In a parking lot of 240 red and blue cars, the ratio of red cars to blue cars is 3:5. How many red cars are in the parking lot?

Answers

Answer 1
Answer: Given:
240 red and blue cars
3:5 ratio of red cars to blue cars

3 + 5 = 8

red cars: 3/8 * 240 = 90
blue cars: 5/8 * 240 = 150

ratio of red cars to blue cars: 90:150

simplify:
  90 ÷ 30 = 3
150 ÷ 30 = 5 

Thus: 90:150 = 3:5
Answer 2
Answer:

Answer:

90, because 3/8 of the cars are red

Step-by-step explanation:

This is the answer on ttm.


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What are the prime numbers of numbers 1-49?

Answers

Generally prime numbers are the odd numbers that aren't divisible by anything

The data set represents the number of rings each person in a room is wearing.0, 2, 4, 0, 2, 3, 2, 8, 6

What is the interquartile range of the data?

2
3
4
6

Answers

Answer:

the interquartile range of the data is:

                                   4

Step-by-step explanation:

We are given a data set as:

             0, 2, 4, 0, 2, 3, 2, 8, 6

On arranging the data in the ascending i.e. increasing order is given by:

    0     0     2     2    2    3      4      6     8

The minimum value of data set=0

Maximum value of data set is: 8

Range of data set= Maximum value-Minimum value

i.e. Range= 8-0

i.e. Range= 8

Also, Median of set is the central tendency of the data and is given by:

Median=  2

Lower set of data is:

                0    0     2    2

Hence, The median of lower set of data is the lower quartile or first quartile.

i.e. Q_1

Hence, Q_1=(0+2)/(2)\n\n\nQ_1=(2)/(2)\n\n\nQ_1=1

Hence, Lower quartile=1

Similarly upper set of data is:

                    3      4      6     8

Hence, The median of upper set of data is the upper quartile or third quartile.

i.e. Q_3

Hence, Q_3=(4+6)/(2)\n\n\nQ_3=(10)/(2)\n\n\nQ_3=5

Hence, Upper quartile=5

Hence, the interquartile range(IQR) is given by:

IQR=Upper quartile-Lower quartile

IQR=5-1

                                    IQR=4

If the data set represents the number of rings each person is wearing, being: 0,2,4,0,2,3,2,8,6, the interquartile range of the data is 2. Being, 4 as the Q1, 3 as the Q2 or median, and 6 as the Q3. Where the formula of getting the interquartile range is IQR= Q1-Q2.

The sum of two numbers is 100. The sum of 8 and the larger number is equal to 5 times the smaller number. What is the smaller number?

Answers

Answer:

The smaller number is 18

Step-by-step explanation:

Let the numbers be x and y where x is the smaller number; y\:>\:x.

The sum of the numbers is 100.

x+y=100...(1)

The sum of 8 and the larger number is equal to 5 times the smaller number.

y+8=5x

\Rightarrow y=5x-8...(2)

Put equation (2) into equation (1).

x+5x-8=100

x+5x=100+8

6x=108

x=18

Answer:

The smaller number is 18.

Step-by-step explanation:

We have given that

The sum of two numbers is 100. The sum of 8 and the larger number is equal to 5 times the smaller number.

Let x and y are two numbers.

Let y is the larger number.

x+y  = 100      eq(1)

y+8 = 5x         eq(2)

From eq(1), we have

y  = 100-x

Putting above eq(3) into eq(2), we have

100-x+8 = 5x

108 = 5x+x

108 = 6x

x  = 108/6

x = 18

Hence, the smaller number is 18.

permutations 2.4 statistics answers A clothing store has a certain shirt in 4 sizes: small, medium, large, and extra large. If it has 2 small, 3 medium, 6 large, and 2 extra large in stock, in how many orders can it sell all the shirts?

Answers

Answer: 360,360

Step-by-step explanation:

The number of permutations of n things of which a are identical, b are identical and so on... :-

(n!)/(a!\ b!....)

Given :  A clothing store has a certain shirt in 4 sizes: small, medium, large, and extra large.

If it has 2 small, 3 medium, 6 large, and 2 extra large in stock, then total shirts : 2+3+6+2=13

Then, the number of orders in which the store can sell all the t-shirts will be :_

(13!)/(2!3!6!2!)\n\n=(13*12*11*10*9*8*7*6!)/(2*3*2*6!*2)\n\n=360360

Hence, the number of orders in which the store can sell all the t-shirts  = 360,360

Karla has a younge sister and an older brother.Her younger sister is 3 years more than a half of karla's age . Her older brother is 7 year lees than twice karla's age. If the sum of all 3 of their is 38, how old is kayla.

Answers

She is twelve years old

F(x)=-(x+2)²+2f(0)=-(0+2)²+2 = ??
f(1)=-(1+2)²+2 = ??
f(2)=-(2+2)²+2 = ??
f(3)=-(3+2)²+2 = ??
f(4)=-(4+2)²+2 = ??
Helpp

Answers

f(0)=-(0+2)²+2 = -1*(2)² + 2 = -4 + 2 = -2        y =-2
element of the set x = 0 attribute to an element of a set of y ( calculated y = -2 )
f(1)=-(1+2)²+2 = -1*(3)² + 2 = -9 + 2 = -7        y = -7
element of the set x = 1 attribute to an element of a set of y ( calculated y = -7 )
f(2)=-(2+2)²+2 = -1*(4)² + 2 = -16 + 2 = -14    y = -14
element of the set x = 2 attribute to an element of a set of y ( calculated y = -14 )
f(3)=-(3+2)²+2 = -1*(5)² + 2 = -25 + 2 = -23    y = -23
element of the set x = 3 attribute to an element of a set of y ( calculated y = -23 )
f(4)=-(4+2)²+2 = -1*(6)² + 2 = -36 + 2 = -34    y = -34
element of the set x = 4 attribute to an element of a set of y ( calculated y = -34 )

Answer:

f(0)=-(0+2)²+2 = -1*(2)² + 2 = -4 + 2 = -2        y =-2

element of the set x = 0 attribute to an element of a set of y ( calculated y = -2 )

f(1)=-(1+2)²+2 = -1*(3)² + 2 = -9 + 2 = -7        y = -7

element of the set x = 1 attribute to an element of a set of y ( calculated y = -7 )

f(2)=-(2+2)²+2 = -1*(4)² + 2 = -16 + 2 = -14    y = -14

element of the set x = 2 attribute to an element of a set of y ( calculated y = -14 )

f(3)=-(3+2)²+2 = -1*(5)² + 2 = -25 + 2 = -23    y = -23

element of the set x = 3 attribute to an element of a set of y ( calculated y = -23 )

f(4)=-(4+2)²+2 = -1*(6)² + 2 = -36 + 2 = -34    y = -34

element of the set x = 4 attribute to an element of a set of y ( calculated y = -34 )