The graph of a linear equation contains the points (3,11) and (-2,1). Which point also lies on the graph

Answers

Answer 1
Answer: the slope is 2/1 so a point that lies on it is (4,13)
(3+1,11+2)
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What is the range and domain of the function : y= sqrt(x) -5 ... Can you please explain? Thanks btw the square root is only over the x

Answers

Domain of √(x) - 5 :  x ≥ 25 .

Range of   √x - 5 : y ≥ -5 .

Given,

f(x) = √x - 5

Here,

To find the domain,

√x - 5 ≥ 0

√x ≥ 5

Squaring both sides ,

x ≥ 25 .

Thus domain of √x - 5 is x ≥ 25 .

Range of √x - 5,

To define the range of the function the value of x can not be negative as it will make the function complex .

So,

Range will be ,

y ≥ -5 .

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okay so basically domain =input and range =output. you can never have a negative number underneath the square root sign because it will make the answer imaginary (i), unless you are on that concept. Therefore the range is any number greater than 0. -> all real numbers greater than or = 0

for the range if you input 0 as x you will get -5, so any number you input after 0 will be greater than -5. so range is all real numbers greater than or equal to -5. 

Which one of the following points lies on the
line y= 2x - 3

Answers

The required point for the given line is (0, -3). The correct option is (D).

What is a linear equation?

A linear equation in two variable has the general form as y = ax + by + c, where a, b and c are integers and a, b ≠ 0.

It can be represented as a straight line on a graph.

The equation of the given line is y = 2x - 3.

In order to find the point lying on it, consider each of the options one by one as follows,

(a) (2 , 3)

Substitute x = 2 and y = 3 in the given equation to obtain LHS and RHS as,

LHS = y

       = 7

RHS = 2x - 3

       = 2 × 2 - 3

       = 1

Since, LHS ≠ RHS, the given point is not the solution.

(b) (-2, -1)

Substitute x = 2 and y = 3 in the given equation to obtain LHS and RHS as,

LHS = y

       = 7

RHS = 2x - 3

       = 2 × -1 - 3

       = -6

Since, LHS ≠ RHS, the given point is not the solution.

(c) (4, 1)

Substitute x = 2 and y = 3 in the given equation to obtain LHS and RHS as,

LHS = y

       = 4

RHS = 2x - 3

       = 2 × 1 - 3

       = -1

Since, LHS ≠ RHS, the given point is not the solution.

(d) (0, -3)

Substitute x = 2 and y = 3 in the given equation to obtain LHS and RHS as,

LHS = y

       = -3

RHS = 2x - 3

       = 2 × 0 - 3

       = -3

Since, LHS = RHS, the given point is the solution.

Hence, the point (0, -3) is the solution of the given equation.

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An online furniture store sells chairs for $100each and tables for $500 each. The store must
sell a minimum of $8300 worth of chairs and
tables each day. Write an inequality that could
represent the possible values for the number of
tables sold, t, and the number of chairs sold, c,
that would satisfy the constraint.

Answers

Answer:

13 3/4

Step-by-step explanation:

Solve 2(x−5)^1/3=−16

Answers

Answer:

x = − 19

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YOU WENT TO THE GYM LAST WEEK AND SPENT THE FOLLOWING AMOUNT OF YOUR TIME ON THE RUNNING MACHINE. Day | Time Spent

Mon | 0.3
Tues | 15%
Wed | 1/6
Thurs | 0.2
Fri | 1/8

ON WHICH DAY DID YOU SPEND THE LEAST AMOUNT OF TIME ON THE RUNNING MACHINE?

Answers

Answer: On Friday, he spend the least amount of time on the running machine.

Step-by-step explanation:

Since we have given that

Monday   0.3 = 0.3* 100\%=30\%

Tuesday = 15%

Wednesday = (1)/(6)* 100\%=16.67\%

Thursday = 0.2* 100\%=20\%

Friday = (1)/(8)* 100\%=12.5\%

Hence, we can compare all the days, and we get that

On Friday, he spend the least amount of time on the running machine.

Thursday sonnnnnnnnnnnnn

The number p is 20 more than the number q . using algebra write the relationship between p and q .

Answers

From what we know, p is 20 more than q. So, we can assume p = 20 + q. Q can also be found by subtracting 20 from both sides. So, q = p - 20.

Hope this helped!