Evaluate 5x - 1 when x = 8.
Answers
Answer:
39
Step-by-step explanation:
5x - 1 when x = 8
plug the variable in
5(8) - 1
40 -1
39
Answer:
39
Step-by-step explanation:
5(8) is 40, minus one is 39.
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subsitute and solve
y<1/5x
and
y>4x-3
4x-3<y<1/5x
try each one and solve
(5,1)
x=5,y=1
4(5)-3<1<1/5(5)
20-3<1 is already false so this is not a solution
(0,0)
subsitute
4(0)-3<0<1/5(0)
0-3<0<0
true
(-2,-3)
x=-2,y=-3
4(-2)-3<-3<1/5(-2)
-8-3<-3<-2/5
-11<-3<2/5
true
(2,5)
4(2)-3<5<1/5(2)
8-3<5 is already false so the answers are (0,0)and (-2,-3)
2.
remember that the y axis runs up and down and the x axis runs left to right
on the y axis, up is positive and down is negative
on the x axis, right is positive and left is negative
they are written in (x,y) form
notice that there are not points to the left side of the origin (0,0) or the center so therefor there are no points/solutions where x is negative (remember that x is the left number)
so we can cross out (-1,0)
remember that if the second number (x,y) y=second number is equal to zero, then he point is on the x axis
(2,0) is in the part of the screen shown so that is the answer
answers are
1. (0,0) and (-2,-3)
2. (2,0)
Answers
The remainder theorem says that dividing a polynomial by
leaves a remainder of
. Here,
, then
.
Final answer:
When you divide the given polynomial by x + 4, the remainder is 0. When you divide by x - 3, the remainder is 428.
Explanation:
To divide the polynomial p(x) = x^4 + 6x^3 + 7x^2 − 6x − 8 by x + 4 and x - 3 using the remainder theorem, first you substitute the roots of the divisor into the polynomial.
For x + 4, the root is -4. Substituting -4 into the polynomial yields p(-4) = (-4)^4 + 6*(-4)^3 + 7*(-4)^2 - 6*(-4) - 8 = 0. Thus, the remainder is 0 when dividing by x + 4.
For x - 3, the root is 3. Substituting 3 into the polynomial yields p(3) = (3)^4 + 6*(3)^3 + 7*(3)^2 - 6*(3) - 8 = 428 . Thus, the remainder is 428 when dividing by x - 3.
Learn more about Polynomial Division here:
#SPJ5
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I don't know if this is what you needed but i hope it helps :)
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