Please help!!!!!You just purchased a cellular phone and are trying to decide the best cellular phone company in which to give your business. When you contacted the Talks-A-Lot Company, they were offering a monthly plan of $40 for 600 minutes and $0.35 for each minute exceeding the 600 minutes. In the Sunday paper you see an ad for the Chat-Away Company, which offers a monthly plan of $50 for 600 minutes and $0.10 for each minute exceeding the 600 minutes. How many minutes would you have to talk over and above the 600 minutes for the cost to be the same with both companies and what would be the equal cost?

Answers

Answer 1

Answer: Well first of all that is a lot of money at least for me but like yeah And second of all I’m sorry because I’m not sure

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Please help me solve this question

Answers

The fraction is equal 0 if the numerator is equal 0.

$(12)/(x(x+8))=0\iff12=0\ FALSE$

Therefore your answer is 1. 0

Question ?????????????

Answers

17.45 +2.00= 19.45 cost without coupon
19.45-5.95=13.50 subtract for snacks
13.50/2= $6.75 divide by 2
$6.75 for each

Answer:

The answer is $4.75 for one admission cost

Step-by-step explanation:

it was 17.45 for 2 peoples admission

17.45-2.00= 15.45

15.45-5.95=9.50

9.50/2= $4.75

Give one example of when you would use the friendly numbers strategy to subtract.

Answers

I would say: when we want to substract numbers that are close to each other, but when the respective digits of the number from which the second number is subtracted are lower than in the other number.

For example, when we want to substract 18 from 21. Those two numbers are very close, but if you did it digit by digit, your would run into a problem.

So instead you can collect their differences to the friendly number 20: 21 is one number away from 20, and 18 two numbers, which makes a total of 3 numbers: and 3 is the solution!

For this case, we use the strategy of friendly numbers when subtraction is something complex to do mentally.

Let's suppose that we have the following subtraction:

$117 - 83$

Using friendly numbers we have:

$(100 + 17) - (80 + 3)$

Then, applying the associative property we have:

$(100 - 80) + (17 - 3)$

Doing the calculations we have:

$20 + 14 = 34$

Finally we have:

$117 - 83 = 34$

You are going to pull two cards from a standard deck of 52 cards (without replacement) and record whether you got a face card (jack, queen, king, or ace) or a number card (2-10). Which list of events correctly makes up the sample space?

Answers

Answer:

The list of event (pulling a face card,F or a number card, N) that correctly makes up the sample space when a card is drawn without replacement is;

NF and

Step-by-step explanation:

Here we have the definition of a sample space as one which has all possible outcomes

Therefore, the list of events that correctly makes up the sample space of events when you pull out two cards we have either a face card F or a number card N, and the sample space is;

NF and

Where the likelihood of each outcome changes as the number of face cards and number card changes as each card is drawn without replacement.

Answer:

just took the test, the correct answer is:

B) two number cards, two face cards, one number card and one face card

Which measure is not the area of a circle with radius 20 mm?

Answers

Given:
radius = 20 mm

Area of a circle = π r²
A = 3.14 * (20mm)²
A = 3.14 * 400mm²
A = 1,256 mm²

400mm² ; 628.57mm² ; and mm² ARE NOT THE AREA OF A CIRCLE

Answer:

thx for the answer

Step-by-step explanation:

What is the product? assume x>0 (√3x + √5) (√15x +2√30

Answers

The first step for solving this expression is to multiply the parenthesis.
$√(45) x^(2) + 2√(90) x + √(75)x + 2√(150)$
Simplify the first radical.
$3√(5) x^(2) + 2√(90) x + √(75)x + 2√(150)$
Simplify the second radical.
$3√(5) x^(2) + 2X3√(10) x + √(75)x + 2√(150)$
Simplify the third radical.
$3√(5) x^(2) + 2X3√(10) x + 5√(3)x + 2√(150)$
Simplify the final radical.
$3√(5) x^(2) + 2X3√(10) x + 5√(3)x + 10√(6)$
Lastly,, calculate the product of 2 × 3 $√(10)$ x to get your final answer.
$3√(5) x^(2) + 6√(10) x + 5√(3)x + 10√(6)$
Let me know if you have any further questions.
:)

Answer: B: 3x√5+6√10x+5√3x+10√6x

Step-by-step explanation:

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