I need the answers for these questions

Answers

Answer 1

Answer: 1. 17/5
2. 25/4
3. 25/12
4. 27/10
5. 2 2/5
6. 8
7. 10 2/3
8. 1 8/12 or 1 2/3

Answer 2

Answer: 1. 17/5
2. 25/4
3. 25/12
4. 27/10
5. 2 2/5
6. 8
7. 10 2/3
8. 1 8/12

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What is the value of x?

5.6/8=x/24

Answers

$Cross \ Multiply: \n\ 8x = 134.4 \n\ x = 16.8$

The answer is 16.8. Do you need to know how?

Complete the table of values

Answers

Both problems give you a function in the second column and the x-values. To find out the values of a through f, you need to plug in those x-values into the function and simplify!

You need to know three exponent rules to simplify these expressions:
1) The negative exponent rule says that when abase has a negative exponent, flip the base onto the other side of thefraction to make it into a positive exponent. For example, $3^(-2) =(1)/(3^(2) )$ .
2) Raising a fraction to a power is the same as separately raising the numerator and denominator to that power. For example, $((3)/(4)) ^(3) = ( 3^(3) )/(4^(3) )$ .
3) The zero exponent rule says that any numberraised to zero is 1. For example, $3^(0) = 1$ .

Back to the Problem:
Problem 1
The x-values are in the left column. The title of the right column tells you that the function is $y = 4^(-x)$ . The x-values are:
1) x = 0
Plug this into $y = 4^(-x)$ to find letter a:
$y = 4^(-x)\ny = 4^(-0)\ny = 4^(0)\ny = 1$

2) x = 2
Plug this into $y = 4^(-x)$ to find letter b:
$y = 4^(-x)\n y = 4^(-2)\n y = (1)/(4^(2)) \n y= (1)/(16)$

3) x = 4
Plug this into $y = 4^(-x)$ to find letter c:
$y = 4^(-x)\n y = 4^(-4)\n y = (1)/(4^(4)) \n y= (1)/(256)$

Problem 2
The x-values are in the left column. The title of the right column tells you that the function is $y = ((2)/(3))^x$ . The x-values are:
1) x = 0
Plug this into $y = ((2)/(3))^x$ to find letter d:
$y = ((2)/(3))^x\ny = ((2)/(3))^0\ny = 1$

2) x = 2
Plug this into $y = ((2)/(3))^x$ to find letter e:
$y = ((2)/(3))^x\n y = ((2)/(3))^2\n y = (2^2)/(3^2)\ny = (4)/(9)$

3) x = 4
Plug this into $y = ((2)/(3))^x$ to find letter f:
$y = ((2)/(3))^x\n y = ((2)/(3))^4\n y = (2^4)/(3^4)\n y = (16)/(81)$

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Answers:
a = 1
b = $(1)/(16)$
c = $(1)/(256)$
d = 1
e = $(4)/(9)$
f = $(16)/(81)$