HELP ASAPFor the reaction 2H2(g) + S2(g)<---> 2H2S(g), determine the equilibrium constant at 700oC if at this temperature, the equilibrium concentrations are as follows:
[H2] = 0.208 M, [S2] = 1.13 × 10-6 M , [H2S] = 0.725 M
A) 1.08 × 107
B) 3.49
C)4.55 × 10-7
D)3.22 × 106
E)441

Answers

Answer 1

Answer: Equilibrium constant of a reaction is the ratio of concentrations of the products and the reactants when the reaction is in equilibrium. This value is independent of the concentrations since the conditions are at equilibrium instead it depends on ionic strength and temperature.

First, we write the equilibrium expression.

K = [H2S]^2 / [H2]^2 x [S2]
K = (0.725^2) / [(0.208^2) (1.13 x 10^-6)]
K = 10751545.56 or 1.08 x 10^7

Thus, the answer is A.

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Answers

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Explanation;

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Answers

Following the rule of thumb in dilution, the equation that can be used to solve this problem is:

C1V1 = C2V2

where:
C1 = concentration of solution 1
V1 = volume of solution 1
C2 = concentration of solution 2
V2 = volume of solution 2

(0.1)(V1) = (0.05)(750)
V1 = 375 mL

This shows that 375 mL of a 0.1 m NaHCO3 solution is needed in order to dilute it to a 0.05 m NaHCO3 solution of 750 mL.

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Answers

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Answers

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Answers

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