How many moles of CaO are needed to react with an excess of water to form 370 grams of calcium hydroxide?

Answers

Answer 1

Answer:

The required moles of CaO are needed to react with an excess of water to form 370 grams of calcium hydroxide is 280g.

What is the relation between mass & moles?

Relation between the mass and moles of any substance will be represented as:

n = W/M, where

W = given mass
M = molar mass

Given chemical reaction is:

CaO + H₂O → Ca(OH)₂

Moles of Ca(OH)₂ = 370g / 74g/mol = 5mol

From the stoichiometry of the reaction, 5 moles of CaO is required to produce 5 moles of Ca(OH)₂.

Mass of CaO = (5mol)(56g/mol) = 280g.

Hence required mass of CaO is 280g.

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Answer 2

Answer: CaO + H20 --> Ca(OH)2

Calcium Hydroxide has a relative molecular mass of approximately 74 grams. Therefore, with 370 grams provided, we have 370g/74g, or 5 moles.

Therefore, due to molar ratios, 5 moles of CaO must have reacted with 5 moles of H2O to form 5 moles of Ca(OH)2.

The answer to your question is 5 moles of CaO or 280 g of CaO

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A car with constant speed travelso 150 km in 7200 seconds what is the speed of the car

Answers

7200sec÷60sec in a minute÷60minutes in an hour=2hours. 150km÷ 2 hours= 75 km/hour

Given its position on the periodic table, the element sulfur (S) is classified as aA. metal.
B. metalloid.
C. nonmetal.
D. transition metal.

Answers

periodic table sulphur is on the right hand side near the top so it is a non metal

A _________ shampoo is designed to re-balance the pH level of your hair by neutralizing any alkali and unwanted residues in the hair. Options: A) Clarifying B) Moisturizing C) Neutralizing D) Medicated

Answers

Answer:

C) Neutralizing

Explanation:

A neutralizing shampoo is specifically formulated to restore the pH balance of the hair by neutralizing any alkali or unwanted residues that may have accumulated. It is commonly used after chemical treatments such as perms or relaxers, which can alter the hair's pH level.

Chemical processes like perms and relaxers often involve the use of alkaline substances to break down and reshape the hair structure. After the process is complete, a neutralizing shampoo is used to stop the chemical reaction and bring the hair's pH back to its normal, balanced state. This helps to ensure the hair's health, smoothness, and manageability.

How many moles are there in 77.1 g of cl2?

Answers

According to the mole concept, there are 1.8074 moles in 77.1 g of chlorine.

What is a mole?

Mole is defined as the unit of amount of substance . It is the quantity measure of amount of substance of how many elementary particles are present in a given substance.

It is defined as exactly 6.022×10²³ elementary entities. The elementary entity can be a molecule, atom ion depending on the type of substance. Amount of elementary entities in a mole is called as Avogadro's number.

It is widely used in chemistry as a suitable way for expressing amounts of reactants and products.For the practical purposes, mass of one mole of compound in grams is approximately equal to mass of one molecule of compound measured in Daltons. Number of moles is calculated as, mass/molar mass

Substituting values in formula gives, number of moles=77.1/70.90=1.8074

Thus, there are 1.8074 moles in 77.1 g of Cl₂.

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There are 70.90g of Cl2 in 1 mol (because 35.45g Cl in one mol). So 77.1g/70.9g≈1.0874 mol.

What are the functions of protein in organisms?

Answers

Proteins make up many many important structures in our cells ( ex : receptors , Enzymes , integral proteins and so on )

Calculate ℰ° values for the galvanic cells described below. (a) cr3+(aq) + cl2(g) equilibrium reaction arrow cr2o72-(aq) + cl -(aq) v (b) io3-(aq) + fe2+(aq) equilibrium reaction arrow fe3+(aq) + i2(aq)

Answers

Answer:

$\boxed{\text{(a) 0.00 V; (b) 0.424 V}}$

Explanation:

We must look up the standard reduction potentials for the half-reactions.

ℰ°

Cr₂O₇²⁻ + 14H⁺ + 6e⁻ ⇌ 2Cr³⁺ + 7H₂O 1.36

Cl₂ + 2e⁻ ⇌ 2Cl⁻ 1.35827

2IO₃⁻ + 12H⁺ + 10e⁻ ⇌ I₂ + 6H₂O 1.195

Fe³⁺ + e⁻ ⇌ Fe²⁺ 0.771

(a) Cr³⁺/Cl₂

We reverse the sign of ℰ° for the oxidation half-reaction. Then we add the two half-reactions and their ℰ° values.

ℰ°/V

2Cr³⁺ + 7H₂O ⇌ Cr₂O₇²⁻ + 14H⁺ + 6e⁻ -1.36

Cl₂ + 2e⁻ ⇌ 2Cl⁻ 1.358 27

2Cr³⁺ + 3Cl₂ + 7H₂O ⇌ Cr₂O₇²⁻ + 6Cl⁻ + 14H⁺ 0.00

(b) Fe²⁺/IO₃⁻

ℰ°/V

Fe²⁺ ⇌ Fe³⁺ + e⁻ -0.771

2IO₃⁻ + 12H⁺ + 10e⁻ ⇌ I₂ + 6H₂O 1.195

10Fe²⁺ + 2IO₃⁻ + 12H⁺ ⇌ 10Fe³⁺ + I₂ + 6H₂O 0.424

The ℰ° values for the cells are $\boxed{\textbf{(a) 0.00 V; (b) 0.424 V}}$

Answer:

Answer:

\boxed{\text{(a) 0.00 V; (b) 0.424 V}}

Explanation:

We must look up the standard reduction potentials for the half-reactions.

ℰ°

Cr₂O₇²⁻ + 14H⁺ + 6e⁻ ⇌ 2Cr³⁺ + 7H₂O 1.36

Cl₂ + 2e⁻ ⇌ 2Cl⁻ 1.35827

2IO₃⁻ + 12H⁺ + 10e⁻ ⇌ I₂ + 6H₂O 1.195

Fe³⁺ + e⁻ ⇌ Fe²⁺ 0.771

(a) Cr³⁺/Cl₂

We reverse the sign of ℰ° for the oxidation half-reaction. Then we add the two half-reactions and their ℰ° values.

ℰ°/V

2Cr³⁺ + 7H₂O ⇌ Cr₂O₇²⁻ + 14H⁺ + 6e⁻ -1.36

Cl₂ + 2e⁻ ⇌ 2Cl⁻ 1.358 27

2Cr³⁺ + 3Cl₂ + 7H₂O ⇌ Cr₂O₇²⁻ + 6Cl⁻ + 14H⁺ 0.00

(b) Fe²⁺/IO₃⁻

ℰ°/V

Fe²⁺ ⇌ Fe³⁺ + e⁻ -0.771

2IO₃⁻ + 12H⁺ + 10e⁻ ⇌ I₂ + 6H₂O 1.195

10Fe²⁺ + 2IO₃⁻ + 12H⁺ ⇌ 10Fe³⁺ + I₂ + 6H₂O 0.424

The ℰ° values for the cells are \boxed{\textbf{(a) 0.00 V; (b) 0.424 V}}

Explanation:

its right trust

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