How many three-digit counting numbers are exactly divisible by 6 but not also exactly divisible by 9?

Answers

Answer 1

Answer: There are ⌊ 999 6 ⌋ − ⌊ 99 6 ⌋ numbers between 100 and 999 (i.e. three digit numbers) which are divisible by six.

Answer 2

Answer:

There are a total of 900 /999-99/ 3-digit numbers. And they are 900 consecutive numbers, 1/6th of these should be divisible by 6, 900/6=150 numbers. So the answer to your question is answer is... 150! :3

Hope I helped.

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Answers

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Yes they all 4 sides

the sum of two consecutive odd integers is 64 what is the smaller number plzzzz help also can you some me how to do it

Answers

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Answers

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"Suppose the leftmost digits of 2 numbers are 8 and 3. Can you tell which number is greater? Explain."

Answers

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There is 1/4 ounce of yeast in every 2 1/4 teaspoons of years. A recipe for bread calls for 2 teaspoons of yeast. How many ounces of yeast are needed for this recipe??

Answers

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John is thinking of a number. He gives the following 3 clues. ``My number has 125 as a factor. My number is a multiple of 30. My number is between 800 and 2000.'' What is John's number?Please answer correctly

Answers

Answer:

John's number is 1500

Step-by-step explanation:

* Lets explain how to solve the problem

- Factors of a number are the numbers you multiply to get the number

- Ex: Factors of 12 are 1 × 12 , 2 × 6 , 3 × 4

- The factors of a number smaller than or equal the number

- Multiple of a number is that number multiplied by an integer

- Ex: 2, 4, 6, 8, and 10 are multiples of 2

- The multiples of a number greater than or equal the number

* Lets solve the number

- John is thinking of a number

- He gives the following 3 clues

# The number has 125 as a factor

# The number is a multiple of 30

# The number is between 800 and 2000

∵ 125 is a factor of the number

- Assume that the number is 125 (its factors 1 , 5 , 25 , 125)

∵ The number is a multiple of 30

- Assume the number is 30 (the first multiple of 30)

- To solve the problem lets find the lowest common multiple of 125

and 30 by using prime numbers only

∵ The prime factors of 125 = 5 × 5 × 5

∵ The prime factors of 30 = 2 × 3 × 5

- L.C.M of the two numbers is the product of their prime factors

without reputation

∴ L.C.M = 5 × 5 × 5 × 2 × 3 = 750

∵ 750 has 125 as a factor

∵ 750 is a multiple of 30

- But 750 is not between 800 and 2000

∴ Find a multiple of 750 and between 800 and 2000

∵ 2 × 750 = 1500

* lets check the three clues

∵ 1500 has 125 as a factor

∵ 1500 is a multiple of 30

∵ 1500 is between 800 and 2000

∴ John's number is 1500

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