MATHEMATICS HIGH SCHOOL

What is the sum of the geometric sequence 3, 15, 75, … if there are 8 terms?39,062
58,593
195,312
292,968

Answers

Answer 1
Answer: If you would like to know the sum of the geometric sequence, you can calculate this using the following steps:

3, 15, 75, 75 * 5 = 375, 375 * 5 = 1875, 1875 * 5 = 9375, 9375 * 5 = 46875, 46875 * 5 = 234375

3 + 15 + 75 + 375 + 1875 + 9375 + 46875 + 234375 = 292,968

The correct result would be 292,968.
Answer 2
Answer:

Answer:

292,968

Step-by-step explanation:

Step 1: Use geometric sequence formula s_n=(a1r^n)/(1-r)

S_n & n= the sum of geometric sequence & terms in total (8)

r= common ratio (5)

a_1= first term in sequence (3)

s_8=(3(5)^(^8^))/( 1-5 )\ns_8=((3)390625)/(-4)\ns_8= (1171875)/( -4 )\ns_8=292968

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A segment has endpoints A (-1, 1) and B (8, 4) . If the segment is divided into four equal parts, the coordinates of the point closest to point A are _____. (7/2, 5/2) (5/4, 7/4) (23/4, 13/4)

Answers

Line is divided into 4 equal parts.

we have to find a point which is closest to point A.

So that means required point P(x,y) is at 1 unit away from A(-1,1) and 3 unit away from B(8,4)

Now we just need to use section formula to get the coordinate of required point using m1=1 and m2=3

\left ( (m_1x_2+m_2x_1)/(m_1+m_2) , (m_1y_2+m_2y_1)/(m_1+m_2) \right )

= \left ( (1*8+3*(-1))/(1+3) , (1*4+3*1)/(1+3) \right )

= \left ( (8-3)/(4) , (4+3)/(4) \right )

= \left ( (5)/(4) , (7)/(4) \right )

So the final answer is \left ( (5)/(4) , (7)/(4) \right ).

Answer:

ANSWER IS ( 5/4 , 7/4 ).

Step-by-step explanation:

Write 0.87 as a fraction in simplest form.

Answers

Write the decimal number as a fraction
(over 1)
0.87 = 0.87 / 1

Multiplying by 1 to eliminate 2 decimal places
we multiply top and bottom by 2 10's

Numerator (N)
N = 0.87 × 10 × 10 = 87
Denominator (D)
D = 1 × 10 × 10 = 100

N / D = 87 / 100

Simplifying our fraction

= 87/100

= 87/100

If 52 x equals 7800 y what does 1 x equal? What is the maths equation?

Answers

You gave the equation right at the beginning.  It's [ 52 x = 7,800 y ].

As you requested, I'll proceed now to solve your equation for 'x'.
I'll go slowly, and explain each step clearly.  Please try to follow
along with my procedure.

Step #1:
Write down the equation:     52 x = 7,800 y

Step #2:
Divide each side of the equation by 52 :    x = 7,800 y / 52

Step #3:
Perform the division indicated by the fraction, and underline the answer.

                  x = 150 y

52x=7800y\n x=150y

Cx/2=ag answer needed for x

Answers

Cx/2=ag 
First multiply each side by 2            Cx=2ag
Then divide by C on both sides       x=2ag/C

ANSWER: x=2ag/C
The answer to this answer is 56 

Suppose that an object whose is 10th weighs 50 N find the weight of an object whose is 6 kg

Answers

Weight is another term for the force from mass multiplied by acceleration due to gravity, the equation being expressed as f = ma, being force, mass, and acceleration respectively.

We already have 2 parts of the equation,50 = 10a 

Acceleration due to gravity on the planet is 5 m/s^2

Plug it into the equation f = ma

f=6kg x 5m/s^2

Weight or force from gravity is 60N.

On average Exante Express trains are 50km/hr faster than Paral passenger trains. A Paral passenger train requires 60% more time then Exante train to travel 1800 km from Matsay to Rawindi. Calculate average speed of each train. Calculate time it takes for each train for the journey.

Answers

V- average\ speed\ of\ Exante\ Express\ train\nt-travel\ time\ of\ Exante\ Express\ train \n \nV= (S)/(t) \ \ \ \ and\ \ \ V-50= (S)/(t+60\%t) = (S)/(1.6t)\ \ \ \ and\ \ \ S=1800\n \nV= (1800)/(t) \ \ \ and\ \ \ V-50=(1800)/(1.6t)\ \ \ \Rightarrow\ \ \ (1800)/(t)-50= (1125)/(t) \ /\cdot t\n \n1800-50 t=1125\ \ \ \Rightarrow\ \ \ 50t=1800-1125\ \ \ \Rightarrow\ \ \ 50t=675\ /:50\n \nt=13.5\ [h]=13\ [h]\ 30\ [min]\n\n1.6t=21.6\ [h]=21\ [h]+ 0.6\cdot60\ [min]=21\ [h]\ 36\ [min]

V= (1800)/(t) =(1800)/(13,5) =133 (1)/(3) \ [km/h]\approx133.3\ [km/h]\n\nV-50\approx83.3\ [km/h]

Ans.\n average\ speed\ of\ Exante\ Express\ train\ is\ 133.3\ km/h,\ntravel\ time\ of\ Exante\ Express\ train\ is\ 13\ h\ 30\ min;\naverage\ speed\ of\ Paral \ passenger \ train\ is\ 83.3\ km/h,\ntravel\ time\ of\ Paral \ passenger\ train\ is\ 21\ h\ 36\ min
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