Payments of $27.50 are made monthly for a period of 36 months, and the amount financed is $835. What is the APR using the formula above?

Answers

Answer 1

Answer: The monthly payment for loans with no fees is expressed by a formula. The monthly payment equation is expressed as:

P = (P° x r x (1+r)^N) / ((1+r)^N -1)

where P is the monthly payment, P° is the loan amount, r is the APR, N is the number of monthly payments

We substitute the values and manipulate where one side contains the unknown term r.

27.50/835 = ( r x (1+r)^36) / ((1+r)^36 -1)

Using some functions in the calculator we obtain,

r = 9.51 x 10^-3

Thus, the problem above has an APR of 0.95% monthly.

Answer 2

Answer:

Answer:

Step-by-step explanation:

y = payments per year = 12

c = total interest paid = (36 * 27.50) - 835

m = amount financed = 835

n = total number of payments = 36

It is just a matter of finding the definitions and implementing them.

I get 12.0281484 for the exact result.

so 12 would most likely be the best answer for this.

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Given the point (5,6) and the slope of 5, find y when x=21

Answers

If slope is 5, 5.(x-5)=y-6 so 5x-y-19=0. When x=21, y=86.

$\sf{Slope =(y_2-y_1)/(x_2-x_1)}\n\n5 = (y - 6)/(21-5) \n\n5=(y-6)/(16)\n\n16(5) = y-6\n\n80 = y-6\n\ny = 80 + 6\n\n\boxed{\bf{y=86}}$

Write an equation in slope-intercept form of the line that passes through the given point and is parallel to the graph of the given equation.(-3,-3);y=-3x-2 y=−3x+2
Write an equation for the line in slope-intercept form.

Answers

Answer:

y = –3x – 6

Step-by-step explanation:

We'll begin by obtaining the slope of the equation y = –3x – 2.

This can be obtained by comparing

y = –3x – 2 with y = mx + c

Thus, the slope (m) of the equation

y = –3x – 2 is –3.

Next, we shall determine the slope of the equation parallel to line with equation y = –3x – 2.

This is illustrated below:

For parallel lines, the slope are related as follow:

m1 = m2

m1 = –3

m2 = m1 = –3.

Finally, we shall determine the equation as follow:

Coordinate = (–3, –3)

x1 coordinate = –3

y1 coordinate = –3

Slope (m) = –3

y –y1 = m(x – x1)

y – (–3) = –3 (x – (–3))

y + 3 = –3 (x + 3)

y + 3 = –3x – 3

Rearrange

y = –3x – 3 – 3

y = –3x – 6

Thus, the equation parallel to the line is y = –3x – 6

Which of the following options best describes the function graphed below?A graph shows a slanting straight line that starts at the origin and goes up.
Nonlinear increasing Nonlinear decreasing Linear increasing Linear decreasing I believe the answer is C. but I also think its D but I'm seriously stuck

Answers

Answer:

The graph of the function is:

Linear increasing.

Step-by-step explanation:

We are given a graph such that it is a slanting straight line.

This means that the relationship is linear.

Also the graph starts at origin and goes up.

This means that the graph of the function is continuously increasing.

Hence, the option that best describes the function graphed is:

Linear increasing.

It is going to be : Linear increasing (C)

POP QUIZFirst person to answer correctly gets brainliest

1. 1-1
2. (1248/56)^0
3. 2*0

Answers

This seems really easy, but

1) 0

2) 0

3) 0

Answer:

What's the question? All you posted was the potential answers.

Step-by-step explanation:

PLEASE HELP ASAP!!!!Hugo is writing a coordinate proof to show that the midpoints of a quadrilateral are the vertices of a parallelogram. He starts by assigning coordinates to the vertices of quadrilateral RSTV and labeling the midpoints of the sides of the quadrilateral as A, B, C, and D. Quadrilateral R S T V in a coordinate plane with vertex R at 0 comma 0, vertex S in the first quadrant at 2 a comma 2b, vertex T also in the first quadrant at 2 c comma 2 d, and vertex V on the positive side of the x-axis at 2 c comma 0. Point A is between points R and S, point B is between points S and T, point C is between points T and V, and point D is between points R and V. Enter the answers, in simplified form, in the boxes to complete the proof. The coordinates of point A are ( , ). The coordinates of point B are ( , ). The coordinates of point C are (2c, d) . The coordinates of point D are (c, 0) . The slope of both AB¯¯¯¯¯ and DC¯¯¯¯¯ is . The slope of both AD¯¯¯¯¯ and BC¯¯¯¯¯ is −bc−a . Because both pairs of opposite sides are parallel, quadrilateral ABCD is a parallelogram.