/2(8×10×12.076)
A = 40×12.076
A= 483.04 in^2
Rounded to the nearest tenth would be...
483.0 in^2
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D = 32g/8cm^3
D = 4g/cm^3
I am write the other answer is wrong. She got her numbers mixed. Mass is calculated using grams and volume is calculated using cm cubed.
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= 9/2 pounds
Amount of dough required by Rosa to make 1 pizza = 3/4 pounds
Then
The number of pizza that can be made with 9/2 pounds of dough = 1/(3/4) * (9/2)
= (4/3) * (9/2)
= 2 * 3
= 6
So Rosa can make 6 pizzas with the amount of dough she has.I hope the procedure is clear enough for you to understand.Glad to have helped you.
Answer:
6
Step-by-step explanation:
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27 divide by 2 will be 13.5.
so the answer is 13.5
Answer:Use A for third graders, B for fourth graders, and C for fifth graders.
33 = A + B + C
Since there are three variables, you need to come up with two other equations to substitute in.
C = 6 + A Since there are six more fifth graders than third graders.
A = B Since there is an equal amount of third and fourth graders.
Since A is in both equations, lets put each variable in terms of A.
B = A
C = 6 + A
So: A+A+A+6=33
A+A+A=27 Since you subtract six from both sides.
3A=27 Since you combine all three A's.
A=9 Since you divide both sides by three.
Therefore, since A is the number of third graders, there are 9 third graders.
Step-by-step explanation: