Which is not an equation of the line that passes through the points (1, 1) and (5, 5)?

Answers

Answer 1
Answer:

Answer:

Any equation of the line that is different from y=x is the solution to the problem.

Step-by-step explanation:

step 1

Find the slope of the line that passes through the points (1, 1) and (5, 5)

m=(5-1)/(5-1)=1

step 2

Find the equation of the line into slope point form

y-y1=m(x-x1)

we have m=1

(x1,y1)=(1,1)

substitute

y-1=(1)(x-1)

y=x-1+1

y=x

therefore

Any equation of the line that is different from y=x is the solution to the problem.


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Angelo's pet rabbit weighs 1 pound less than twice the weight of Carmen's pet rabbit.Angelo's pet rabbit weighs 9 pounds. Write an equation that can be used to find (w) , the weight of Carmen's pet rabbit

How do I solve this?

Answers

area=LW
perimiter=2(L+W)

aera=36
P=25

36=LW
25=2(L+W)


25=2(L+W)
divide both sides by 2
12.5=L+W
minus W
12.5-W=L

sub for L
36=W(12.5-W)
36=12.5W-W^2
minus (12.5W-W^2) both sides
0=W^2-12.5W+36
use quadratic formula

if you have
ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^(2)-4ac} }{2a}

a=1
b=-12.5
c=36

W=\frac{-(-12.5)+/- \sqrt{(-12.5)^(2)-4(1)(36)} }{2(1)}
W=(12.5+/- √(156.25-144) )/(2)
W=(12.5+/- √(12.25) )/(2)
aprox
W=8 or 4.5

sub
12.5-W=L


12.5-8=L=4.5
12.5-4.5=L=8
either way

the dimentions are 4.5cm by 8 cm
\sf\nP=2L+2W=25 \sf\nA=LW=36\n\nFind\ the\ value\ of\ one\ of\ the\ variables\ in\ terms\ of\ the\ other. \sf\n36=LW\nW= (36)/(L)\n\nSubstitute.\nP=25\n=2L+2W\n=2L+2( (36)/(L) )\n=2L+ (72)/(L) \n\nMake\ them\ have\ a\ common\ denominator.\n2L+(72)/(L)\n= (2L)/(1) +(72)/(L)\n=(2L^2)/(L)+ (72)/(L) \n= (2L^2+72)/(L) \n\nMultiply\ L\ on\ the\ other\ side.\n25L=2L^2+72\n0=2L^2-25L+72\n\nUse\ the\ quadratic\ formula.\n L=\frac{-b+/- \sqrt{b^(2)-4ac} }{2a}\nax^2+bx+c
a=2\nb=-25\nc=72\n\n L=\frac{-(-25) +/- \sqrt{(-25)^(2)-4(2)(72)} }{2(2)} \n =(25+/- √(625-576) )/(4) \n =(25+/- √(49) )/(4)\n =(25(+/-)7)/(4) \n\n\sf\ We\ now\ have\ two\ options.\n(1) L=(25+7)/(4)= (32)/(4) =8\n(2)L=(25-7)/(4)= (18)/(4) =4.5\n\n\sf\ Either\ W\ is\ 8\ and\ L\ is\ 4.5\ or\ W\ is\ 4.5\ and\ L\ is\ 8.\ It\ doesn't\ matter.\n\n{\boxed{The\ dimensions\ are\ 8\ cm\ by\ 4.5\ cm.}

What are the prime factors of 72?

Answers

72= 2^3*3^2

Hope this helps~
The answer to this question should be 3x3x2x2x2 and when you did the times the answer will give you 72

A bag contains 2 white marbles and 7 purple marbles. Two marbles are drawn at random. One marble is drawn and not replaced, then a second marble is drawnA. What is the probability of selecting a purple marble and then a white marble?
B. What is the probability of selecting 2 white marbles?
C. Is there a greater chance of selecting 2 white marbles in a row or 2 purple marbles in a row? Show your work!

Hallie is trying to win the grand prize on a game show. Should she try her luck by spinning a wheel with 6 equal sections labeled from 1 to 6 and hope she gets a 5, or should she roll two number cubes and hope she gets the same number on both cubes. Show your work?

Answers

A. likely

B. unlikely

C. There is a greater chance in picking to purple marbles because there are less of the white and more purple.

Hallie should spin the wheel because u have a greater chance of landing on a 5 then rolling two number cubes and hoping both number cubes come to equal 5.

two white marbles: probability first is white is \frac{2}{9} probability second is white given that the first is white is \frac{1}{8} again probability both happen is \frac{2}{9}\times \frac{1}{8}

Hope this helps.

The average adult human has approximately 2.5 X 10' red blood cells and 7 X 10' whiteblood cells. About how many times as great is the number of rea blood cells than the
number of white blood cells? Write and solve an equation.

Answers

Answer:

\large \boxed{r =\frac{\text{RBC}}{\text{WBC}};\,\text{400 times}}

Step-by-step explanation:

I think your missing numbers are

RBC = 2.5 × 10¹³ and  

WBC = 7    × 10¹⁰

This is a ratio question.

You are asked to find the ratio of RBCs to WBCs.

Let r = the ratio.

Then the equation for the ratio is

\mathbf{r} =\mathbf{ \frac{\text{RBC}}{\text{WBC}}}

Insert the values and do the division.

\begin{array}{rcl}r& =& \frac{\text{RBC}}{\text{WBC}}\n\n& =&(2.5 * 10^(13))/(7 * 10^(10))\n\n& =&\mathbf{400}\n\end{array}\n\text{The number of RBCs is $\large \boxed{\textbf{400 times}}$ as great as that of the WBCs.}

The one cost DVD is 16.98, and the cost of another DVD is 9.29. Ed estimated the cost of the two DVD to be about 27. Is his estimate higher or lower than the actual cost? Explain

Answers

Answer:

Higher

Step-by-step explanation:

16.98 + 9.29 = 26.27 < 27.00

26.27 is rounded to 26.10 or 26.00 so Ed's estimate is higher

Hope this helps

Answer:

another DVD is $9.29. Ed estimated the cost of the two DVDs to be about $27. Is his estimate higher or lower than the actual cost? your answer is 21.

Step-by-step explanation:

brainliest please

there are 40 girls in a computer club. the ratio of girls to boys is 2 to 5. How many boys are in the club? complete this table to find out.

Answers

girsl=2 units
boys=5 units

girls=2units=40
divide 2
1 unit=20

boys=5 unit
5 times 20=100
boys=100
divide 40 by 20 to get 2. multiply 5 by 20 to get 100. 100 boys are in the club.