jason divide 3 pounds of dog food equally among six dogs. draw a diagram and explain how you can use it to find the amount of food for each dog receive

Answers

Answer 1

Answer: Each dog will get half a pound

Answer 2

Answer: A half of dog food. Hope I helped

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Neil and Manny have different amounts of money. If Manny gives Neil $6, then Neil and Manny will have the same amount of money. If Neil gives Manny $6, then Manny will have 3 times as much money as Neil. Together, do Neil and Manny have enough money to buy a $50 video game? Show your work or explain how you found your answer. Define any variables you use.

Answers

Neil would have $6, and Manny would have $12. $6+$6=$12 that manny has, so they would both have the same amount of money. But if Neil gives manny $6, then Manny would have $18, which is three times greater than $6 that Neil has. $12+$6 only equals $18, so they don't have enough money to buy the game.

The digit in the tenths place is how many times as much as the value of the digit in the hundredths

Answers

10 since ten times ten is a hundred

Final answer:

The value of the digit in the tenth place in a decimal number is ten times as much as the value of the digit in the hundredth place.

Explanation:

Each place value in a decimal is ten times the value of the place to its right. So, in a decimal number, the value of the digit in the tenth place is ten times as much as the value of the digit in the hundredth place. For example, in the decimal 0.58, the number 5 is in the tenth place and the number 8 is in the hundredth place. The 5 in the tenth place represents 5/10 or 0.5, which is ten times greater than the 8 in the hundredth place, which represents 8/100 or 0.08.

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Linda has a bag of marbles. She chooses a marble from the bag. writes down the color, and places the marbles back in the bag. She repeats this process 130 times. Linda calculates the relative frequency of each color marble.

Which statement about Linda's experiment is true?

A. The outcomes do not appear to be equally likely, so a uniform probability model is not a good model to represent probabilities in Linda's experiment.

B. The outcomes appear to be equally likely, so a uniform probability model IS a good model to represent probabilities in Linda's experiment.

C. The outcomes do not appear to be equally likely, so a uniform probability model is a good model to represent probabilities in Linda's experiment.

D. The outcomes appear to be equally likely, so a uniform probability model is not a good model to represent probabilities in Linda's experiment.

Answers

Answer:

Option: B is the correct answer.

B. The outcomes appear to be equally likely, so a uniform probability model IS a good model to represent probabilities in Linda's experiment.

Step-by-step explanation:

Equally likely outcomes--

The equally likely outcomes are the one that have equal chance or probability or likelihood of occurring.

Also, from the given relative frequency from the table we could observe that the outcomes have approximately the same relative frequency or the chances of their occurrence is almost similar.

Hence, the outcomes are equally likely.

Also a uniform probability model is one in which the outcomes have equal probability.

Hence, the statement that is true about Linda's experiment is:

Option: B

b
just took the test
hope this helps

What is the inverse of the function below? f(x)= x/4 -2

Answers

The inverse of function f(x) = x/4 - 2 is:

f^(-1)(x) = 4(x + 2).

Option C is the correct answer.

We have,

To find the inverse of the function f(x) = x/4 - 2, we can follow these steps:

Step 1: Replace f(x) with y: y = x/4 - 2.

Step 2: Swap the variables x and y: x = y/4 - 2.

Step 3: Solve the equation for y.

Let's start by isolating y:

x = y/4 - 2

x + 2 = y/4 (Adding 2 to both sides)

4(x + 2) = y (Multiplying both sides by 4)

So, the inversefunction is y = 4(x + 2).

However, it's common to write the inversefunction with the variable x instead of y.

Therefore,

The inverse of function f(x) = x/4 - 2 is:

f^(-1)(x) = 4(x + 2).

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$f(x)=(x)/(4)-2\to y=(x)/(4)-2\n\n\text{Interchange the y and the x}\n\nx=(y)/(4)-2\n\n\text{Solve for y}\n\n(y)/(4)-2=x\qquad|+2\n\n(y)/(4)=x+2\qquad|\cdot4\n\ny=4(x+2)$