How many years is a light year

Answers

Answer 1

Answer: A "light year" is not an amount of time.

It's an amount of distance ... the distance that light travels
through space in one year.

1 light year = 5,878,625,372,000 miles
(rounded to the nearest thousand miles)

1 light-year = 9,460,730,473,000 kilometers
(rounded to the nearest thousand kilometers)

Answer 2

Answer: 10,108 earth years equals 1 light year

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Is 30 minutes to nine the same as 30 minutes after 8 in life

Answers

Yes. In real life, those are both the same time.

If somebody said she'll meet you on the corner at 30 minutes to nine,
and you arrived there at 30 minutes after eight, then you both arrived
on the corner at exactly the same time. In real life.

yes it is the same because 30 minutes before 9 is 8:30 and 30 minutes after 8 is 8:30

Determine what forces are present in this situation: An elevator is rising at a constant speed; the elevator is the object in this situation.

Answers

Tension pointing up at the top Weight pointing down at the bottom If there is someone standing inside the elevator, there will be a normal reaction force pointing down at the bottom.

gravity and tension

i took the test

The amount of work done on an object is found by multiplying what and what

Answers

(the distance the object moves)
times
(the force in the direction of motion that made it move) .

How is a positive charge usually given to a neutral object?

Answers

the answer is 1) neutrons are added to the object.

The answer is #1 thank if it gelp

Four small spheres, each of which you can regard as a point of mass 0.200 kg, are arranged in a square 0.400 m on a side and connected by light rods. Find the moment of inertia of the system about an axis through the center of the square, perpendicular to its plane.

Answers

The moment of inertia of the system about an axis through the center of the square, perpendicular to its plane is $0.0636 \;\rm kg-m^(2)$ .

Given data:

The mass of each sphere is, $m = 0.200 \;\rm kg$ .

Length of side of square is, $L = 0.400 \;\rm m$ .

The expression for the moment of inertia of the system about an axis through the center of the square, perpendicular to its plane is,

$I = 4 mR^(2)$

Here,

R is the distance between center of the square and the sphere. And its value is,

$R =(1)/(2)\sqrt{L^(2)+L^(2)}\nR =(1)/(2)\sqrt{0.400^(2)+0.400^(2)}\nR = 0.282 \;\rm m$

Then, moment of inertia is,

$I = 4 mR^(2)\nI = 4 * 0.200 * 0.282^(2)\nI = 0.0636 \;\rm kg-m^(2)$

Thus, the moment of inertia of the system about an axis through the center of the square, perpendicular to its plane is $0.0636 \;\rm kg-m^(2)$ .

Learn more about moment of inertia here:

brainly.com/question/2176093?referrer=searchResults

The moment of inertia of the system about an axis through the center of the square, perpendicular to the plane is 0.064 kg.m²

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