Bonnie and some friends went to an amusement park. They bought rve of thesame lunches and 3 desserts and spent a total of $60.25 on the food. Eachdessert costs $5.25 less than one of the lunches.a. Detine a variable: Write an equation that can be used to find the cost oflunch.b. Solve the equation to find the cost of a lunch.en5.2

Answers

Answer 1

Answer: Let the variable be the cost of the lunch: x

so they bought 5 lunches: 5x
deserts are cheaper than lunches; they cost:
x-5.25
So together they paid:
5x+3*(x-5.25)=60.25

(we know how much they paid, so we can make an equation)

Let's remove the bracket:
5x+3*x-15.75=60.25

8x-15.75=60.25//we add 15.75 to both sides:
8x=76
and divide by 8:
x=9.5

So each lunch costs 9.5 dollars!

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Rational or irrational? -101

Answers

Answer:

irrational

Step-by-step explanation:

Answer:

rational

Step-by-step explanation:

The rational numbers includes all positive numbers, negative numbers and zero that can be written as a ratio (fraction) of one number over another.

20% of 50 is what number

PLEASE HELP

Answers

To find a percentage, multiply the number by the percentage as a decimal. 20% as a decimal is .2.
50 times .2 is 10
50×.2=x
50×.2 = 10
10=10

20% of 50 is 10!

To get 20% of a question you would have to be able to divide by 5 so 50/5=10. So the answer is 10. Hope this helped.

One circle has a diameter of 6 inches. A second, larger circle has a diameter that is four times the diameter of the first circle. What is the ratio of the area of the smaller circle to the larger circle?

Answers

The area of a circle:
$A=\pi r^2$
r - the radius, which is equal to half the diameter d

The first circle:
$d_1=6 \nr_1=(6)/(2) = 3 \nA_1=\pi * 3^2=9\pi$

The second circle:
the second circle has a diameter that is four times the diameter of the first circle.
$d_2=6 * 4=24 \nr_2=(24)/(2)=12 \nA_2=\pi * 12^2 = 144\pi$

The ratio of the area of the smaller cirlce to the area of the larger circle:
$(A_1)/(A_2)=(9 \pi)/(144 \pi)=(9)/(144)=(9 / 9)/(144 / 9)=(1)/(16)$

The ratio is 1:16.

How do I transform the equations 5x+4y=8 and -2x+5y=30 so that they are in the form that y=MX+b?

Answers

4y=5x+8 5y=-2x+30 the y always goes first. then the equal sign. next is x and finally just the digit which is also known as "b".

Make y the subject for both equations:

5x + 4y = 8
4y = -5x + 8
y = -(4/5)x + 8

-2x + 5y = 30
5y = 2x + 30
y = (2/5)x + 6

There you go, both equations are in y = mx + b for :)

What is 9/10 as a decimal and percent