What is the formula used to calculate heat of fusion?

Answers

Answer 1

Answer:

Answer:

The formula used to calculate heat of fusion:

q = m·ΔH f

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Proteins carry out cellular functions. where do they get instructions?

Answers

Photosynthesis and cellular respiration go hand and hand. Remember the two equations are just a reverse of the opposite equation.

Cellular Respiration-
C₆H₁₂O₆ + 6O₂ (Yeilds or Makes) 6CO₂ + 6H₂O + ATP (Or Energy)

Photosynthesis-
6CO₂ + 6H₂O + ATP (Or Sunlight) (Yeilds or Makes) C₆H₁₂O₆ + 6O₂

When a plant goes through photosynthesis it produces oxygen as a waste product, which you should know is what animals use to breathe, well when animals use oxygen in the process, they also make a waste product which happens to be Carbon Dioxide, which a plant uses to make glucose during photosynthesis, so if we didin't have one we wouldn't have the other.

ANSWER: Cells get their instruction from the formula.

What is a periodic element that is named after Einstein?

Answers

einsteinium, atomic number 99

Einsteinium is a synthetic element with symbol Es and atomic number 99. It is the seventh transuranic element, and an actinide. Einsteinium was discovered as a component of the debris of the first hydrogen bomb explosion in 1952, and named after Albert Einstein.

What is the gram-formula mass of Fe(NO3)3?(1) 146 g/mol (3) 214 g/mol

(2) 194 g/mol (4) 242 g/mol

Answers

The gram-formula mass of Fe(NO₃)₃ is 242 g/mol. Therefore, option D is correct.

Gram-formula mass is also known as the molar mass. It refers to the mass of one mole of a substance. It is expressed in units of grams per mole (g/mol) and is commonly used in chemistry to relate the amount of a substance to its mass.

The atomic mass of Iron= 56 amu.

The atomic mass of Nitrogen = 14 amu.

The atomic mass of Oxygen = 16 amu.

Gram-formula mass of Fe(NO₃)₃ = (Atomic mass of Fe) + 3 × {(Atomic mass of N × 1) + (Atomic mass of O × 3)}

= 56 + 3 × (14 × 1 + 16 ×3)

= 56 + 3 × (14 + 48)

= 56 + 3 × 62

= 56 + 186

= 242 g/mol

Therefore, the gram-formula mass of Fe(NO₃)₃ is 242 g/mol.

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Gram formula mass is the mass of 1 mol of substance.

the given compound is Fe(NO₃)₃

the molar mass of Fe(NO₃)₃ can be calculated taking the sum of the products of the individual elements by the number of atoms of the element making up the compound.

molar mass of Fe(NO₃)₃ = molar mass of Fe + 3 (molar mass of N + (3 x molar mass of O))

molar mass of Fe - 56, N - 14 and O - 16 g/mol

substituting the values in the above formula

molar mass of Fe(NO₃)₃ = 56 + 3 (14 + (3 x 16) )

molar mass of Fe(NO₃)₃ = 56 + 3 (14 + 48) = 56 + 3(62) = 56 + 186 = 242

therefore molar mass of Fe(NO₃)₃ is 4)242 g/mol

Using enthalpies of formation, calculate H.

Answers

ΔH° = -851.5 kJ/mol given that

$\begin{array}{cc}\textbf{Species}&{\bf {\Delta H_f\textdegree{}}}\n \text{Fe}_2\text{O}_3\;(s) & -824.2\;\text{kJ}\cdot\text{mol}^(-1)\n\text{Al}_2\text{O}_3\;(s) & -1675.7\;\text{kJ}\cdot\text{mol}^(-1)\end{array}$

(Source: Chemistry Libretexts.)

Explanation

Refer to a thermodynamic data table for the standard enthalpy of formation for each species.

Don't be alerted if the data for Al (s) and Fe (s) are missing. Why?

The standard enthalpy of formation of a substance measures the ΔH required to form each mole of it from the most stable allotrope of its elements under STP.
Both Al (s) and Fe (s) are already the most stable form of their element under STP (note that the state symbol matters.) There's no need to form them again.

As a result, $\Delta H_f\textdegree{} = 0$ for both Al (s) and Fe (s).

$\displaystyle \Delta H_{\text{rxn}}\textdegree{} = \text{Sum of }\Delta H\text{ for all }\textbf{Product} - \text{Sum of }\Delta H\text{ for all }\textbf{Reactant}}\n\phantom{\Delta H_{\text{rxn}}\textdegree{}} = (1* \Delta H_f\textdegree{}(\text{Al}_2\text{O}_3\;(s)) + 1* \Delta H_f\textdegree{}(\text{Al}\;(s)) \n \phantom{\Delta H_{\text{rxn}}\textdegree{}=}-(1* \Delta H_f\textdegree{}(\text{Fe}_2\text{O}_3\;(s)) + 1*\Delta H_f\textdegree{}(\text{Fe}\;(s))$

$\Delta H_{\text{rxn}}\textdegree{}} = (1 * (-1675.7)) - (1*(-824.2)) = -851.5\;\text{kJ}\cdot\text{mol}^(-1)$ .

The number "1" here emphasizes that in case there are more than one mole of any species in one mole of the reaction, it will be necessary to multiply the $\Delta H_f\textdegree{}$ of that species with its coefficient in the equation.

Vertical columns on the periodic table are called _______The elements in each column have_____
For #1 For #2
A.grouping A.Similar element names
B.families B.Similar properties
C.periods C.Similar symbols
D.lines D.Similar masses

Answers

The columns of the periodic table are called groups and they contain elements with similar properties based primarily on the number of electrons in the outer shell. Are you sure there isn't another option?

Vertical columns on the periodic table are called B. families.

The elements in each column, or family, have B. Similar properties.

How elements are placed in the periodic table

In the periodic table, elements are organized into rows and columns based on their atomic number and electron configuration. Each vertical column represents a family or group of elements that share similar chemical and physical properties.

The elements within a family tend to have similar valence electron configurations, leading to similar chemical behaviors and reactivity patterns.

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Which scientist performed the cathode ray experiment leading to the discovery of electrons?A.
Dalton
B.
Rutherford
C.
Democritus
D.
Bohr
E.
Thomson

Answers

Answer:

The scientist is E. Thomson.

Explanation:

In the late nineteenth century, physicist J.J. Thomson started trying different things with cathode beam tubes. Cathode beam cylinders are fixed glass tubes from which the greater part of the air has been emptied. A high voltage is applied crosswise over two terminals toward one side of the cylinder, which makes a light emission stream from the cathode (the contrarily charged anode) to the anode (the emphatically charged cathode).

The cylinders are called cathode beam tubes on the grounds that the molecule bars or “cathode beam” begins at the cathode. The beam can be distinguished by painting a material known as phosphors onto the most distant finish of the cylinder past the anode. The phosphors sparkles, or produces light, when affected by the cathode beam.

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