Simplify 4x+6(3x- 2)

Answers

Answer 1

Answer: The first thing we are going to do is distribute:
=4x+(6)(3x)+(6)(−2)
=4x+18x+−12
Second thing we are going to do is Combine Like Terms:
=4x+18x+−12
=(4x+18x)+(−12)
And your final answer is:
22x+−12
I hope this helps you! :)

Answer 2

Answer: Hi There i'm sorry i was looking at the wrong question,

Answer:22x−12

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Which expression is equivalent to 30(1/2x-2)+40(3/4y-4)?1.45xy-220
2.15x-30y-220
3.15x+30y-220
4.15x+30y-64

Answers

The expression is equivalent to the expression 30(1/2x - 2) + 40(3/4y - 4) will be 15x + 30y - 220. Then the correct option is C.

What is Algebra?

Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.

The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.

The expression is given below.

⇒ 30(1/2x - 2) + 40(3/4y - 4)

Simplify the expression, then we have

⇒ 30(1/2x - 2) + 40(3/4y - 4)

⇒ 15x - 60 + 30y - 160

⇒ 15x + 30y - 220

The expression is equivalent to the expression 30(1/2x - 2) + 40(3/4y - 4) will be 15x + 30y - 220. Then the correct option is C.

More about the Algebra link is given below.

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15x-60+30y-160
= 15x+30y-220

HELP PLS!! Which postulate proves that ABC and EDC are congruent?

Answers

The answer is c the

Final answer:

Depending on what is known about triangles ABC and EDC, either the Side-Side-Side (SSS), Side-Angle-Side (SAS), Angle-Side-Angle (ASA), Angle-Angle-Side (AAS), or Hypotenuse-Leg (HL) Postulate might be used to prove their congruence.

Explanation:

In mathematics, there are several postulates that can be used to prove that two triangles are congruent (i.e., identical in shape and size). In the case of triangles ABC and EDC, the appropriate postulate would depend on what information we have about these triangles. If we know that corresponding sides and angles are equal, we could apply the Side-Side-Side (SSS), Side-Angle-Side (SAS), Angle-Side-Angle (ASA), Angle-Angle-Side (AAS), or Hypotenuse-Leg (HL) Postulate. Without specific details about triangles ABC and EDC, I can't determine which postulate would prove their congruence.

Learn more about Congruence Postulates:

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ms. mckee wants to give each student in her class some candy. She wants everyone to recieve an equal number of jelly beans. She has less than 100 jellybeans. If she makes groups of 2,3, or 4 she will have 1 jelly bean left over. If she makes groups of 5, she will have no jellybeans left over, How many jellybeans could she have?

Answers

ok so since she makes groups of 5 an no left over, the number is divisble by 5
means that it ends with 5 or 0
possible ones are
5,10,15,20,25,30,35,40,45,50,55,60,65,70,75,80,85,90,95

groups of 2, will have 1 jelly bean left over
it is not divisble by 2, means it doesn't end with 0 (ending with 0 means it is divisible by 10, and 10 is divisible by 2)
5,15,25,35,45,55,65,75,85,95

groups of 3
not divisble by 3 (a hack to test, is that you add the digits and if the sum is divisble by 3, then the number is divisble), the list below is eliminated numbers divisble by 3

5,25,35,55,65,85,95
if makes group of 2 will have exactly 1 left over
5/3 has remainder of 2, eliminate
25 works so far (2*12=24,3*8=24,4*6=24)
35/4 has remainder of 3, eliminate
55/4 has remainder of 3, eliminate
65/3 has remainder of 2, eliminate
85 works
95/3 has remainder of 2,eliminate

the ones that work are 25 aand 85

she could have 25 or 85 jelly beans

so we are told that if the teacher makes the number of jelly beans she has (call that x) into groups of 2, 3, or 4 she'll have 1 jelly left over. to put that in math terms, x leaves a remainder of 1 when divided by 2, 3, or 4. This then implies that (x-1) is a multiple of 2, 3, or 4 (think about it!!!). all common multiples of 2, 3, or 4 must be a multiple of the LEAST common multiple of 2, 3 and 4. the least common multiple of those 3 numbers is 12. this means our common multiples can be:
12, 24, 36, 48, 60, 72, 84, 96 (we stop listing here because the number of jelly beans is less than 100)
this also means the possible number of jelly beans she can have is the numbers in the previous list plus 1 (remember it is x-1 NOT x that is the common multiple of 2, 3, 4):
13, 25, 37, 49, 61, 73, 85, 97
now we use our last clue which is if the teacher groups her jelly beans in groups of 5 there will be none left over. this is equivalent to saying that the number of jelly beans is a multiple of 5. we look through our 2nd list and find that only 25, and 85 is a multiple of 5. therefore the number of jelly beans the teacher can have is 25 and 85.
note that we took the problem in steps and used process of elimination to determine which of the natural numbers less than 100 can be the answer to the question. this is a very very good strategy in problem solving, but it can be challenging to know what order to take the "steps" but that can be mastered with patient practice.

let me know if you have any questions!!!!

What’s the cot(180°) + (cos(180°)/sin(180°))

Answers

Answer:

the answer is 'undefined'

Step-by-step explanation:

Cot is defines as (cos x)/(sin x)

So we can rewrite our expression as...

(cos 180°)/(sin 180°) + (cos 180°)/(sin 180°)

2(cos 180°)/(sin 180°)

Cos 180° = 1, sin 180° = 0 (you get these from the unit circle)

so we have

2(1/0) = 2/0, which is undefined, because we don't divide by zero

Mrs. Dimas has $130 to buy basketballs for Edison Middle School

Answers

Mrs. Dimas has $130 to but basketballs for Edison Middle School. How many can she buy at $15 each? interpret the reminder

you can't go over budget

cost=cost per backetball times number of basketbals
cost=15 times b
cost≤130
15b≤130
divide both sides by 15
b≤8 and 10/15
b≤8 and 2/3
round down because you can't buy 2/3 basketball

buy 8
the remainder means you have 2/3 of $15 left or $10

Answer:

Step-by-step explanation:

Do all shapes that have right angles have sides that are parallel.

Answers

Not all shapes, a right triangle does not have any parallel sides.

I hope this helped!

Not all of them, like what do you think about a circle?

helped? :)