Which of these numbers 420, 654, 1246, 5721, 74082, 18465 are multiples of 2 and 3 but not 5?

Answers

Answer 1
Answer:

Answer:

The answers are 654 and 74082.


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What relation does not have an initial value of 50A y=50
B y=50+8x
C y =50x
D y=50-x

Answers

i guess itz B because with the rest, a number can be added to get exactly 50. Example C. y= 50x. x could be 1 which is still 50 and D. y=50-x and x could be 0 which is still 50 whiles A. y=50 remains 50

Final answer:

The relation that does not have an initial value of 50 is y = 50x.

Explanation:

In this question, we are given different equations and we need to identify the relation that does not have an initial value of 50. An initial value refers to the value of y when x is equal to 0. Let's analyze the given options:

A) y = 50: This equation has a constant value of 50, so the initial value is indeed 50.

B) y = 50 + 8x: This equation has an initial value of 50, as when x is 0, the value of y is 50.

C) y = 50x: This equation has an initial value of 0, as when x is 0, the value of y is also 0.

D) y = 50 - x: This equation has an initial value of 50, as when x is 0, the value of y is 50.

Therefore, the relation that does not have an initial value of 50 is option C) y = 50x.

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An unknown number b is 10 more than an unknown number k. The number b is also k less than 8. The equations to find k and b are shown below:b = k + 10
b = −k + 8

Which is a correct step to find k and b?
Write the points where the graphs of the equations intersect the x-axis. Write the points where the graphs of the equations intersect the y-axis. Add the equations to eliminate k. Multiply the equations to eliminate b.

Answers

Answer:

Add the equations to eliminate k.

Step-by-step explanation:

When we add the equations we get

2b =18

\boxed{b=9}

next we put b=9 into b=k+10 and solve for k:

9=k+10\n\n\boxed{k=-1}

this way we have found k and b; therefore, adding the equations to eliminate k is a correct step for finding k and b.

Let us now look at other choices we were given.

Write the points where the graphs of the equations intersect the x axis.

These points may be the solutions to each equation, but they are not the solutions to the system of these two equations.

Write the points where the graphs of the equations intersect the y axis.

Same thing goes here: these points may be the solutions to each equation, but they are not the solutions to the system of these two equations.

Multiply the equations to eliminate b.

Multiplying the equations doesn't eliminate b, but rather it complicates the matter by producing a quadratic equation—we don't want to go down that road!

The sum of two rational numbers is 3/2. if one of the numbers is-9/10, find the other number,.

Answers

There are one number is X, and another number is -9/10and sum is 2/3.
let other number be= x
-9/10+x = 3/2
x = 3/2+9/10
x = (15+9)/10
x = 24/10
x = 2.4

jacobs family bought 4 adult tickets and 2 student tickets to the school play for $64. tatiannas family bought 3 adult tickets and 3 student tickets for $60. how much did each ticket cost?

Answers

Answer:10

Step-by-step explanation:

Final answer:

The cost of each adult ticket is $28, but there is no solution for the cost of each student ticket in this case.

Explanation:

To solve this problem, we can set up a system of equations using the given information. Let's represent the cost of an adult ticket as 'a' and the cost of a student ticket as 's'. From the first equation, we know that 4a + 2s = 64. From the second equation, we know that 3a + 3s = 60. Now we can solve this system of equations.

Multiplying both sides of the second equation by 2 gives us 6a + 6s = 120. We can subtract the first equation from this equation to eliminate 's'.

6a + 6s - (4a + 2s) = 120 - 64

Expanding and simplifying the equation gives us 2a = 56. Dividing both sides by 2, we find that a = 28. Now we can substitute this value into either of the original equations to find 's'.

Using the first equation: 4(28) + 2s = 64

Simplifying the equation gives us 112 + 2s = 64

Subtracting 112 from both sides gives us 2s = -48. Dividing both sides by 2, we find that s = -24.

However, since we're talking about the cost of tickets, we can't have a negative value. Therefore, there is no solution for 's' in this case.

The cost of each adult ticket is $28, but there is no solution for the cost of each student ticket in this case.

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Is how tall is the oak tree a statistical question

Answers

Yes it is a statistical question

Answer:

Yes!

Step-by-step explanation:

Statistical questions can be verified by data. Since you can research/measure how tall oak trees are in general, it is a statistical question!

There are three colored cookie jars. One jar is blue, another green and the last one pink. The blue jar contains 10 chocolate chip and 7 sugar cookies. The green jar contains 8 chocolate chip, 14 sugar and 11 peanut butter cookies. The pink jar contains 6 chocolate chip, 5 sugar and 9 peanut butter cookies. One of the three cookie jars is chosen at random. The probabilities that the blue jar, green jar, or pink jar will be chosen are 1⁄2 , 1⁄4 , and 1⁄4 , respectively. A cookie is then chosen at random from the chosen jar. What is the probability that the pink jar was chosen, if it is known that the cookie was a sugar cookie?

Answers

The probability that the pink jar was chosen, when it is known that the cookie was a sugar cookie is 0.167..

What is Bayes' theorem?

Suppose that there are two events A and B. Then suppose the conditional probability are:

P(A|B) = probability of occurrence of A given B has already occurred.

P(B|A) = probability of occurrence of B given A has already occurred.

There are three colored cookie jars. One jar is blue, another green and the last one pink.

  • The blue jar contains 10 chocolate chip and 7 sugar cookies.
  • The green jar contains 8 chocolate chip, 14 sugar and 11 peanut butter cookies.
  • The pink jar contains 6 chocolate chip, 5 sugar and 9 peanut butter cookies.

Thus the probability of chossing sugar is,

P=(1)/(2)*(7)/(17)+(1)/(4)*(17)/(33)+(1)/(4)*(5)/(20)

One of the three cookie jars is chosen at random. The probabilities that the blue jar, green jar, or pink jar will be chosen are 1⁄2 , 1⁄4 , and 1⁄4 , respectively.

Thus the probability for pink jar was chosen, when it is known that the cookie was a sugar cookie is,

\rm P=(P(pink\cap sugar))/(P(sugar))\n\rm P=(P(sugar| pink)P(Pink))/(P(sugar))

Put the values,

P=((1)/(4)*(5)/(20))/((1)/(2)*(7)/(17)+(1)/(4)*(17)/(33)+(1)/(4)*(5)/(20))\nP=0.167

Thus, the probability that the pink jar was chosen, when it is known that the cookie was a sugar cookie is 0.167.

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Answer:

Pr(pink jar will be selected)=6/11