Following are the program to convert height and weight values:
#include <iostream>//header file
using namespace std;
int main ()//main method
{
double height, weight,h,w; //defining a doubale variable
cout<<"Following are the converter of Weight and height: "<<endl;//print message
cout<<"Enter the height in inches: ";//print message
cin>>height;//input value
cout<<"Enter the weight in stones: ";//print message
cin>>weight;//input value
h=height* 2.54;//converting height value into centimetres and holding its value in h variable
w= weight* 6.364;//converting weight value into kilograms and holding its value in w variable
cout<<"The converted height is "<<h<<" cm."<<endl;//printing the converted value
cout<<"The converted weight is "<<w<<" kg."<<endl;//printing the converted value
return 0;
}
Program Explanation:
Output:
Please find the attached file.
Find out more information about the conversion here:
b. an eye for design and a knowledge of computer programming
c. a historical knowledge of architecture
d. architectural talent and an eye for design
Answer:
Cinematography
Explanation:
Cinematography is the blend of art and science and it deals with the recording of moving images on film or a digital storage device.
While making a movie some example of cinematography are the conclusions reached about lighting, camera filters, lenses etc.
Hi Lisa
Complex and simple
I hope that's help :)
Answer:
57,600
Explanation:
The Nyquist rate for an analog signal is twice its bandwidth. Therefore, for the three signals:
Signal 1: 2 * 1200 Hz = 2400 samples per second
Signal 2: 2 * 600 Hz = 1200 samples per second
Signal 3: 2 * 600 Hz = 1200 samples per second
Since all three signals are sampled at their respective Nyquist rates and encoded with 12-bit words, we can calculate the bit rate for each signal:
Bit rate for Signal 1 = 2400 samples/second * 12 bits/sample = 28,800 bits/second
Bit rate for Signal 2 = 1200 samples/second * 12 bits/sample = 14,400 bits/second
Bit rate for Signal 3 = 1200 samples/second * 12 bits/sample = 14,400 bits/second
To find the total bit rate for the multiplexed signal, simply add up the bit rates of the three signals:
Total bit rate = Bit rate for Signal 1 + Bit rate for Signal 2 + Bit rate for Signal 3
Total bit rate = 28,800 bits/second + 14,400 bits/second + 14,400 bits/second
Total bit rate = 57,600 bits/second
So, the bit rate for the time-division multiplexed signal is 57,600 bits per second.
To determine the bit rate for the multiplexed analog signals, the combined bandwidth is multiplied by the Nyquist rate (2 times the bandwidth), and then by the number of bits in the chosen encoding method (12 bits). This results in a bit rate of 57,600 bits per second.
In this scenario, one of the keys is to be aware that the Nyquist rate for sampling an analog signal is twice the maximum frequency of the signal. Therefore, to find the bit rate for the multiplexed signal, we need to combine the three signals of 1200 Hz, 600 Hz, and 600 Hz. These add up to 2400 Hz, which would be the total bandwidth of the system.
The Nyquist rate equals 2 times the total bandwidth, resulting in 4800 samples per second. Given that the analog signals are encoded with 12-bit words, we multiply the total number of samples per second by 12 bits, which results in a bit rate for the multiplexed signal of 57,600 bits per second.
This is a common calculation in digital communication systems such as cell phone conversations and computer data transmission, where multiple signals are converted into binary, multiplexed, and transmitted over a shared medium.
Learn more about Bit Rate Calculation here:
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