What is the volume of a block of ice measuring 3 meters long, 1.5 meters wide, and 2 meters high? A. 900 cu. m B. 12 cu. m C. 9 cu. m D. 6 cu. m

Answers

Answer 1

Answer: To find volume of a rectangular prism, you simply need to multiply length times width times height. We know from the text that our block of ice is 3 meters long, 1.5 meters wide, and 2 meters high. So all we need to do is multiply:

3 * 1.5 = 4.5

4.5 * 2 = 9

The block of ice has a volume of 9 cubic meters.
Choice C is your correct answer.
Hope that helped! =)

Answer 2

Answer: I'm 75% sure it's
c. 9 cu. m

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This box has the same length , width, and height as the 2 basketballs. Which expression gives the volume of the empty space encircling the basketballs inside the box?

Answers

Answer:

$4,608(6- \pi)\ cm^(3)$

Step-by-step explanation:

we know that

The volume of the empty space encircling the basketballs inside the box is equal to the volume of the box minus the volume of the two basketball inside the box

The volume of the box is equal to

$V=LWH$

in this problem we have

$L=2*24=48\ cm$

$W=24\ cm$

$H=24\ cm$

substitute

$V=48*24*24=27,648\ cm^(3)$

The volume of the two basketball inside the box is equal to

$V=2*(4)/(3) \pi r^(3)$

n this problem we have

$r=24/2=12\ cm$

substitute

$V=(8)/(3) \pi 12^(3)$

$V=4,608 \pi\ cm^(3)$

The expression is equal to

$(27,648-4,608 \pi)\ cm^(3)$

$4,608(6- \pi)\ cm^(3)$

Answer:

Upper Left Answer

Step-by-step explanation:

I did it on TTM

Verify cot x sec^4x=cotx +2tanx +tan^3x

Answers

Answer:

See explanation

Step-by-step explanation:

We want to verify that:

$\cot(x) \: { \sec}^(4) x = \cot(x) + 2 \tan(x) + { \tan}^(3) x$

Verifying from left, we have

$\cot(x) \: { \sec}^(4) x = \cot(x) \: ( 1 + { \tan}^(2) x )^(2)$

Expand the perfect square in the right:

$\cot(x) \: { \sec}^(4) x = \cot(x) \: ( 1 + { 2\tan}^(2) x + { \tan}^(4) x)$

We expand to get:

$\cot(x) \: { \sec}^(4) x = \cot(x) \: + \cot(x){ 2\tan}^(2) x +\cot(x) { \tan}^(4) x$

We simplify to get:

$\cot(x) \: { \sec}^(4) x = \cot(x) \: + 2 ( \cos(x) )/(\sin(x) ) ) * \frac{{ \sin}^(2) x}{{ \cos}^(2) x} +( \cos(x) )/(\sin(x) ) ) * \frac{{ \sin}^(4) x}{{ \cos}^(4) x}$

Cancel common factors:

$\cot(x) \: { \sec}^(4) x = \cot(x) \: + 2 \frac{{ \sin}x}{{ \cos}x} +\frac{{ \sin}^(3) x}{{ \cos}^(3) x}$

This finally gives:

$\cot(x) \: { \sec}^(4) x = \cot(x) + 2 \tan(x) + { \tan}^(3) x$

How to write 4/10 as a product of a whole number and a unit fraction

Answers

As a product of a whole number and a unit fraction 4/10 can be written as : 4 x 1/10

What is unit fraction?

A unit fraction is a rational number written as a fraction where the numerator is one and the denominator is a positive integer.
A unit fraction is therefore the reciprocal of a positive integer, 1/n.
Examples are 1/1, 1/2, 1/3, 1/4, 1/5 etc.

Given is the fraction -

4/10

We can write 4/10 as a product of a whole number and a unit fraction as given below -

4 x 1/10

Therefore, as a product of a whole number and a unit fraction 4/10 can be written as -

4 x 1/10

To solve more questions on fractions, visit the link below -

brainly.com/question/10354322

#SPJ3

It would be 4 times 1 over 10

Which of the following is a correct interpretation of the expression 2 - (-5)

Answers

Answer:

2+5

Step-by-step explanation:

When there are two negatives together they combine and turn to a addition sign.

Ex: -(-x)= +x

Hope this helped!

alisson separates her 23 stickers into 4 equal piles.how many stickers does she have left over? A27 B 19 C 5 D 3

Answers

We need to find the remainder- the sticker left over

Divide 23 stickers into 4 piles = 23/4= 5 stickers per pile and 3 stickers left over

D. She would have 3 stickers left over

What is the Gcf Of 35,21 and 14?

Answers

The greatest common factor of 35, 21, and 14 is 7. (7•5=35) (7•3=21) (7•2=14)

Its 7 because 7 goes into all those number.

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