Two fire-lookout stations are 190 miles apart, with station A directly south of station B. Both stations spot a fire. The bearing of the fire from station A is Upper N 55 degrees Upper E and the bearing of the fire from station B is Upper S 60 degrees E. How far, to the nearest tenth of a mile, is the fire from each lookout station?
Answers
Step-by-step explanation:
Let's say the position of the fire is point C.
Bearings are measured from the north-south line. So ∠BAC = 55°, and ∠ABC = 60°.
Since angles of a triangle add up to 180°, ∠ACB = 65°.
Using law of sine:
190 / sin 65° = a / sin 60° = b / sin 55°
Solving:
a = 181.6
b = 171.7
Station A is 181.6 miles from the fire and station B is 171.7 miles from the fire.
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Convert the measurements below:a. 8 millimeters = ____meters
Find all possible values for A, B and C+ABABAB-----------CCCEach letter represents a single digit from 9 to 0
Find each percent increase. Round to the nearest percent
Answers
Answer: your answer would be [2, 4]
Step-by-step explanation:
tell me if im wrong please
Answers
Step-by-step explanation:
1) angle 2 and 4
2)angle 2 and 3
3)angle 1 and 4
Hope it helps
645 divided by 100
645 divided by 50
48.6 divided by 30
48.6 divided by x
Answers
Answer:
645/100 = 129/20 or 6.45
645/50 = 129/10 or 12.9
48.6/30 = 1.62
48 divided by x = 48.6/x
Step-by-step explanation:
645/100
Factor the number:
= 5*129/100
Factor the number:
= 5*129/5*20
Cancel the common factor:
= 129/20
645/50
Factor the number:
5*129/50
Factor the number:
5*129 / 5*10
Cancel the common factor:
= 129/10
48.6/30
Write the problem in long division format
Multiply the quotient digit (1) by the divisor (30)
Subtract 30 from 48
Add a decimal and bring down the next number
Divide 186 by 30 to get 6
Continue...A few steps later...
Subtract 60 from 60
Solution is 1.62
48.6/x
Re-write division as a fraction:
48.6/x
Answers
The probability that the sample mean would differ from the population mean by more than 1.8 millimeters is approximately 0.0668.
What is the standard deviation?
A standard deviation (σ) is a measure of the distribution of the data in reference to the mean.
The standard deviation of the population is millimeters. The standard error of the sample mean is then
millimeters.
The probability that the sample mean would differ from the population mean by more than 1.8 millimeters is the probability that it falls outside of the interval . We can use the standard normal distribution to approximate this probability.
First, we need to convert the difference between the sample mean and the population means to standard units.
The difference of 1.8 millimeters is :
standard units.
Then, we can use the standard normal distribution to find the probability that the sample mean falls outside of this interval.
This probability is equal to ,
where is the standard normal cumulative distribution function.
Therefore, the required probability is approximately 0.0668.
Learn more about the standard deviation here:
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Answers
Answer:
11.725%
Step-by-step explanation:
Given that :
True value = 0.904 seconds
Measured time = 1.010 seconds
Experimental error :
(|measured value - True value | / true value) * 100%
(|1.010 - 0.904| ÷ 0.904) * 100%
= 0.106 / 0.904 * 100%
= 0.1172566 * 100%
= 11.725%
Answer:
11.725%
Step-by-step explanation:
Answers
If you miss 8 out of 67 questions on the exam, your grade percentage would be approximately 88.06%.
Given that there are 67 questions on an exam. If you miss 8 of these questions then Subtract the number of questions missed (8) from the total number of questions (67):
Number of questions answered correctly = Total questions - Questions missed
= 67 - 8
= 59
Now, Grade percentage = (Number of questions answered correctly / Total questions) * 100
= (59 / 67) * 100
≈ 88.06% (rounded to two decimal places)
Therefore, if you miss 8 out of 67 questions on the exam, your grade percentage would be approximately 88.06%.
Learn more about percent here:
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