What is the probability that a randomly drawn hand of four cards contains all black cards or all face cards? The probability is 6 Round to four decimal places as needed.)
Answers
Answer: 0.05699
Step-by-step explanation:
The total number of cards in a deck = 52
The total number of black cards = 26
Then ,
The total number of face cards = 12
Then ,
The number of cards that are black and face cards = 6
Then ,
Then , the probability that a randomly drawn hand of four cards contains all black cards or all face cards is given by :-
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Which choice is equivalent to the expression below?√√-12 A. 2√3 OB. -12i OC. -2√3 D. 2√31 E. 12/
Answers
Answer:
0; 2; 6; 0 or -1
Step-by-step explanation:
If the question says "f(a)=" they are asking for the y value with the given x such as the two first ones.
If it's "f(x)=a than x=" they are asking you what x is when the (bolded) x is a given value.
Answers
y = 3x +2
interchange the variables:
x = 3y +2
switch the equation so the Y is on the left side:
3y +2 = x
subtract 2 from each side:
3y = x-2
divide each term by 3 to get y alone:
y = (x-2)/3
replace y with inverse of F(x) which is f^-1(x):
f^-1(x) = -(x-2)/3
Answers
Answer:
C(60) = 2.7*10⁻⁴
t = 1870.72 s
Step-by-step explanation:
Let x(t) be the amount of chlorine in the pool at time t. Then the concentration of chlorine is
C(t) = 3*10⁻⁴*x(t).
The input rate is 6*(0.001/100) = 6*10⁻⁵.
The output rate is 6*C(t) = 6*(3*10⁻⁴*x(t)) = 18*10⁻⁴*x(t)
The initial condition is x(0) = C(0)*10⁴/3 = (0.03/100)*10⁴/3 = 1.
The problem is to find C(60) in percents and to find t such that 3*10⁻⁴*x(t) = 0.002/100.
Remember, 1 h = 60 minutes. The initial value problem is
dx/dt= 6*10⁻⁵ - 18*10⁻⁴x = - 6* 10⁻⁴*(3x - 10⁻¹) x(0) = 1.
The equation is separable. It can be rewritten as dx/(3x - 10⁻¹) = -6*10⁻⁴dt.
The integration of both sides gives us
Ln |3x - 0.1| / 3 = -6*10⁻⁴*t + C or |3x - 0.1| = e∧(3C)*e∧(-18*10⁻⁴t).
Therefore, 3x - 0.1 = C₁*e∧(-18*10⁻⁴t).
Plug in the initial condition t = 0, x = 1 to obtain C₁ = 2.9.
Thus the solution to the IVP is
x(t) = (1/3)(2.9*e∧(-18*10⁻⁴t)+0.1)
then
C(t) = 3*10⁻⁴*(1/3)(2.9*e∧(-18*10⁻⁴t)+0.1) = 10⁻⁴*(2.9*e∧(-18*10⁻⁴t)+0.1)
If t = 60
We have
C(60) = 10⁻⁴*(2.9*e∧(-18*10⁻⁴*60)+0.1) = 2.7*10⁻⁴
Now, we obtain t such that 3*10⁻⁴*x(t) = 2*10⁻⁵
3*10⁻⁴*(1/3)(2.9*e∧(-18*10⁻⁴t)+0.1) = 2*10⁻⁵
t = 1870.72 s
Please help ☝
Answers
Answer:
-2x - 12
Step-by-step explanation:
-5(4x)+6(3x - 2)
-20x +18x - 12
-2x - 12
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WHO EVER ANSWERS FIRST I WILL GIVE BRAINLIEST PLSE HELP ME
Answers
Answer:
I personally think B but I do not know for sure.
Step-by-step explanation:
Answers
Answer:
13
Step-by-step explanation: