MATHEMATICS HIGH SCHOOL

For the inverse variation equation xy = k, what is the constant of variation, k, when x = 7 and y = 3?A. 3/7

B. 7/3

C. 10

D. 21

Answers

Answer 1
Answer:

Answer:

  D.  21

Step-by-step explanation:

The equation tells you xy = k. Substituting the given values, you get ...

  7·3 = k

  21 = k
Answer 2
Answer:

Answer:

D) 21

Step-by-step explanation:

The given inverse variation equation is x.y = k, where k is the constant of proportionality.

Given: x = 7 and y = 3.

We need to find the constant variation, k.

To find the constant variation, k, plug in x = 7 and y = 3 in the given equation and simplify.

k = 7*3

k = 21.

Therefore, the constant of variation k = 21.

Answer is D) 21.

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Write an equivalent expression in factored for to x squared+3x+4x+12. and
x squared+7x+10

Answers

(x + 4)(x + 3)
x² + 3x + 4x + 12
x² + 7x + 12

x² + 7x + 10
x² + 2x + 5x + 10
(x + 5)(x + 2)

What is pie the equivalent to?

Answers

3.14159265358979323846
Or just 3.14

What is the y-value of the solution to the system of equations? 3x + 5y = 1 7x + 4y = −13

Answers

3x + 5y = 1 . . . . . . . . (1)
7x + 4y = -13 . . . . . . .(2)
(1) x 7: 21x + 35y = 7 . . (3)
(2) x 3: 21x + 12y = -39 .(4)
(3) - (4) = 23y = 46
y = 46/23 = 2

Answer:

2

Step-by-step explanation:



 

Shana sells
t-shirts.  It costs Shana $6.50 to buy
each t-shirt.  She also pays $150 each
month to rent equipment to add print to the t-shirts.


Shana sells each
t-shirt for $12.

 

Write an
inequality that can be used to determine the number of t-shirts (T) Shana must
sell each month in order to make a profit for the month.

Answers

12t - (6.50t + 150) > 0 => 5.50t > 150 => t > 150/5.50 => t > 27.27 => t>= 28 t- shirts;

LMN is a right triangle.

A= True
B= False

Answers

Answer:

true

Step-by-step explanation:

it has a right angle!

me = big brain

A polynomial function has a root of –6 with multiplicity 1, a root of –2 with multiplicity 3, a root of 0 with multiplicity 2, and a root of 4 with multiplicity 3. If the function has a positive leading coefficient and is of odd degree, which statement about the graph is true?A.) The graph of the function is positive on (–6, –2).
B.) The graph of the function is negative on (negative infinity symbol, 0).
C.) The graph of the function is positive on (–2, 4).
D.) The graph of the function is negative on (4, infinity symbol).

Answers

The correct answer for the question that is being presented above is this one: "C.) The graph of the function is positive on (–2, 4)." A polynomial function has a root of –6 with multiplicity 1, a root of –2 with multiplicity 3, a root of 0 with multiplicity 2, and a root of 4 with multiplicity 3. If the function has a positive leading coefficient and is of odd degree, then C.) The graph of the function is positive on (–2, 4).

Answer:

C -2,4

Step-by-step explanation:

i got it right on edge
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