What does the ideal gas law allow a scientist to calculate that the other laws do not?a. Number of miles
b. Pressure
c. Energy
d. Volume

Answers

Answer 1

Answer: The ideal gas law.
PV=nRT
P=presure
V=volume
n=number of moles
R=Gas costant
T=temperature.

Answer: a. Number of moles.

Answer 2

Answer:

Answer:

A). number of moles

Explanation:

I took the test. It is correct.

Related Questions

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What is the acceleration of a 5.9 kilogram bowling ball if a force of 11 N is applied to it?
Green light has a lower frequency than blue light. Which color of light has a longer wavelength?
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The sun is the ultimate source for energy on the Earth.a. Trueb. False

A girl with a mass of 40 kg is swinging from a rope with a length of 2.5 m. What is the frequency of her swinging?

Answers

For a pendulum with a massless rope 'L' meters long, swinging through
a small arc, the period of the swing is

2 π √(L/g) seconds .

and it doesn't depend on the mass of the thing on the end of the rope ...
that could be a pebble or a bus.

For the girl on the 2.5-m rope,

Period = (2 π) √(2.5 / 9.8) = 3.17 seconds

Frequency = 1 / period = about 0.315 Hz .

If a girl with a mass of 40 kg is swinging from a rope with a length of 2.5 m , then the frequency of her swinging is 0.32 Hz

Further explanation

Simple Harmonic Motion is a motion where the magnitude of acceleration is directly proportional to the magnitude of the displacement but in the opposite direction.

The pulled and then released spring is one of the examples of Simple Harmonic Motion. We can use the following formula to find the period of this spring.

$\large { \boxed {T = 2 \pi\sqrt{(m)/(k)} } }$

T = Periode of Spring ( second )

m = Load Mass ( kg )

k = Spring Constant ( N / m )

The pendulum which moves back and forth is also an example of Simple Harmonic Motion. We can use the following formula to find the period of this pendulum.

$\large { \boxed {T = 2 \pi\sqrt{(L)/(g)} } }$

T = Periode of Pendulum ( second )

L = Length of Pendulum ( kg )

g = Gravitational Acceleration ( m/s² )

Let us now tackle the problem !

Given:

Mass of A Girl = m = 40 kg

Length of Rope = L = 2.5 m

Gravitational Acceleration = g = 10 m/s²

Unknown:

Frequency of Swinging = f = ?

Solution:

Recall the formula for calculating period as mentioned above.

$T = 2 \pi\sqrt{(L)/(g)}$

$T = 2 \pi\sqrt{(2.5)/(10)}$

$T = 2 \pi\sqrt{(1)/(4)}$

$T = 2 \pi (1)/(2)$

$T = \pi ~ seconds$

$T \approx 3.1 ~ seconds$

Finally, we can calculate the magnitude of frequency with the following formula.

$f = (1)/(T)$

$f = (1)/(\pi) ~ Hz$

$f \approx 0.32 ~ Hz$

Learn more

Model for Simple Harmonic Motion : brainly.com/question/9221526
Force of Simple Harmonic Motion : brainly.com/question/3323600
Example of Simple Harmonic Motion : brainly.com/question/11892568

Answer details

Grade: High School

Subject: Physics

Chapter: Simple Harmonic Motion

Keywords: Simple , Harmonic , Motion , Pendulum , Spring , Period , Frequency

What is convection current

Answers

A convection current is a flow of a fluid or air due to heating andcooling of the fluid or air. And for that matter the IE: Hot air rises. Cold air falls.

Answer:

A convection current is the flow of heat within a fluid.

sophia exerts a steady 40n horizontal force on a 8kg resting on a lab bench. the box slides against a horizontal friction of 24n. show that the box accelerates at 2m/s 2

Answers

Force = 40 - 24 = 16N

Force = mass / acceleration

Acceleration = Force / mass

Acceleration = 16 / 8

Acceleration = 2 m/s^2

Force = 40 - 24
= 16N.

Thus, Force = 16N.

By deducing Newton's second law of motion,

F = MA

16 = 8A

Thus, A = 16/8 = 2 m/s²

Thus, the object accelerates at 2m/s²

A charge of 90 C passes through a wire in 1 hour 15 minutes . what is the current in the wire

Answers

We calculate current from the formula:
$I= (q)/(t)$ , where q is a electric charge transferred over time t
Time should be converted to seconds:
1h 15 min= 75min= 4500s
I= $(90C)/(4500s)=0,02A$ Result is in unit-Ampere

Current = C / seconds.

1 hour = 3600 seconds
15 minutes = 900 seconds

1 hour 15 minutes = 4500 seconds

90 C / 4500 sec = 0.02 amperes = 20 milliamperes

Trumpeter A holds a B-flat note on the trumpet for a long time. Person C is running towards the trumpeter at a constant velocity. Person B is running away from the trumpeter at the same rate. Person D is standing still the whole time.Which person hears a frequency that is lower than the B-flat?
A) Person A
B) Person B
C) Person C
D) Person D

Answers

The person running towards the trumpet, Mr. C,
hears a higher frequency.

The person running away from the trumpet, Mrs. B,
hears a lower frequency.

The trumpeter, Mr. A, and the person who is just standing still
and listening, Miss D, both hears the beautiful perfect B-flat.

Answer:B

Explanation:Making fast and simple :)

The Hubble telescope’s orbit is 5.6 × 105 meters above Earth’s surface. The telescope has a mass of 1.1 × 104 kilograms. Earth exerts a gravitational force of 9.1 × 104 Newtons on the telescope. The magnitude of Earth’s gravitational field strength at this location is

Answers

The gravitational field is the Force divided by the mass

Call g the gravitational fiel, F the force exerted by the earth and m the mass of the telescope.

g = F / m

g=9.1x10^4 N / 1.1 x 10^4 kg = 8.27 N/kg

Note that the unit N/kg is equivalent to m/s^2

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